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Virginia SOL Mathematics Textbook

Grade 6 Workbook — Chapter 14: Circles: Circumference and Area

SOL 6.MG.1 · Companion to Textbook Chapter 14

Each page below is one Canva page. Headings are sized for direct paste: page title as H1, section labels as H2. Figures referenced by filename live in ../figures/.


PAGE 1 — Chapter opener

Chapter 14 · Circles: Circumference and Area

Standard 6.MG.1

In this chapter you will:

Words to know: circle · center · radius · diameter · chord · circumference · area · pi · semicircle

Formula bar: d=2rd = 2r · r=d2r = \dfrac{d}{2} · C=πdC = \pi d · C=2πrC = 2\pi r · A=πr2A = \pi r^2 · use π3.14\pi \approx 3.14


PAGE 2 — Parts of a circle

14.1 Parts of a Circle

FIGURE: fig1-circle-parts.png (full width) [Circle with center O; labeled radius OA, diameter BC through the center, chord DE not through the center, an arrow to the curve labeled circumference, and the shaded interior labeled area.]

Label each part on the figure above, then complete the definitions.

A radius goes from the ____________ to a point on the circle.

A diameter passes through the ____________ and has both endpoints on the circle.

A chord has both endpoints ____________ , and does not have to pass through the center.

Circumference is the distance ____________ the circle. Units: ____________

Area is the surface ____________ the circle. Units: ____________

True or false.

Statement T or F
Every diameter is a chord.
Every chord is a diameter.
All radii of one circle are the same length.
The diameter is the longest chord.

PAGE 3 — Radius and diameter

d=2rd = 2r and r=d2r = \dfrac{d}{2}

FIGURE: fig2-radius-diameter.png (right half of page) [Two circles: one labeled r = 5 cm with diameter 10 cm and a bracket showing two radii; one labeled d = 14 in with radius 7 in.]

Complete the table.

Radius Diameter
66 cm
4.54.5 in
12.512.5 m
3030 ft
77 cm
1515 in
1414 cm
1111 in

Apply it. A round pond measures 4040 ft straight across through the middle.

That measurement is called the ____________ . Distance from center to edge: ______ ft, called the ____________ .

Explain. Why can a chord never be longer than the diameter?



PAGE 4 — Exit ticket 14.1

Exit Ticket · Lesson 14.1

Name: ________________________ Date: ____________

  1. A circle has radius 1111 cm. Diameter: ______

  2. A circle has diameter 99 in. Radius: ______

  3. Define chord in your own words.


  1. Why is circumference measured in units but area in square units?


PAGE 5 — Wrap the string

14.2 Discovering Pi

FIGURE: fig4-wrap-string.png (full width) [A can lid with string wrapped once around it; below, the string laid straight with three diameter-lengths laid end to end along it and a short piece left over.]

The big question: How many diameters fit around a circle?

Your answer after wrapping the string: about ______ diameters and a little more.

Measure three round objects. Record and compute.

Object Circumference CC Diameter dd C÷dC \div d (hundredths)

Average of your three ratios: ______

The number you are closing in on is called ____________ , written π\pi, and we use π\pi \approx ______ .


PAGE 6 — Class data set

Comparing CC to dd

Compute each ratio to the nearest hundredth.

Object CC dd C÷dC \div d
Jar lid 15.715.7 cm 5.05.0 cm
Cup rim 25.325.3 cm 8.08.0 cm
Platter 75.275.2 cm 24.024.0 cm
Bottle cap 12.612.6 cm 4.04.0 cm
Salad bowl 47.147.1 cm 15.015.0 cm
Mug 29.829.8 cm 9.59.5 cm
Wastebasket 69.169.1 cm 22.022.0 cm

FIGURE: fig5-pi-scatter.png (half width) [Scatter plot of diameter versus circumference for five circles with a straight line through the origin labeled C = 3.14d.]

What do all seven ratios have in common?


Explain. Why does almost nobody measure exactly 3.143.14?



PAGE 7 — Exit ticket 14.2

Exit Ticket · Lesson 14.2

Name: ________________________ Date: ____________

  1. C=18.9C = 18.9 cm and d=6.0d = 6.0 cm. Find C÷dC \div d to the nearest hundredth. ______

  2. What number does C÷dC \div d approach for every circle? ______ Its name: ____________

  3. About how many diameters fit around a circle? ______

  4. Why are measured ratios not all the same?



PAGE 8 — Building the circumference formula

14.3 Circumference

FIGURE: fig6-circumference-formula.png (full width) [Two circles: one with diameter labeled d and C = pi times d beneath; one with radius labeled r and C = 2 times pi times r beneath; a two-way arrow labeled d = 2r between them.]

Fill in the derivation.

π=C___C=π×___\pi = \frac{C}{\_\_\_}\qquad \Longrightarrow \qquad C = \pi \times \_\_\_

Because d=2rd = 2r, replacing dd gives C=π(___)=___πrC = \pi(\_\_\_) = \_\_\_\pi r.

Which formula would you use?

Given Formula
radius =7= 7 m
diameter =7= 7 m

Find each circumference. Show the substitution.

  1. d=10d = 10 cm → C=3.14×C = 3.14 \times ______ == ______

  2. d=20d = 20 in → ______

  3. r=4r = 4 ft → C=2×3.14×C = 2 \times 3.14 \times ______ == ______

  4. r=9r = 9 m → ______


PAGE 9 — Circumference practice

Circumference Practice

Find each circumference. Include units.

a) d=5d = 5 cm b) d=30d = 30 mm
c) r=11r = 11 in d) r=2.5r = 2.5 m
e) d=7.5d = 7.5 cm f) r=6r = 6 cm
g) d=25d = 25 ft h) r=12r = 12 m

Work backward.

  1. C=94.2C = 94.2 ft. Diameter: ______ Radius: ______

  2. C=31.4C = 31.4 m. Diameter: ______

  3. C=18.84C = 18.84 cm. Radius: ______

Doubling. Circle A: r=3r = 3 cm → C=C = ______ Circle B: r=6r = 6 cm → C=C = ______

What happened to the circumference when the radius doubled? _______________

Error hunt. Priya wrote: "r=8r = 8 cm, so C=3.14×8=25.12C = 3.14 \times 8 = 25.12 cm."

Her error: _______________________________________________

Correct answer: ______


PAGE 10 — Exit ticket 14.3

Exit Ticket · Lesson 14.3

Name: ________________________ Date: ____________

  1. d=15d = 15 cm → C=C = ______

  2. r=5r = 5 in → C=C = ______

  3. C=31.4C = 31.4 m → d=d = ______

  4. Why do C=πdC = \pi d and C=2πrC = 2\pi r always agree for the same circle?



PAGE 11 — Where the area formula comes from

14.4 Area of a Circle

FIGURE: fig7-area-sectors.png (full width) [A circle cut into 8 equal wedges, then the wedges rearranged into a row alternating point-up and point-down to form a near-parallelogram; the slanted height labeled r and the base labeled half the circumference, pi times r.]

Complete the reasoning.

The height of the near-parallelogram is the ____________ , or rr.

The base is half the circumference, which is 2πr2=\dfrac{2\pi r}{2} = ______ .

Area of a parallelogram == base ×\times height, so A=(πr)(r)=A = (\pi r)(r) = ______ .

Order matters. In A=πr2A = \pi r^2, square the ____________ first, then multiply by π\pi.

For r=5r = 5: 52=5^2 = ______ , then 3.14×3.14 \times ______ == ______

FIGURE: fig8-area-grid.png (half width) [A circle of radius 5 on a square grid with whole interior squares shaded darker and partial edge squares shaded lighter.]

Counting squares gives about ______ square units, which matches the formula.


PAGE 12 — Area practice

Area Practice

Find each area. Include square units.

a) r=5r = 5 cm b) r=10r = 10 in
c) r=3r = 3 cm d) r=7r = 7 in
e) r=2.5r = 2.5 in f) r=1.5r = 1.5 cm
g) d=8d = 8 ft h) d=20d = 20 m
i) d=12d = 12 ft j) d=30d = 30 m

Work backward.

  1. A=50.24 ft2A = 50.24\ \text{ft}^2. Radius: ______

  2. A=28.26 m2A = 28.26\ \text{m}^2. Radius: ______

Same circle, two measurements. r=6r = 6 cm.

C=C = ______ A=A = ______ Why are the units different? _______________

Error hunt. Devon wrote: "d=10d = 10 cm, so A=3.14×102=314 cm2A = 3.14 \times 10^2 = 314\ \text{cm}^2."

Error: _______________________________________________

Correct area: ______ Devon's answer was ______ times too large.


PAGE 13 — Exit ticket 14.4

Exit Ticket · Lesson 14.4

Name: ________________________ Date: ____________

  1. r=9r = 9 cm → A=A = ______

  2. d=4d = 4 in → A=A = ______

  3. A=28.26 m2A = 28.26\ \text{m}^2r=r = ______

  4. Why is area reported in square units but circumference is not?



PAGE 14 — Which measurement does the job need?

14.5 Circle Problems in Context

FIGURE: fig9-sprinkler.png (right half of page) [Overhead view of a lawn with a sprinkler at the center of a shaded circle of watered grass, radius labeled 12 ft.]

Circle the measurement each job needs.

Job Circumference or Area?
Fencing a round pen C / A
Mulching a round flower bed C / A
Trim around a tabletop C / A
Grass a sprinkler waters C / A
One full turn of a wheel C / A
Glass to cover a round table C / A

Then ask: were you given the radius or the diameter?

"Reaches 1212 ft in every direction" gives the ____________ .

"A pizza is 1616 inches" gives the ____________ .

Solve.

  1. Sprinkler, r=12r = 12 ft. Area watered: ______

  2. Pen 4040 ft across. Fence needed: ______

  3. Round rug, r=4r = 4 ft. Area: ______

  4. Trampoline 1414 ft across. Edge padding: ______


PAGE 15 — Real-world circles

Circle Problems

Show your work in the space beside each item.

  1. A pool is 1818 ft across. Distance around: ______ Surface area: ______

  2. A wagon wheel is 22 ft across and turns 100100 times. Distance rolled: ______

  3. A garden has r=10r = 10 ft. Fencing costs $4 per foot. Total cost: ______

  4. A pizza pan has r=7r = 7 in. Area of the pan surface: ______

  5. Two 1010-inch pizzas or one 1616-inch pizza? (Sizes are diameters.)

    Two 1010-in: ______ One 1616-in: ______ More pizza: ______ By how much: ______

  6. A round table is 55 ft across. A cloth must hang 66 in past the edge all around.

    Cloth diameter: ______ Fabric area: ______

  7. Semicircle. A window is a 44 ft by 33 ft rectangle with a semicircle on top.

FIGURE: fig10-semicircle-window.png (half width) [Window shaped as a rectangle 4 ft wide and 3 ft tall with a semicircle of radius 2 ft on top, straight edge matching the rectangle's width.]

Rectangle area: ______  Semicircle area: ______  Total glass: ______
  1. Doubling. Complete the table, then explain.
Circle CC AA
d=6d = 6 cm
d=12d = 12 cm

Doubling the diameter multiplies CC by ______ and AA by ______ .

Why the difference? _______________________________________________


PAGE 16 — Exit ticket 14.5

Exit Ticket · Lesson 14.5

Name: ________________________ Date: ____________

  1. A tabletop is 66 ft across. Trim needed: ______

  2. A sprinkler reaches 99 ft in every direction. Area watered: ______

  3. A wheel 33 ft across makes 5050 turns. Distance: ______

  4. To find how much sod a circular lawn needs, which formula do you use, and why?



PAGE 17 — Chapter 14 review, part 1

Chapter 14 Review

Use π3.14\pi \approx 3.14. Include units.

Part A · Parts of a circle

  1. Name each: a) segment from center to circle ____________ b) segment with both endpoints on the circle ____________ c) distance around ____________ d) surface inside ____________

  2. Difference between a chord and a diameter: _______________________________________________

  3. Which uses square units, CC or AA? ______ Why? _______________

  4. A circle has r=15r = 15 cm. Length of its longest chord: ______

Part B · Radius, diameter, circumference

  1. Diameter: a) r=8r = 8 in ______ b) r=3.5r = 3.5 ft ______

  2. Radius: a) d=50d = 50 m ______ b) d=9d = 9 cm ______

  3. r=2r = 2 cm → C=C = ______ ; r=6r = 6 cm → C=C = ______ ; effect of tripling: _______________

  4. The circumference of a circle is always about ______ times its diameter.

Part C · Approximating pi

  1. C÷dC \div d to hundredths: a) C=25.1C = 25.1 cm, d=8.0d = 8.0 cm ______ b) C=44.0C = 44.0 cm, d=14.0d = 14.0 cm ______

  2. Average of 9a and 9b: ______ This approximates ______ .

  3. A group reports 3.553.55. Likely cause: _______________________________________________


PAGE 18 — Chapter 14 review, part 2

Chapter 14 Review (continued)

Part D · The circumference formula

  1. From π=Cd\pi = \dfrac{C}{d}, show how to get C=πdC = \pi d: _______________________________________________

  2. Why does C=2πrC = 2\pi r follow from C=πdC = \pi d? _______________________________________________

  3. Circumference: a) d=22d = 22 cm ______ b) r=15r = 15 in ______

  4. C=43.96C = 43.96 ft. Diameter: ______ Radius: ______

Part E · Problems with circumference and area

  1. Area: a) r=12r = 12 cm ______ b) d=26d = 26 in ______

  2. A fountain has r=6r = 6 ft. Distance around: ______ Surface area: ______

  3. A tire is 3030 in across. One turn: ______ Twenty turns: ______

  4. A patio is 2020 ft across. Concrete $5 per square foot, border $8 per foot.

    Concrete cost: ______ Border cost: ______ Total: ______

  5. Radii 55 cm and 1010 cm. Show with numbers why doubling the radius doubles CC but multiplies AA by four.



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