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Virginia SOL Mathematics Textbook

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Chapter 14 — Circles: Circumference and Area

Standard: 6.MG.1 — The student will identify the characteristics of circles and solve problems, including those in context, involving circumference and area.

By the end of this chapter you will be able to:

Lessons: 14.1 Parts of a Circle · 14.2 Discovering Pi · 14.3 Circumference · 14.4 Area of a Circle · 14.5 Circle Problems in Context

Throughout this chapter, use 3.143.14 for pi. Because 3.143.14 is an approximation, your answers are approximations too.


Lesson 14.1 — Parts of a Circle

What makes a circle a circle

Every figure you have studied so far — triangles, rectangles, parallelograms — is built from straight segments. A circle is built from a single rule about distance.

A circle is the set of all points in a plane that are the same distance from one fixed point. That fixed point is the center of the circle. The circle itself is only the curve; the center is not part of it.

That one rule is doing a lot of work. It is why a circle looks the same from every direction, and it is why the parts of a circle have such tidy relationships with each other.

Circle with center O labeled with radius, diameter, chord, circumference, and area

Radius and diameter

A radius is a segment from the center to any point on the circle. Because every point on the circle is the same distance from the center, every radius of a circle has the same length. When we say "the radius is 5 cm," we mean that common length. The plural of radius is radii.

A diameter is a segment that passes through the center and has both endpoints on the circle. A diameter is made of two radii lying end to end in a straight line, so:

d=2randr=d2d = 2r \qquad \text{and} \qquad r = \frac{d}{2}

Here dd stands for the length of the diameter and rr for the length of the radius. This is the first of the three relationships the standard asks you to investigate, and it is the one you will use most often, because problems hand you one and formulas ask for the other.

Two circles showing that the diameter is twice the radius

Chords

A chord is a segment whose endpoints are both on the circle. A chord does not have to pass through the center.

That definition should look familiar, because a diameter fits it. So:

Every diameter is a chord, but not every chord is a diameter. A diameter is exactly the chord that passes through the center, and it is the longest chord a circle has.

Three chords in one circle; the chord through the center is the diameter

Why is the diameter longest? Any chord that misses the center takes a shortcut across the circle. Only the chord that goes straight through the center uses the full width.

Circumference and area

Two measurements describe the size of a circle, and they answer different questions.

The circumference is the distance around the circle — its perimeter. It is a length, so it is measured in units such as centimeters, inches, feet, or meters. If you walked once around a circular track, the circumference is how far you walked.

The area is the amount of surface inside the circle. It is measured in square units such as square centimeters (cm2\text{cm}^2) or square feet (ft2\text{ft}^2). If you painted the inside of that track, the area is how much surface you covered.

Measurement Question it answers Units
Circumference How far around? units (cm, in, ft, m)
Area How much surface inside? square units (cm2\text{cm}^2, in2\text{in}^2, ft2\text{ft}^2, m2\text{m}^2)

Keeping these straight is mostly a matter of watching your units. If your answer to a "how much fencing" question comes out in square feet, something went wrong.

Worked examples

Example 1 — Naming a part from a description

A segment has one endpoint at the center of a circle and the other endpoint on the circle. Name this part.

One endpoint at the center, one on the circle, is the definition of a radius.

Answer: a radius

Example 2 — From radius to diameter

A circle has a radius of 99 cm. Find the diameter.

A diameter is two radii long, so double the radius.

d=2r=2×9=18d = 2r = 2 \times 9 = 18

Answer: 1818 cm

Example 3 — From diameter to radius

A circle has a diameter of 2626 in. Find the radius.

A radius is half a diameter, so divide by 2.

r=d2=262=13r = \frac{d}{2} = \frac{26}{2} = 13

Answer: 1313 in

Example 4 — Chord or diameter?

In a circle of radius 1010 cm, a chord measures 1414 cm. Could this chord be a diameter? Explain.

The diameter of this circle is d=2×10=20d = 2 \times 10 = 20 cm. A diameter must be 2020 cm long, and this chord is only 1414 cm.

Answer: No. It is a chord that does not pass through the center, since a diameter of this circle would measure 2020 cm.

Example 5 — Choosing circumference or area

A gardener wants to put a low fence around a round flower bed and then cover the soil inside with mulch. Which measurement does each job need?

Fencing goes around the edge; mulch covers the inside surface.

Answer: The fence needs the circumference (measured in feet). The mulch needs the area (measured in square feet).

Guided practice

  1. Name the part of a circle described: a segment from the center to a point on the circle.
  2. Name the part of a circle described: the longest chord of a circle.
  3. A circle has radius 99 m. Find the diameter.
  4. A circle has diameter 2626 ft. Find the radius.
  5. Is every diameter a chord? Is every chord a diameter? Explain each answer in one sentence.

Independent practice

  1. Using the figure at the start of this lesson, name a radius, a diameter, and a chord that is not a diameter.
  2. Find the diameter for each radius: a) 66 cm b) 4.54.5 in c) 12.512.5 m
  3. Find the radius for each diameter: a) 3030 ft b) 77 cm c) 1515 in
  4. One of these measurements is a length and one is a surface. Which is which, and what units does each use: circumference or area?
  5. A circle has radius 88 cm. Explain the difference between a chord that measures 88 cm and a radius that measures 88 cm.
  6. Application. A round pond measures 4040 ft straight across through the middle. Name that measurement, then give the distance from the center of the pond to its edge and name that measurement.
  7. Reasoning. Jonah says a circle can have a chord longer than its diameter. Explain why this is impossible.

Exit ticket 14.1

  1. A circle has radius 1111 cm. Find the diameter.
  2. A circle has diameter 99 in. Find the radius.
  3. Define chord in your own words.
  4. Explain why circumference is measured in units but area is measured in square units.

Lesson 14.2 — Discovering Pi

An investigation, not a formula

You are about to find one of the most useful numbers in mathematics, and you are going to find it by measuring. The question driving the whole lesson is simple:

How many diameters does it take to go once around a circle?

Take a can lid. Wrap a string once around the outside, cut the string to that exact length, then lay it flat next to the lid. Now measure across the lid with that string. You will fit three full diameters and have a little piece of string left over — noticeably less than another full diameter.

A string wrapped around a lid unrolled beside three diameters

Do it with a bigger lid and the answer is the same: three diameters and a little more. Do it with a bottle cap, a plate, a bicycle tire, a hula hoop. Always the same. That constancy is the discovery.

Gathering the data

Investigating carefully means measuring several circles and recording the ratio Cd\dfrac{C}{d} each time, where CC is the circumference and dd is the diameter. Here is a data set collected by one class using string and a centimeter ruler.

Object Circumference CC Diameter dd Cd\dfrac{C}{d} rounded to hundredths
Soup can lid 20.420.4 cm 6.56.5 cm 3.143.14
Tape roll 31.531.5 cm 10.010.0 cm 3.153.15
Jar lid 23.523.5 cm 7.57.5 cm 3.133.13
Dinner plate 81.681.6 cm 26.026.0 cm 3.143.14
Bucket rim 94.594.5 cm 30.030.0 cm 3.153.15

The objects range from a small jar lid to a bucket rim, and yet the ratios crowd into a narrow band around 3.143.14. Averaging the five ratios gives

3.14+3.15+3.13+3.14+3.155=15.715=3.142\frac{3.14 + 3.15 + 3.13 + 3.14 + 3.15}{5} = \frac{15.71}{5} = 3.142

Naming the number

That ratio has a name. Pi, written with the Greek letter π\pi, is the ratio of the circumference of any circle to its diameter:

π=Cd\pi = \frac{C}{d}

Pi is the same number for every circle, large or small. It is not a nice fraction and its decimal never ends or repeats; it begins 3.141593.14159\ldots. In this course we use the approximation

π3.14\pi \approx 3.14

Because that is an approximation, every circumference and area you compute is an approximation too. It is honest to say "about."

Why measured ratios vary. Your string slips, the ruler lands between marks, the lid is not perfectly round. Small measurement errors move the ratio a few hundredths in either direction. Getting 3.113.11 or 3.173.17 does not mean pi changed; it means measuring is imperfect. Averaging many circles pulls the noise out.

The data as a graph

Plotting diameter on the horizontal axis and circumference on the vertical axis makes the pattern visible in a second way.

Scatter plot of circumference against diameter along the line C = 3.14d

The points lie almost on a straight line through the origin. That is exactly what a constant ratio looks like on a graph: whatever the diameter, the circumference is about 3.143.14 times as large.

Worked examples

Example 1 — Computing the ratio from measurements

A lid has circumference 2222 cm and diameter 77 cm. Find Cd\dfrac{C}{d} rounded to the nearest hundredth.

Cd=227=3.1428\frac{C}{d} = \frac{22}{7} = 3.1428\ldots

Rounding to hundredths, the digit in the thousandths place is 22, so round down.

Answer: about 3.143.14

Example 2 — A ratio that runs high

A cup has circumference 14.214.2 cm and diameter 4.54.5 cm. Find the ratio and comment on it.

14.24.5=3.15553.16\frac{14.2}{4.5} = 3.1555\ldots \approx 3.16

This is close to 3.143.14 but a little high, which suggests the string was pulled slightly long or the diameter was measured a bit short.

Answer: about 3.163.16; measurement error, not a different pi

Example 3 — Estimating with "a little more than 3 diameters"

A circle has diameter 99 cm. Estimate its circumference without a formula.

Three diameters is 3×9=273 \times 9 = 27 cm, and the circumference is a little more than that.

Answer: a little more than 2727 cm — around 2828 cm

Example 4 — Averaging class data

Three groups report ratios of 3.123.12, 3.153.15, and 3.183.18. Find the average.

3.12+3.15+3.183=9.453=3.15\frac{3.12 + 3.15 + 3.18}{3} = \frac{9.45}{3} = 3.15

Answer: 3.153.15, close to 3.143.14

Example 5 — Judging a suspicious result

A group reports a ratio of 2.602.60 for a circle. Is measurement error a good explanation?

Every careful measurement lands near 3.143.14, and 2.602.60 is more than half a unit away. An error that large usually means the diameter was measured along a chord that missed the center, making it too long, or the string was not pulled all the way around.

Answer: No. This is too far off to be small measurement error; the group should re-measure, most likely the diameter.

Guided practice

For 1–3, find Cd\dfrac{C}{d} rounded to the nearest hundredth.

  1. Jar lid: C=15.7C = 15.7 cm, d=5.0d = 5.0 cm
  2. Cup rim: C=25.3C = 25.3 cm, d=8.0d = 8.0 cm
  3. Platter: C=75.2C = 75.2 cm, d=24.0d = 24.0 cm
  4. Find the average of your three ratios from items 1–3, rounded to the nearest hundredth.
  5. Explain why almost nobody measures a ratio of exactly 3.143.14.

Independent practice

  1. Find Cd\dfrac{C}{d} to the nearest hundredth for each object.

    Object CC dd
    a) Bottle cap 12.612.6 cm 4.04.0 cm
    b) Salad bowl 47.147.1 cm 15.015.0 cm
    c) Mug 29.829.8 cm 9.59.5 cm
    d) Wastebasket 69.169.1 cm 22.022.0 cm
  2. Average the four ratios from item 6, rounded to the nearest hundredth. What well-known number is it close to?

  3. Use the ratio 3.143.14 to predict the circumference of a circle whose diameter is 2020 cm.

  4. A circle has a diameter of nearly 8,0008{,}000 miles, about the size of Earth. What is Cd\dfrac{C}{d} for that circle? Explain how you know without measuring.

  5. Application. You mark one spot on a bicycle wheel, set the mark on the ground, and roll the wheel until the mark touches the ground again. Explain what distance the wheel traveled. If the wheel's diameter is 0.50.5 m, about how far did it roll?

  6. Application. A student measures a circular tray and reports C=50C = 50 cm with a ratio of 3.603.60. What diameter did the student record? What diameter should the tray actually have, to the nearest tenth? What probably went wrong?

  7. Reasoning. Why is it better to gather data from many different circles than to measure just one very carefully?

Exit ticket 14.2

  1. A circle has C=18.9C = 18.9 cm and d=6.0d = 6.0 cm. Find Cd\dfrac{C}{d} to the nearest hundredth.
  2. What number does Cd\dfrac{C}{d} get close to for every circle? What is it called?
  3. About how many diameters fit around the outside of a circle?
  4. Explain why measured ratios are not all the same.

Lesson 14.3 — Circumference

Building the formula

Lesson 14.2 ended with a fact about every circle:

π=Cd\pi = \frac{C}{d}

That is a statement about a ratio, but what problems actually ask for is the circumference. Multiply both sides by dd to move dd out of the denominator, and the ratio becomes a formula:

C=πdC = \pi d

The circumference of a circle equals pi times the diameter. Read it as a sentence: going once around is 3.143.14 times the distance straight across.

Many problems give you the radius instead. Since a diameter is two radii, replace dd with 2r2r:

C=πd=π(2r)=2πrC = \pi d = \pi (2r) = 2\pi r

C=πdorC=2πr\boxed{C = \pi d \qquad \text{or} \qquad C = 2\pi r}

These are not two different facts. They are the same formula written for the measurement you happen to have.

Circles labeled with the formulas C = pi times d and C = 2 times pi times r

Using the formulas

Three questions decide everything:

  1. What am I given — radius or diameter? Pick the matching formula.
  2. Did I substitute 3.143.14 for π\pi?
  3. Are my units plain units, not square units? Circumference is a distance.

Worked examples

Example 1 — Given the diameter

Find the circumference of a circle with diameter 1010 cm.

C=πdC = \pi d C3.14×10C \approx 3.14 \times 10 C31.4C \approx 31.4

Answer: about 31.431.4 cm

Example 2 — Given the radius

Find the circumference of a circle with radius 77 in.

C=2πrC = 2\pi r C2×3.14×7C \approx 2 \times 3.14 \times 7 C6.28×7C \approx 6.28 \times 7 C43.96C \approx 43.96

Answer: about 43.9643.96 in

Example 3 — Given the radius, using the other formula

Find the circumference of a circle with radius 66 m by first finding the diameter.

d=2r=2×6=12 md = 2r = 2 \times 6 = 12 \text{ m} C=πd3.14×12=37.68C = \pi d \approx 3.14 \times 12 = 37.68

Check with the other formula: C=2πr2×3.14×6=37.68C = 2\pi r \approx 2 \times 3.14 \times 6 = 37.68. Same answer, as it must be.

Answer: about 37.6837.68 m

Example 4 — A decimal radius

Find the circumference of a circle with radius 2.52.5 ft.

C=2πr2×3.14×2.5C = 2\pi r \approx 2 \times 3.14 \times 2.5 C6.28×2.5=15.7C \approx 6.28 \times 2.5 = 15.7

Answer: about 15.715.7 ft

Example 5 — Working backward from the circumference

A circle has circumference 62.862.8 cm. Find its diameter and its radius.

Start from C=πdC = \pi d and undo the multiplication by dividing.

62.83.14×d62.8 \approx 3.14 \times d d62.83.14=20d \approx \frac{62.8}{3.14} = 20 r=d2=202=10r = \frac{d}{2} = \frac{20}{2} = 10

Answer: diameter about 2020 cm; radius about 1010 cm

Guided practice

  1. Find the circumference of a circle with diameter 1010 cm.
  2. Find the circumference of a circle with diameter 2020 in.
  3. Find the circumference of a circle with radius 44 ft.
  4. Find the circumference of a circle with radius 99 m.
  5. A circle has radius 66 cm. Find its diameter, then its circumference.

Independent practice

  1. Find each circumference: a) d=5d = 5 cm b) d=30d = 30 mm c) r=11r = 11 in d) r=2.5r = 2.5 m
  2. Find the circumference of a circle with diameter 7.57.5 cm.
  3. A circle has circumference 94.294.2 ft. Find its diameter and its radius.
  4. Circle A has radius 33 cm and Circle B has radius 66 cm. Find both circumferences and describe what happened to the circumference when the radius doubled.
  5. Application. A bicycle wheel has a diameter of 2626 in. How far does the bike travel in one full turn of the wheel? How far in 1010 full turns?
  6. Application. A circular flower bed has radius 3.53.5 ft. Plastic edging is sold by the whole foot. How many feet should the gardener buy?
  7. Reasoning. Priya computes the circumference of a circle with radius 88 cm as 3.14×8=25.123.14 \times 8 = 25.12 cm. Find her error, give the correct circumference, and state the rule she should remember.

Exit ticket 14.3

  1. Find the circumference of a circle with diameter 1515 cm.
  2. Find the circumference of a circle with radius 55 in.
  3. A circle has circumference 31.431.4 m. Find its diameter.
  4. Explain why C=πdC = \pi d and C=2πrC = 2\pi r always give the same answer for the same circle.

Mid-chapter check (Lessons 14.1–14.3)

  1. A circle has radius 1414 cm. Find its diameter.
  2. A circle has diameter 1111 in. Find its radius.
  3. Name the longest chord of a circle.
  4. A lid has C=34.5C = 34.5 cm and d=11.0d = 11.0 cm. Find Cd\dfrac{C}{d} to the nearest hundredth.
  5. Find the circumference of a circle with diameter 2525 ft.
  6. Find the circumference of a circle with radius 1212 m.
  7. A circle has circumference 18.8418.84 cm. Find its radius.
  8. A round tabletop is 44 ft across. About how much ribbon is needed to trim its edge exactly once?

Lesson 14.4 — Area of a Circle

Where the formula comes from

Area asks how much surface is inside the circle. A circle has no straight sides to multiply, so we borrow a shape that does.

Imagine cutting a circle into many thin wedges, like slices of a pizza, and then arranging the wedges in a row with the points facing up and down alternately. With enough thin wedges, the row is nearly a parallelogram.

A circle cut into eight wedges rearranged into a parallelogram

Look at that near-parallelogram:

A parallelogram's area is base times height, so

A=(πr)(r)=πr2A = (\pi r)(r) = \pi r^2

A=πr2\boxed{A = \pi r^2}

The area of a circle equals pi times the radius squared. The exponent tells you why the answer comes out in square units: you are multiplying a length by a length.

Order of operations matters here

In A=πr2A = \pi r^2, the square applies only to rr. Square the radius first, then multiply by π\pi.

A=πr2meansA3.14×(r×r)A = \pi r^2 \quad \text{means} \quad A \approx 3.14 \times (r \times r)

For a radius of 55: square first, 52=255^2 = 25, then 3.14×25=78.53.14 \times 25 = 78.5. Multiplying first would give 3.14×5=15.73.14 \times 5 = 15.7 and then 15.72=246.4915.7^2 = 246.49, which is wrong.

When you are given the diameter

The area formula needs the radius, so if a problem gives the diameter, cut it in half before you square anything.

The most common area mistake is squaring the diameter. For a circle with d=10d = 10: the radius is 55, so A3.14×25=78.5A \approx 3.14 \times 25 = 78.5 square units. Squaring the 1010 instead gives 314314, which is four times too big.

A circle of radius 5 on a unit grid with whole and partial squares shaded

Counting squares on a grid is a good reality check. A circle of radius 55 covers a little more than 7878 whole and partial squares, which agrees with the 78.578.5 square units the formula gives.

Worked examples

Example 1 — Given the radius

Find the area of a circle with radius 55 cm.

A=πr2A = \pi r^2 A3.14×52A \approx 3.14 \times 5^2 A3.14×25A \approx 3.14 \times 25 A78.5A \approx 78.5

Answer: about 78.5 cm278.5\ \text{cm}^2

Example 2 — Given the diameter

Find the area of a circle with diameter 1212 in.

First halve the diameter.

r=122=6 inr = \frac{12}{2} = 6 \text{ in} A3.14×62=3.14×36=113.04A \approx 3.14 \times 6^2 = 3.14 \times 36 = 113.04

Answer: about 113.04 in2113.04\ \text{in}^2

Example 3 — A decimal radius

Find the area of a circle with radius 1.51.5 cm.

A3.14×1.52A \approx 3.14 \times 1.5^2 A3.14×2.25=7.065A \approx 3.14 \times 2.25 = 7.065

Answer: about 7.065 cm27.065\ \text{cm}^2

Example 4 — Circumference and area for the same circle

A circle has radius 1010 m. Find its circumference and its area, and compare the units.

C=2πr2×3.14×10=62.8 mC = 2\pi r \approx 2 \times 3.14 \times 10 = 62.8 \text{ m} A=πr23.14×102=3.14×100=314 m2A = \pi r^2 \approx 3.14 \times 10^2 = 3.14 \times 100 = 314\ \text{m}^2

The circumference is a distance in meters. The area is a surface in square meters. The numbers are different and so are the units.

Answer: C62.8C \approx 62.8 m; A314 m2A \approx 314\ \text{m}^2

Example 5 — Working backward from the area

A circle has area about 50.24 ft250.24\ \text{ft}^2. Find its radius.

Undo the multiplication by π\pi, then undo the squaring.

50.243.14×r250.24 \approx 3.14 \times r^2 r250.243.14=16r^2 \approx \frac{50.24}{3.14} = 16 r=4since 42=16r = 4 \quad \text{since } 4^2 = 16

Answer: about 44 ft

Guided practice

  1. Find the area of a circle with radius 55 cm.
  2. Find the area of a circle with radius 1010 in.
  3. Find the area of a circle with diameter 88 ft.
  4. Find the area of a circle with diameter 2020 m.
  5. Find the area of a circle with radius 1.51.5 cm.

Independent practice

  1. Find each area: a) r=3r = 3 cm b) r=7r = 7 in c) d=12d = 12 ft d) d=30d = 30 m
  2. Find the area of a circle with radius 2.52.5 in.
  3. A circle has radius 66 cm. Find its circumference and its area, and explain why the units are different.
  4. Circle A has radius 44 m and Circle B has radius 88 m. Find both areas, then describe what happened to the area when the radius doubled.
  5. Application. A pizza is 1616 in across. Find the area of its top surface.
  6. Application. A round tabletop has diameter 55 ft. Find its area to help decide how much glass is needed to cover it.
  7. Reasoning. Devon finds the area of a circle with diameter 1010 cm by computing 3.14×102=314 cm23.14 \times 10^2 = 314\ \text{cm}^2. Explain the mistake, give the correct area, and state how many times too large Devon's answer was.

Exit ticket 14.4

  1. Find the area of a circle with radius 99 cm.
  2. Find the area of a circle with diameter 44 in.
  3. A circle has area about 28.26 m228.26\ \text{m}^2. Find its radius.
  4. Explain why area is reported in square units but circumference is not.

Lesson 14.5 — Circle Problems in Context

Deciding which formula the situation needs

Real problems do not announce "use C=πdC = \pi d." They describe a job, and the job tells you which measurement to find.

The job involves You need Units
Fencing, edging, trim, ribbon, a border circumference ft, m, in, cm
One full turn of a wheel or roller circumference ft, m, in, cm
Mulch, paint, sod, glass, fabric, a pizza's surface area ft2\text{ft}^2, m2\text{m}^2, in2\text{in}^2, cm2\text{cm}^2
Ground a sprinkler waters, region a light covers area ft2\text{ft}^2, m2\text{m}^2

Then check what you were handed. Sprinklers and radar are described by reach, which is a radius. Pizzas, plates, wheels, and pipes are usually described by how far across, which is a diameter. Halve the diameter before using the area formula.

Overhead view of a lawn watered in a circle of radius 12 feet

A four-step habit

  1. Name the job. Around the edge, or the surface inside?
  2. Name what you have. Radius or diameter?
  3. Substitute and compute with π3.14\pi \approx 3.14, showing each step.
  4. Answer the question asked, with correct units — and round the way the situation requires.

Step 4 does more than it looks like. If you need 21.9821.98 ft of edging sold by the whole foot, you buy 2222 ft, because 2121 ft would leave a gap. Real contexts sometimes round up no matter what the decimal says.

Rolling wheels

A wheel that turns one full revolution without slipping travels exactly its circumference. That single sentence turns every wheel question into a circumference question:

distance in n turns=n×C\text{distance in } n \text{ turns} = n \times C

Half circles

A semicircle is half of a circle. Its area is half the circle's area. Be careful with its perimeter: the curved part is half the circumference, but the straight part across the top is the diameter, and it counts.

A window made of a 4 ft by 3 ft rectangle topped by a semicircle

Worked examples

Example 1 — A sprinkler

A sprinkler sprays water in a circle reaching 1212 ft in every direction. How much lawn does it water?

The job is the surface covered, so use area. The reach is a radius.

A=πr23.14×122A = \pi r^2 \approx 3.14 \times 12^2 A3.14×144=452.16A \approx 3.14 \times 144 = 452.16

Answer: about 452.16 ft2452.16\ \text{ft}^2

Example 2 — Fencing a pen

A circular dog pen is 4040 ft across. How much fencing goes around it?

Around the edge means circumference, and "across" means diameter.

C=πd3.14×40=125.6C = \pi d \approx 3.14 \times 40 = 125.6

Answer: about 125.6125.6 ft of fencing

Example 3 — Cost of edging

A circular garden has radius 1010 ft. Edging costs $3 per foot. Find the cost.

C=2πr2×3.14×10=62.8 ftC = 2\pi r \approx 2 \times 3.14 \times 10 = 62.8 \text{ ft} cost62.8×3=188.40\text{cost} \approx 62.8 \times 3 = 188.40

Answer: about $188.40

Example 4 — A rolling wheel

A wheel has diameter 22 ft. How far does a cart travel in 100100 turns of the wheel?

C=πd3.14×2=6.28 ft per turnC = \pi d \approx 3.14 \times 2 = 6.28 \text{ ft per turn} distance100×6.28=628\text{distance} \approx 100 \times 6.28 = 628

Answer: about 628628 ft

Example 5 — A semicircular window

The window in the figure above has a semicircle of radius 22 ft on top of a rectangle 44 ft wide and 33 ft tall. Find the total glass area.

Rectangle first:

Arect=4×3=12 ft2A_{\text{rect}} = 4 \times 3 = 12\ \text{ft}^2

Then half of a full circle of radius 22:

Acircle3.14×22=3.14×4=12.56 ft2A_{\text{circle}} \approx 3.14 \times 2^2 = 3.14 \times 4 = 12.56\ \text{ft}^2 Asemi12.562=6.28 ft2A_{\text{semi}} \approx \frac{12.56}{2} = 6.28\ \text{ft}^2 Atotal12+6.28=18.28A_{\text{total}} \approx 12 + 6.28 = 18.28

Answer: about 18.28 ft218.28\ \text{ft}^2

Guided practice

  1. A sprinkler waters a circle of radius 1212 ft. Find the area watered.
  2. A circular pen is 4040 ft across. Find the length of fence needed to enclose it.
  3. A round rug has radius 44 ft. Find its area.
  4. A trampoline is 1414 ft across. Find the length of padding needed to wrap its edge once.
  5. A manhole cover has diameter 2424 in. Find the area of its top surface.

Independent practice

  1. A circular swimming pool is 1818 ft across. Find the distance around the pool and the area of its surface.
  2. A wagon wheel has diameter 22 ft. How far does the wagon roll in 100100 turns of the wheel?
  3. A circular garden has radius 1010 ft. Fencing costs $4 per foot. Find the total cost.
  4. A round pizza pan has radius 77 in. Find the area of the pan's surface.
  5. Application. Two 1010-inch pizzas cost the same as one 1616-inch pizza. (Pizza sizes give the diameter.) Which choice gives more pizza, and by how much?
  6. Application. A round table is 55 ft across. A tablecloth must hang 66 in past the edge all the way around. Find the diameter of the cloth and the area of fabric needed.
  7. Reasoning. A circle's diameter doubles from 66 cm to 1212 cm. Compute the circumference and area both times, then describe what doubling the diameter does to each. Explain why the two effects are different.

Exit ticket 14.5

  1. A circular tabletop is 66 ft across. Find the length of trim needed for its edge.
  2. A sprinkler reaches 99 ft in every direction. Find the area it waters.
  3. A wheel with diameter 33 ft makes 5050 turns. How far does it travel?
  4. A problem asks how much sod is needed for a circular lawn. Explain which formula you would use and why.

Chapter 14 Review

Vocabulary. circle · center · radius · diameter · chord · circumference · area · pi · semicircle

Use π3.14\pi \approx 3.14 throughout. Include units in every answer.

Part A — Identifying and describing the parts of a circle (6.MG.1a)

  1. Name the part of a circle described by each: a) a segment from the center to the circle b) a segment with both endpoints on the circle c) the distance around the circle d) the surface inside the circle
  2. Explain the difference between a chord and a diameter.
  3. Which measurement is reported in square units, circumference or area? Why?
  4. A circle has radius 1515 cm. Name the length of its longest chord.

Part B — Relationships among radius, diameter, and circumference (6.MG.1b)

  1. Find the diameter: a) r=8r = 8 in b) r=3.5r = 3.5 ft
  2. Find the radius: a) d=50d = 50 m b) d=9d = 9 cm
  3. A circle's radius triples from 22 cm to 66 cm. Find both circumferences and describe the effect on the circumference.
  4. Complete the sentence and explain: the circumference of a circle is always about ______ times its diameter.

Part C — Approximating pi from data (6.MG.1c)

  1. Find Cd\dfrac{C}{d} to the nearest hundredth: a) C=25.1C = 25.1 cm, d=8.0d = 8.0 cm b) C=44.0C = 44.0 cm, d=14.0d = 14.0 cm
  2. Average the two ratios from item 9 and name the number they approximate.
  3. A group reports a ratio of 3.553.55. Explain why this is probably a measurement error and name one likely cause.

Part D — Developing and using the circumference formula (6.MG.1d)

  1. Starting from π=Cd\pi = \dfrac{C}{d}, show how to get C=πdC = \pi d.
  2. Explain why C=2πrC = 2\pi r follows from C=πdC = \pi d.
  3. Find the circumference: a) d=22d = 22 cm b) r=15r = 15 in
  4. A circle has circumference 43.9643.96 ft. Find its diameter and radius.

Part E — Solving problems involving circumference and area (6.MG.1e)

  1. Find the area: a) r=12r = 12 cm b) d=26d = 26 in
  2. A circular fountain has radius 66 ft. Find the distance around it and the area of its surface.
  3. A tire has diameter 3030 in. How far does it travel in one turn? In 2020 turns?
  4. Application. A circular patio has diameter 2020 ft. Concrete costs $5 per square foot and a decorative border costs $8 per foot. Find the total cost of the patio and its border.
  5. Reasoning. Two circles have radii 55 cm and 1010 cm. Explain, with numbers, why doubling the radius doubles the circumference but multiplies the area by four.

Standards coverage check — Chapter 14

Knowledge and Skill Where it is taught Where it is practiced
6.MG.1a — identify and describe chord, diameter, radius, circumference, and area of a circle 14.1 14.1 all sets; Mid-chapter check; Review Part A
6.MG.1b — investigate and describe the relationships between diameter and radius, radius and circumference, and diameter and circumference 14.1, 14.2, 14.3 14.1 items 3–8, 11; 14.2 all sets; 14.3 items 5, 9; Mid-chapter check; Review Part B
6.MG.1c — develop an approximation for pi (3.14) by gathering data comparing circumference to diameter 14.2 14.2 all sets; Mid-chapter check item 4; Review Part C
6.MG.1d — develop the formula for circumference using the relationship between diameter, radius, and pi 14.3 14.3 all sets; Review Part D
6.MG.1e — solve problems, including those in context, involving circumference and area given the diameter or radius 14.3, 14.4, 14.5 14.3, 14.4, 14.5 all sets; Mid-chapter check items 5–8; Review Parts D and E

Answer keys for every set in this chapter are in Appendix A.