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Virginia SOL Mathematics Textbook

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Chapter 6 — Percent of a Number

Standard: 7.CE.2 (d) — The student will solve problems, including those in context, involving proportional relationships.

By the end of this chapter you will be able to:

Lessons: 6.1 Benchmark Percentages · 6.2 Estimating a Percent of a Number · 6.3 Finding an Exact Percent of a Number · 6.4 Percent in Context

Chapter 5 built the machinery of ratio tables, proportions, and unit conversion. This chapter puts one particular proportional relationship to work: the relationship between a percent and an amount. Everything you learned about proportions still applies, and we will use it — but the goal here is speed and judgment. By the end you should be able to find a tip in your head at a restaurant table, and know without checking whether your answer is roughly right.


Lesson 6.1 — Benchmark Percentages

Percent means "per hundred"

A percent is a ratio that compares a number to 100. The symbol %\% means "per hundred," so 35%35\% means 35 out of every 100. That single idea is the whole foundation of this chapter.

Because a percent is a ratio out of 100, every percent can be written three equivalent ways:

35%=35100=0.3535\% = \frac{35}{100} = 0.35

A hundred-square grid with 35 of the 100 cells shaded

Each small square in the grid is one hundredth of the whole, which is exactly 1%1\%. Shade 35 of them and you have shaded 35%35\% of the grid. When someone asks for "35% of 80," they are asking: if the whole 80 were split into 100 equal pieces, how much would 35 of those pieces be worth?

The whole matters

A percent by itself is not an amount. 50%50\% of 8 is 4, and 50%50\% of 800 is 400. The percent tells you what fraction of the whole to take; the whole (also called the base) tells you what you are taking it from. Always name the whole before you start computing.

The benchmark percentages

A benchmark percentage is a percent whose value you can find in your head, without writing anything down. These seven are worth memorizing as actions, not as facts:

Benchmark What it means How to find it Example
100%100\% the whole thing leave the number alone 100%100\% of 39 is 3939
50%50\% one half divide by 2 50%50\% of 86 is 4343
25%25\% one quarter divide by 4, or halve twice 25%25\% of 120 is 3030
75%75\% three quarters 50%+25%50\% + 25\% 75%75\% of 120 is 60+30=9060 + 30 = 90
10%10\% one tenth shift the decimal point one place left 10%10\% of 74 is 7.47.4
5%5\% half of a tenth find 10%10\%, then halve it 5%5\% of 74 is 3.73.7
1%1\% one hundredth shift the decimal point two places left 1%1\% of 74 is 0.740.74

A percent bar from 0% to 100% with the benchmark percentages marked

Why the decimal point shifts

Finding 10%10\% means dividing by 10, and finding 1%1\% means dividing by 100. Dividing by 10 shifts the decimal point one place to the left; dividing by 100 shifts it two places. This is not a trick to memorize — it is what our place-value system does, and you saw it in Chapter 1 with powers of ten.

Finding 10% and 1% of 640 by shifting the decimal point

So 10%10\% of 640640 is 6464, and 1%1\% of 640640 is 6.46.4. Every whole number has an invisible decimal point sitting after its last digit, which is why 640640 becomes 64.064.0 and then 6.406.40.

Watch the whole, not the digits. Students sometimes learn "move the decimal" and then apply it to the percent instead of the base. The decimal point that moves belongs to the whole. To find 10%10\% of 74, move the point in 74.

Combining benchmarks

The reason these seven benchmarks are enough for most mental math is that other percents can be built from them by adding, subtracting, or halving.

35% of 80 shown as a 25% piece plus a 10% piece

The bar shows 35%35\% of 80. The 25%25\% piece is worth 20 and the 10%10\% piece is worth 8, so the two together are worth 28. Checking with multiplication: 0.35×80=280.35 \times 80 = 28. The benchmark route and the multiplication route must always agree, and if they do not, one of them contains an error.

Percents over 100 and under 1

Nothing in the definition stops a percent from being larger than 100 or smaller than 1.

A percent greater than 100%100\% always produces an amount larger than the whole, and a percent less than 100%100\% always produces an amount smaller than the whole. That is a useful check on every answer you write in this chapter.

A double number line for percents

Because percent and amount are proportional, they can be drawn on a double number line — the same tool you used for rates in Chapter 5. The top line carries the percent, always running from 0%0\% to 100%100\%, and the bottom line carries the amount, running from 0 to the whole.

A double number line pairing percent with the number of students in a class of 60

For a class of 60 students, 100%100\% lines up with 60, so each 10%10\% step is 6 students. Reading straight down from any percent gives the matching amount: 30%30\% is 18 students, 70%70\% is 42 students.

Worked examples

Example 1 — Halves and quarters

Find 50%50\% of 48 and 25%25\% of 48.

Half of 48 is 24. A quarter is half of that half.

50% of 48=48÷2=2425% of 48=24÷2=1250\% \text{ of } 48 = 48 \div 2 = 24 \qquad 25\% \text{ of } 48 = 24 \div 2 = 12

Answer: 50%50\% of 48 is 2424; 25%25\% of 48 is 1212

Example 2 — Tenths and hundredths

Find 10%10\% of 350 and 1%1\% of 350.

Shift the decimal point one place left, then two places left.

10% of 350=351% of 350=3.510\% \text{ of } 350 = 35 \qquad 1\% \text{ of } 350 = 3.5

Answer: 3535 and 3.53.5

Example 3 — Building 5% from 10%

Find 5%5\% of 240.

First 10%10\%, then halve it, because 5%5\% is half of 10%10\%.

10% of 240=245% of 240=24÷2=1210\% \text{ of } 240 = 24 \qquad 5\% \text{ of } 240 = 24 \div 2 = 12

Answer: 1212

Example 4 — Building 75% from two benchmarks

Find 75%75\% of 64.

50% of 64=3225% of 64=1650\% \text{ of } 64 = 32 \qquad 25\% \text{ of } 64 = 16 75% of 64=32+16=4875\% \text{ of } 64 = 32 + 16 = 48

Check: 0.75×64=480.75 \times 64 = 48.

Answer: 4848

Example 5 — 100% and 200%

Find 100%100\% of 87 and 200%200\% of 87.

100%100\% is the whole itself. 200%200\% is two wholes.

100% of 87=87200% of 87=2×87=174100\% \text{ of } 87 = 87 \qquad 200\% \text{ of } 87 = 2 \times 87 = 174

Answer: 8787 and 174174

Guided practice

  1. Find 50%50\% of 86.
  2. Find 25%25\% of 120.
  3. Find 10%10\% of 74.
  4. Find 1%1\% of 74.
  5. Find 5%5\% of 60. (Find 10%10\% first, then halve it.)
  6. Find 75%75\% of 200. (Add 50%50\% of 200 and 25%25\% of 200.)

Independent practice

  1. Find each: a) 50%50\% of 250 b) 25%25\% of 88 c) 10%10\% of 4{,}500 d) 1%1\% of 620

  2. Find each: a) 5%5\% of 140 b) 75%75\% of 48 c) 100%100\% of 39 d) 200%200\% of 45

  3. Find 10%10\% of 96, then use that result to find 20%20\% of 96.

  4. Which is greater, 25%25\% of 160 or 10%10\% of 380? Show both amounts.

  5. Explain how to find 10%10\% of 730 without dividing on paper, and give the answer.

  6. Complete the benchmark table for a whole of 600.

    Percent 50%50\% 25%25\% 10%10\% 5%5\% 1%1\% 75%75\%
    Amount of 600
  7. Application. A restaurant bill is $40. Find a 10%10\% tip and a 20%20\% tip on that bill.

  8. Reasoning. Explain why 5%5\% of a number is always exactly half of 10%10\% of that same number.

Exit ticket 6.1

  1. Find 50%50\% of 92.
  2. Find 10%10\% of 830.
  3. Find 1%1\% of 830.
  4. Describe two different ways to find 25%25\% of 48, then give the answer.

Lesson 6.2 — Estimating a Percent of a Number

Why estimate at all

You will not always need an exact answer, and you will not always have paper. Standing in a store, "about $12 off" is enough to decide. More importantly, an estimate is how you catch mistakes: if you estimate 2020 and your calculator says 200200, you know to look again before you trust it.

To estimate a percent of a number means to replace the problem with a nearby, friendlier problem you can do in your head. You make two decisions:

  1. Round the percent to a nearby benchmark. 48%48\% becomes 50%50\%; 26%26\% becomes 25%25\%; 9%9\% becomes 10%10\%; 73%73\% becomes 75%75\%.
  2. Round the whole to a friendly number. Friendly means easy to halve, quarter, or divide by 10 — usually a multiple of 10, 20, or 100.

Then compute the friendly problem exactly. That result is your estimate.

Naming the strategy

An estimate is only defensible if you say what you rounded to. "About 40" means nothing on its own; "50%50\% of 80 is 40, so it's about 40" is a complete answer that another person can check. Throughout this lesson, state the benchmark you used.

48% of 8250% of 80=4048\% \text{ of } 82 \approx 50\% \text{ of } 80 = 40

The symbol \approx is read "is approximately equal to." Use it whenever you replace a problem with a nearby one, and save the equals sign for statements that are exactly true.

High or low?

You can often tell which side of the exact answer your estimate falls on, just by looking at how you rounded.

The benchmark estimate for 48% of 250 shown beside the exact value

For 48%48\% of 250, only the percent was rounded, and it was rounded up from 48%48\% to 50%50\%. So the estimate of 125 must be a little high — and it is, since the exact value is 120.

When you round the percent one way and the whole the other way, the two effects push in opposite directions and you cannot tell the direction of the error from the rounding alone. In that situation, say so rather than guessing.

Worked examples

Example 1 — Rounding to 50%

About how much is 48%48\% of 82?

48%48\% is close to 50%50\%, and 82 is close to 80.

48% of 8250% of 80=4048\% \text{ of } 82 \approx 50\% \text{ of } 80 = 40

Answer: about 4040

Example 2 — Rounding to 25%

About how much is 26%26\% of 119?

26%26\% is close to 25%25\%, and 119 is close to 120, which divides evenly by 4.

26% of 11925% of 120=3026\% \text{ of } 119 \approx 25\% \text{ of } 120 = 30

Answer: about 3030

Example 3 — Rounding to 10%

About how much is 9%9\% of 71?

9% of 7110% of 70=79\% \text{ of } 71 \approx 10\% \text{ of } 70 = 7

Because the percent was rounded up and the whole was rounded down, the two errors partly cancel. The exact value is 6.396.39, close to the estimate.

Answer: about 77

Example 4 — Rounding to 75%

About how much is 73%73\% of 41?

73% of 4175% of 40=3073\% \text{ of } 41 \approx 75\% \text{ of } 40 = 30

Answer: about 3030

Example 5 — Choosing among options

Which is closest to 19%19\% of 246: 25, 50, 75, or 100?

Round to 20%20\% of 250. Since 10%10\% of 250 is 25, doubling gives 20%20\% of 250=50250 = 50.

Answer: 5050

Guided practice

  1. Estimate 52%52\% of 78 by finding 50%50\% of 80.
  2. Estimate 24%24\% of 41 by finding 25%25\% of 40.
  3. Estimate 11%11\% of 89 by finding 10%10\% of 90.
  4. Estimate 76%76\% of 61 by finding 75%75\% of 60.
  5. Estimate 9%9\% of 412 by finding 10%10\% of 400.
  6. Estimate 48%48\% of 305 by finding 50%50\% of 300.

Independent practice

  1. Estimate each using the benchmark and friendly whole shown in parentheses. a) 49%49\% of 62 (50%50\% of 60) b) 26%26\% of 79 (25%25\% of 80) c) 9%9\% of 51 (10%10\% of 50) d) 74%74\% of 81 (75%75\% of 80)
  2. Which is closest to 31%31\% of 297: 30, 60, 90, or 120? Name the benchmark you used.
  3. Which is closest to 6%6\% of 396: 8, 16, 24, or 40? Name the benchmark you used.
  4. Estimate 48%48\% of 398 by finding 50%50\% of 400. Is your estimate higher or lower than the exact answer? Explain how you know without computing the exact answer.
  5. Estimate 35%35\% of 61 by combining two benchmarks of 60.
  6. Application. A jacket costs $59. About how many dollars is 20%20\% of that price? Use $60 as the friendly whole.
  7. Application. A school has 412 students, and about 25%25\% of them ride the bus. About how many students ride the bus? Name the friendly whole you used.
  8. Reasoning. Marisol estimates 9%9\% of 240 as 24, because 10%10\% of 240 is 24. Is her estimate higher or lower than the exact answer? Explain.

Exit ticket 6.2

  1. Estimate 51%51\% of 78 by finding 50%50\% of 80.
  2. Estimate 24%24\% of 121 by finding 25%25\% of 120.
  3. Which is closest to 11%11\% of 508: 5, 50, 100, or 250?
  4. Explain why rounding the whole up, with the percent left alone, makes an estimate greater than the exact answer.

Lesson 6.3 — Finding an Exact Percent of a Number

Four routes to the same answer

When an exact answer is required, you have four reliable methods. They are not competing rules to choose between at random — each is best suited to a particular kind of problem.

Method 1 — Multiply by the decimal. Rewrite the percent as a decimal by dividing by 100, then multiply.

18% of 250=0.18×250=4518\% \text{ of } 250 = 0.18 \times 250 = 45

Method 2 — Multiply by the fraction. Rewrite the percent as a fraction over 100 and multiply. This is often fastest when the fraction simplifies.

18% of 250=18100×250=950×250=9×5=4518\% \text{ of } 250 = \frac{18}{100} \times 250 = \frac{9}{50} \times 250 = 9 \times 5 = 45

Method 3 — Set up a proportion. From Chapter 5, a proportion is an equation stating that two ratios are equal. The percent proportion pairs the part-to-whole ratio with the percent-to-100 ratio:

partwhole=percent100\frac{\text{part}}{\text{whole}} = \frac{\text{percent}}{100}

For 18%18\% of 250, that gives x250=18100\dfrac{x}{250} = \dfrac{18}{100}. Solve it with the cross-product reasoning from Chapter 5: 100x=18×250=4500100x = 18 \times 250 = 4500, so x=45x = 45.

Method 4 — Combine benchmarks. Break the percent into benchmark pieces, find each piece, and add.

18% of 250=10%+5%+1%+1%+1%=25+12.5+2.5+2.5+2.5=4518\% \text{ of } 250 = 10\% + 5\% + 1\% + 1\% + 1\% = 25 + 12.5 + 2.5 + 2.5 + 2.5 = 45

All four give 45, because they are all expressions of the same proportional relationship. Method 1 is the workhorse. Method 4 is the one to use when you have no pencil.

Choosing well

If the percent is… Reach for…
built from benchmarks, like 15%15\%, 35%35\%, 60%60\% Method 4, benchmarks
an awkward two-digit percent, like 18%18\% or 47%47\% Method 1, decimal multiplication
a percent whose fraction simplifies, like 20%20\% or 75%75\% Method 2, fractions
stated in a word problem with an unknown to name Method 3, a proportion

Writing the decimal correctly

Converting a percent to a decimal means dividing by 100, which shifts the decimal point two places left. Keep track of where the point started.

Percent Decimal Note
45%45\% 0.450.45 two digits, so no extra zero needed
8%8\% 0.080.08 one digit, so a placeholder zero is required
120%120\% 1.201.20 greater than 1, as it must be
0.5%0.5\% 0.0050.005 half of 0.010.01

The single most common error in this lesson is writing 8%8\% as 0.80.8. That is 80%80\% — ten times too big. Estimating first protects you: 8%8\% of 250 must be a small piece of 250, so 20 is plausible and 200 is not.

Worked examples

Example 1 — Decimal multiplication

Find 18%18\% of 250.

18%=0.1818\% = 0.18 0.18×250=450.18 \times 250 = 45

Estimate check: 20%20\% of 250 would be 50, and 18%18\% is a bit less than that.

Answer: 4545

Example 2 — Benchmark combination

Find 35%35\% of 80.

25% of 80=2010% of 80=825\% \text{ of } 80 = 20 \qquad 10\% \text{ of } 80 = 8 35% of 80=20+8=2835\% \text{ of } 80 = 20 + 8 = 28

Check: 0.35×80=280.35 \times 80 = 28.

Answer: 2828

Example 3 — Using a proportion

Find 42%42\% of 150.

Let xx be the part.

x150=42100\frac{x}{150} = \frac{42}{100} 100x=42×150=6300100x = 42 \times 150 = 6300 x=6300100=63x = \frac{6300}{100} = 63

Answer: 6363

Example 4 — A small percent

Find 6%6\% of 45.

6%=0.066\% = 0.06 0.06×45=2.70.06 \times 45 = 2.7

Check with benchmarks: 1%1\% of 45 is 0.450.45, and 6×0.45=2.76 \times 0.45 = 2.7.

Answer: 2.72.7

Example 5 — Beyond 100% and below 1%

Find 120%120\% of 65 and 0.5%0.5\% of 400.

120%=1.21.2×65=78120\% = 1.2 \qquad 1.2 \times 65 = 78 0.5%=0.0050.005×400=20.5\% = 0.005 \qquad 0.005 \times 400 = 2

The first answer is greater than 65, as it must be for a percent above 100%100\%. The second is tiny, as it must be for a percent below 1%1\%.

Answer: 7878 and 22

Guided practice

  1. Find 20%20\% of 45.
  2. Find 15%15\% of 60 by adding 10%10\% of 60 and 5%5\% of 60.
  3. Find 8%8\% of 250. (Write the decimal carefully.)
  4. Find 45%45\% of 80.
  5. Find 35%35\% of 140 by adding 25%25\% of 140 and 10%10\% of 140.
  6. Find 110%110\% of 90.

Independent practice

  1. Find each: a) 30%30\% of 70 b) 12%12\% of 300 c) 65%65\% of 40 d) 4%4\% of 225
  2. Find each: a) 55%55\% of 120 b) 85%85\% of 60 c) 150%150\% of 48 d) 2%2\% of 850
  3. Find 65%65\% of 240 by combining benchmarks. Show which benchmarks you used.
  4. Find 18%18\% of 950 by multiplying by a decimal.
  5. Write a proportion for "24%24\% of 175" and solve it. Show the cross products.
  6. Find 0.5%0.5\% of 600.
  7. Application. A store has 640 T-shirts in stock, and 45%45\% of them are blue. How many blue T-shirts are in stock?
  8. Reasoning. Explain why finding 25%25\% of 84 gives the same result as dividing 84 by 4. Give the answer as part of your explanation.

Exit ticket 6.3

  1. Find 40%40\% of 65.
  2. Find 15%15\% of 220.
  3. Find 130%130\% of 50.
  4. Find 35%35\% of 60 two different ways and show that both give the same answer.

Lesson 6.4 — Percent in Context

The four questions that cover most of it

Almost every percent problem you meet outside a classroom is one of four familiar situations. In all four, the mathematics is identical — find a percent of a whole — and the only new work is reading carefully enough to identify which number is the whole.

A reliable procedure

  1. Name the whole. Which number is the bill, the price, the group size?
  2. Name the percent.
  3. Estimate with a benchmark, so you know roughly what to expect.
  4. Compute exactly.
  5. Answer the question that was asked. A discount problem may ask for the amount off, or for the sale price. Those are different numbers.

Step 5 is where careful students still lose points. Read the last sentence of the problem twice.

Working with money

Money answers are written with two decimal places, because prices are exact to the cent: write $9.00, not $9, and $8.64, not $8.64000. When a computation produces a third decimal place, the problem will tell you to round to the nearest cent. If it does not tell you, the numbers were chosen so that the answer lands exactly on the cent.

The benchmark tip

The most useful mental-math skill in this whole chapter is the restaurant tip, and it runs entirely on the benchmarks from Lesson 6.1.

Worked examples

Example 1 — A tip

Find a 20%20\% tip on a $45 restaurant bill.

The whole is $45. Find 10%10\%, then double.

10% of 45=4.520% of 45=2×4.5=910\% \text{ of } 45 = 4.5 \qquad 20\% \text{ of } 45 = 2 \times 4.5 = 9

Answer: $9.00

Example 2 — Sales tax and a total

A bicycle helmet costs $120. Sales tax is 6%6\%. Find the tax and the total cost.

6% of 120=0.06×120=7.26\% \text{ of } 120 = 0.06 \times 120 = 7.2 total=120+7.20=127.20\text{total} = 120 + 7.20 = 127.20

Answer: tax $7.20; total $127.20

Example 3 — A discount and a sale price

A jacket regularly costs $85 and is marked 30%30\% off. Find the discount and the sale price.

30% of 85=0.30×85=25.530\% \text{ of } 85 = 0.30 \times 85 = 25.5 sale price=8525.50=59.50\text{sale price} = 85 - 25.50 = 59.50

Answer: discount $25.50; sale price $59.50

Example 4 — A survey

In a school of 350 students, 12%12\% walk to school. How many students walk?

The whole is 350 students.

12% of 350=0.12×350=4212\% \text{ of } 350 = 0.12 \times 350 = 42

An answer of 42 students is sensible: it is a small part of 350, and it is a whole number of people, which it must be.

Answer: 42 students

Example 5 — Estimate, then compute

A dinner bill is $62 and you want to leave a 15%15\% tip. Estimate first, then find the exact tip.

Estimate with a friendly $60: 10%10\% of 60 is 6, half of that is 3, so about $9.

Exact: 0.15×62=9.30.15 \times 62 = 9.3.

Answer: about $9; exactly $9.30

Guided practice

  1. Find a 10%10\% tip on a $36 bill.
  2. Find a 20%20\% tip on a $55 bill.
  3. A furniture order costs $240. Find the 5%5\% sales tax.
  4. Shoes that cost $64 are marked 25%25\% off. Find the amount of the discount.
  5. In a group of 250 students, 40%40\% chose soccer. How many students chose soccer?

Independent practice

  1. Find a 15%15\% tip on an $80 bill. (Use 10%10\% plus 5%5\%.)
  2. A tablet costs $150 and sales tax is 7%7\%. Find the tax.
  3. A coat regularly costs $120 and is marked 35%35\% off. Find the discount and the sale price.
  4. A basketball team attempted 40 free throws and made 65%65\% of them. How many did they make?
  5. A phone plan includes 1{,}250 megabytes of data, and Jordan has used 8%8\% of it. How many megabytes has Jordan used?
  6. Application. A restaurant bill is $48. Find an 18%18\% tip, then find the total the customer pays.
  7. Application. A theater has 350 seats, and 22%22\% of them are in the balcony. First estimate the number of balcony seats using 20%20\% of 350, then find the exact number.
  8. Reasoning. Explain why taking 20%20\% off a $60 price gives the same sale price as finding 80%80\% of $60. Show both computations.

Exit ticket 6.4

  1. Find a 20%20\% tip on a $65 bill.
  2. A chair costs $250 and sales tax is 6%6\%. Find the tax.
  3. A bike listed at $140 is marked 30%30\% off. Find the amount of the discount.
  4. Describe a benchmark strategy for finding a 15%15\% tip on a $40 bill, and give the tip.

Chapter 6 Review

Vocabulary. percent · whole (base) · benchmark percentage · estimate · double number line · discount · sale price · sales tax · tip

Part A — Benchmark percentages (7.CE.2d)

  1. Find 50%50\% of 148.
  2. Find 25%25\% of 320.
  3. Find 10%10\% of 76.
  4. Find 1%1\% of 76.
  5. Find 5%5\% of 180.
  6. Find 75%75\% of 88.

Part B — Estimating a percent of a number (7.CE.2d)

  1. Estimate 49%49\% of 122 by finding 50%50\% of 120.
  2. Estimate 26%26\% of 79 by finding 25%25\% of 80.
  3. Estimate 9%9\% of 305 by finding 10%10\% of 300.
  4. Estimate 74%74\% of 41 by finding 75%75\% of 40.
  5. Which is closest to 34%34\% of 298: 30, 60, 100, or 150? Name the benchmark you used.
  6. Is 10%10\% of 480 a high estimate or a low estimate for 9%9\% of 480? Give both the estimate and the exact value.

Part C — Determining an exact percent (7.CE.2d)

  1. Find 30%30\% of 150.
  2. Find 12%12\% of 425.
  3. Find 65%65\% of 80.
  4. Find 4%4\% of 375.
  5. Find 140%140\% of 60.
  6. Find 0.5%0.5\% of 800.

Part D — Percent in context (7.CE.2d)

  1. Find an 18%18\% tip on a $60 restaurant bill.
  2. A backpack costs $45 and sales tax is 6%6\%. Find the tax and the total cost.
  3. A tent listed at $95 is marked 40%40\% off. Find the discount and the sale price.

Part E — Mixed application and reasoning

  1. Find 35%35\% of 260 by combining benchmarks. Show each benchmark amount and the sum.
  2. Estimate 48%48\% of 250 using a benchmark, then compute the exact value. Explain why the estimate falls on the high side.
  3. Explain why moving the decimal point gives 10%10\% and 1%1\% of a number. Use 640 in your explanation.

Standards coverage check — Chapter 6

Bullet d of 7.CE.2 asks students to "estimate and determine the percentage of a given whole number, including but not limited to the use of benchmark percentages." That single bullet contains three component demands, tracked separately below.

Component demand of 7.CE.2d Where it is taught Where it is practiced
Use benchmark percentages (1%1\%, 5%5\%, 10%10\%, 25%25\%, 50%50\%, 75%75\%, 100%100\%) of a whole number 6.1 Items 1–18; 29; 38, 41, 45; 55–60, 71; Review 72–77, 93, 95
Estimate the percentage of a whole number 6.2 Items 19–36; 66; Review 78–83, 94
Determine the percentage of a whole number, "not limited to" benchmarks — decimals, fractions, and proportions 6.3 Items 37–54; 61–65, 68–70; Review 84–89, 90–92
Apply both estimating and determining to problems in context 6.2, 6.4 Items 30, 31; 49; 55–71; Review 90–92, 94

Percents greater than 100%100\% appear in items 8d, 42, 44c, 53, and 88; percents less than 1%1\% appear in items 48 and 89. The whole is a whole number throughout, as the standard specifies.

Scope note. Parts a–c of 7.CE.2 — ratio tables, writing and solving proportions, and unit conversion with a given conversion factor — are covered in Chapter 5. This chapter uses proportions as one of four solution methods in Lesson 6.3 but does not re-teach them. Percent increase and decrease, percent error, and finding the whole from a known part are not part of 7.CE.2d and appear in later standards, so they are deliberately absent here.

Answer keys for every set in this chapter are in Appendix A.