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Virginia SOL Mathematics Textbook

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Chapter 4 — Operations with Rational Numbers in Context

Standard: 7.CE.1 — The student will estimate, solve, and justify solutions to multistep contextual problems involving operations with rational numbers.

By the end of this chapter you will be able to:

Lessons: 4.1 Adding and Subtracting Rational Numbers · 4.2 Multiplying and Dividing Rational Numbers · 4.3 Estimating to Judge Whether an Answer Is Reasonable · 4.4 Multistep Problems in Context · 4.5 Justifying a Solution

Calculator note. A calculator is allowed throughout this chapter. That does not make estimation optional — it makes it essential. A calculator will faithfully compute whatever you type, including a mistyped decimal point or a dropped negative sign. Your estimate is the only thing standing between a typing slip and a wrong answer.


Lesson 4.1 — Adding and Subtracting Rational Numbers

What counts as a rational number

A rational number is any number that can be written as a fraction of two integers, with a denominator that is not zero. That definition is broader than it first sounds. It includes:

In this chapter, fractions may be positive or negative, and decimals may be positive or negative and go no further than the thousandths place — three digits after the decimal point, like 3.1993.199.

Every one of these forms shows up in real situations, often in the same problem. A bank statement mixes decimals and integers. A recipe mixes mixed numbers and fractions. Part of the work in this chapter is moving comfortably between forms.

Adding and subtracting with signs

Adding rational numbers works exactly the way adding integers worked in Grade 6, because the number line does not change when the values between the tick marks get finer.

Adding a positive moves right. Adding a negative moves left.

A temperature of 3.53.5°F that falls 12.2512.25 degrees is a starting point plus a negative change:

3.5+(12.25)=8.753.5 + (-12.25) = -8.75

A temperature falling 12.25 degrees from 3.5 degrees Fahrenheit, past zero, to negative 8.75 degrees

Notice how the picture makes the size of the answer sensible before you compute anything. The starting point is only 3.53.5 above zero, and the fall is much larger than that, so the result must be negative — and it must be a bit less than 8-8, since 12.253.5=8.7512.25 - 3.5 = 8.75.

Subtraction is handled by one rule you will use constantly:

To subtract, add the opposite.  ab=a+(b)\ a - b = a + (-b)

So 6.2(3.85)6.2 - (-3.85) becomes 6.2+3.85=10.056.2 + 3.85 = 10.05. Subtracting a negative increases the value, which feels strange until you attach it to a situation: if a $3.85 fee is removed from your account, your balance goes up.

Adding and subtracting fractions in context

With fractions, the arithmetic needs one extra step: a common denominator. You cannot combine eighths and quarters until they are written as the same kind of piece.

A cook starts with 3143\tfrac{1}{4} cups of broth and uses 1581\tfrac{5}{8} cups. Write both as eighths:

314=268158=1383\tfrac{1}{4} = \frac{26}{8} \qquad 1\tfrac{5}{8} = \frac{13}{8}

268138=138=158\frac{26}{8} - \frac{13}{8} = \frac{13}{8} = 1\tfrac{5}{8}

Three and one-fourth cups less one and five-eighths cups, shown as a jump back along a number line ticked in eighths

The line is ticked in eighths so that both quantities land exactly on a tick. That is not decoration — it is the whole reason common denominators exist. Equal-sized pieces are what make the subtraction possible.

Chains of changes

Real situations rarely involve just one change. A diver at 14.5-14.5 ft descends another 6.256.25 ft, then rises 9.759.75 ft. Work left to right:

14.56.25+9.75=20.75+9.75=11-14.5 - 6.25 + 9.75 = -20.75 + 9.75 = -11

A diver starting at negative 14.5 feet, descending 6.25 feet, then rising 9.75 feet to end at negative 11 feet

Two habits will save you here. First, decide what positive means before you start — for elevation, up is positive — and then translate every phrase in the problem into a signed number. Second, keep the running total visible, as shown above, so you can check each stage against the picture rather than only checking the final number.

Worked examples

Example 1 — An overdrawn account receives a deposit

Kalia's checking balance is $18.75-\$18.75. She deposits $45.50. What is her new balance?

A deposit is a positive change, so add.

18.75+45.50-18.75 + 45.50

The deposit is larger than the debt, so the result is positive. Its size is the difference: 45.5018.75=26.7545.50 - 18.75 = 26.75.

Answer: $26.75

Example 2 — A temperature falling through zero

At 4 p.m. the temperature is 3.53.5°F. Overnight it falls 12.2512.25 degrees. What is the temperature afterward?

A fall is a negative change.

3.5+(12.25)3.5 + (-12.25)

Since 12.25>3.512.25 > 3.5, the answer is negative, with size 12.253.5=8.7512.25 - 3.5 = 8.75.

Answer: 8.75-8.75°F

Example 3 — Subtracting mixed numbers in a recipe

A pot holds 3143\tfrac{1}{4} cups of broth. A cook uses 1581\tfrac{5}{8} cups. How much is left?

Rewrite both as eighths, then subtract.

314=268,158=1383\tfrac{1}{4} = \frac{26}{8}, \qquad 1\tfrac{5}{8} = \frac{13}{8}

268138=138=158\frac{26}{8} - \frac{13}{8} = \frac{13}{8} = 1\tfrac{5}{8}

Answer: 1581\tfrac{5}{8} cups

Example 4 — A chain of elevation changes

A diver is at 14.5-14.5 ft. She descends 6.256.25 ft, then rises 9.759.75 ft. What is her final depth?

Descending is negative, rising is positive. Work left to right.

14.56.25=20.75-14.5 - 6.25 = -20.75 20.75+9.75=11-20.75 + 9.75 = -11

Answer: 11-11 ft, or 11 feet below the surface

Example 5 — Adding two negative mixed numbers

A well's water level drops 2132\tfrac{1}{3} ft in June and another 1121\tfrac{1}{2} ft in July. What is the total change?

Both changes are drops, so both are negative.

213+(112)=7332=14696=236-2\tfrac{1}{3} + \left(-1\tfrac{1}{2}\right) = -\frac{7}{3} - \frac{3}{2} = -\frac{14}{6} - \frac{9}{6} = -\frac{23}{6}

236=356-\frac{23}{6} = -3\tfrac{5}{6}

Answer: 356-3\tfrac{5}{6} ft, a total drop of 3563\tfrac{5}{6} feet

Guided practice

  1. Find 7.4+12.9-7.4 + 12.9. First decide whether the answer is positive or negative, then find its size.
  2. Find 214+(534)2\tfrac{1}{4} + \left(-5\tfrac{3}{4}\right). Both quantities are already in fourths.
  3. Rewrite 6.2(3.85)6.2 - (-3.85) as an addition problem, then evaluate it.
  4. At 5 p.m. the temperature is 2.5-2.5°C. It drops 4.754.75°C overnight. What is the temperature the next morning?
  5. Devon's balance is $34.20. He writes a check for $52.75. What is his new balance? State what the sign of your answer means.

Independent practice

  1. Evaluate. a) 9.6+4.25-9.6 + 4.25 b) 323+114-3\tfrac{2}{3} + 1\tfrac{1}{4} c) 7.511.3757.5 - 11.375 d) 56(13)-\tfrac{5}{6} - \left(-\tfrac{1}{3}\right)
  2. A hiker starts at an elevation of 1,240.51{,}240.5 ft, descends 386.75386.75 ft into a valley, then climbs 152.25152.25 ft. What is her final elevation?
  3. A savings account is overdrawn at $42.15-\$42.15. The owner deposits $120.00, then two charges of $18.60 and $35.75 post to the account. What is the final balance?
  4. A jug holds 7127\tfrac{1}{2} quarts of cider. Two pitchers are filled, one with 2342\tfrac{3}{4} quarts and one with 1581\tfrac{5}{8} quarts. How much cider remains in the jug?
  5. Over four days a stock's price changes by 1.25-1.25, +0.875+0.875, 2.5-2.5, and +3.125+3.125 dollars. What is the total change, and did the price end higher or lower than it started?
  6. Application. At 6 a.m. the temperature is 6.5-6.5°F. By noon it has risen 13.2513.25 degrees. By 9 p.m. it has fallen 8.758.75 degrees from the noon reading. What is the temperature at 9 p.m.?
  7. Reasoning. Jordan writes 4.62.8=1.8-4.6 - 2.8 = -1.8, explaining that "subtracting makes it smaller, so I subtracted the digits." Find the correct answer and explain precisely what Jordan misread.

Exit ticket 4.1

  1. Find 8.25+3.5-8.25 + 3.5.
  2. Find 1564131\tfrac{5}{6} - 4\tfrac{1}{3}.
  3. A balance of $16.40-\$16.40 receives a $25.00 deposit. What is the new balance?
  4. Explain, using a situation of your choice, why subtracting a negative number makes a result larger.

Lesson 4.2 — Multiplying and Dividing Rational Numbers

The sign rules, and why they are true

Multiplication is repeated addition, and that is enough to explain the signs.

If a reservoir drops 4.54.5 inches every month, then after 6 months the change is six drops of 4.54.5:

(4.5)(6)=27(-4.5)(6) = -27

A negative repeated a positive number of times stays negative. That gives the first two rules. The third — that two negatives make a positive — is easiest to see by running a pattern backward:

(4.5)(2)=9,(4.5)(1)=4.5,(4.5)(0)=0,(4.5)(1)=4.5(-4.5)(2) = -9, \qquad (-4.5)(1) = -4.5, \qquad (-4.5)(0) = 0, \qquad (-4.5)(-1) = 4.5

Each time the second factor drops by 1, the product rises by 4.54.5. Continuing the pattern past zero forces the product to become positive. In context: if a reservoir has been dropping 4.54.5 inches per month, then one month ago — a negative number of months from now — the level was 4.54.5 inches higher.

Signs of the factors Sign of the product or quotient
positive ×\times positive positive
positive ×\times negative negative
negative ×\times positive negative
negative ×\times negative positive

Division follows the same table, because every division statement is a multiplication statement in disguise: 27÷6=4.5-27 \div 6 = -4.5 is true precisely because (4.5)(6)=27(-4.5)(6) = -27.

Multiplying and dividing fractions

To multiply fractions, multiply numerators and multiply denominators. Convert mixed numbers to improper fractions first, or the distributive property will bite you.

23×(412)=23×(92)=186=3\frac{2}{3} \times \left(-4\tfrac{1}{2}\right) = \frac{2}{3} \times \left(-\frac{9}{2}\right) = -\frac{18}{6} = -3

To divide by a fraction, multiply by its reciprocal — the fraction turned upside down.

638÷34=518×43=20424=172=8126\tfrac{3}{8} \div \frac{3}{4} = \frac{51}{8} \times \frac{4}{3} = \frac{204}{24} = \frac{17}{2} = 8\tfrac{1}{2}

That answer means something concrete: 6386\tfrac{3}{8} cups of soup fills eight full 34\tfrac{3}{4}-cup bowls with half a bowl left over. Division by a fraction almost always answers the question how many of these fit inside that?, and reading the answer back into the situation is how you check that you divided in the right direction.

Two questions division answers

Division in context comes in two flavors, and naming them helps you decide what to divide by what.

Both are division. What changes is which quantity is the divisor, and the surest way to get it right is to state which flavor you are in before you touch the calculator.

Worked examples

Example 1 — A steady negative rate

A reservoir level falls 4.54.5 inches each month. What is the total change after 6 months?

A fall is negative, repeated 6 times.

(4.5)(6)=27(-4.5)(6) = -27

Answer: 27-27 inches, a drop of 27 inches

Example 2 — Multiplying a fraction by a negative mixed number

Find 23×(412)\tfrac{2}{3} \times \left(-4\tfrac{1}{2}\right).

Write the mixed number as an improper fraction, then multiply across.

23×(92)=186=3\frac{2}{3} \times \left(-\frac{9}{2}\right) = -\frac{18}{6} = -3

Answer: 3-3

Example 3 — Sharing a debt

Five roommates split a $73.50 utility overcharge equally. Write the change to each person's balance.

The overcharge is a negative change of 73.50-73.50, shared 5 ways.

73.50÷5=14.70-73.50 \div 5 = -14.70

Answer: $14.70-\$14.70 each, meaning each roommate owes $14.70

Example 4 — Measuring with a fraction divisor

How many 34\tfrac{3}{4}-cup servings can be filled from 6386\tfrac{3}{8} cups of soup?

This is a measuring problem: how many 34\tfrac34 fit inside 6386\tfrac38. Divide by multiplying by the reciprocal.

518÷34=518×43=20424=812\frac{51}{8} \div \frac{3}{4} = \frac{51}{8} \times \frac{4}{3} = \frac{204}{24} = 8\tfrac{1}{2}

Answer: 8 full servings, with half a serving left over

Example 5 — A rate given to the thousandths

A drainage ditch loses 2.3752.375 inches of water per week. What is the change in level after 4 weeks?

(2.375)(4)=9.5(-2.375)(4) = -9.5

Answer: 9.5-9.5 inches, a drop of 9129\tfrac{1}{2} inches

Guided practice

  1. Find (7)(2.5)(-7)(2.5). State the sign first, then the size.
  2. Find (35)(109)\left(-\tfrac{3}{5}\right)\left(-\tfrac{10}{9}\right) and write the answer in simplest form.
  3. Find 20.4÷6-20.4 \div 6.
  4. Find 514÷(112)5\tfrac{1}{4} \div \left(-1\tfrac{1}{2}\right). Convert to improper fractions first.
  5. A well's water level drops 0.3750.375 ft each day. What is the change in level after 8 days?

Independent practice

  1. Evaluate. a) (1.2)(4.5)(-1.2)(-4.5) b) (78)(23)\left(-\tfrac{7}{8}\right)\left(\tfrac{2}{3}\right) c) 15.75÷(2.5)-15.75 \div (-2.5) d) (223)÷45\left(-2\tfrac{2}{3}\right) \div \tfrac{4}{5}
  2. Four friends split a restaurant bill of $146.20 equally. How much does each pay?
  3. A bread recipe calls for 2132\tfrac{1}{3} cups of flour for one batch. How much flour is needed for 2142\tfrac{1}{4} batches?
  4. A scuba tank loses 8.758.75 psi of pressure each minute. What is the change in pressure after 7.27.2 minutes?
  5. A submarine descends at a steady 12.512.5 ft per minute for 6.46.4 minutes. Write its change in elevation as a signed number.
  6. Application. A caterer has 101210\tfrac{1}{2} cups of chili and serves it in 1121\tfrac{1}{2}-cup portions. How many portions can be served, and how do you know none is left over?
  7. Reasoning. Explain why the quotient of two negative numbers is positive. Use the utility-overcharge situation from Example 3 or a situation of your own, not just the sign rule.

Exit ticket 4.2

  1. Find (6)(3.5)(-6)(-3.5).
  2. Find (34)(89)\left(-\tfrac{3}{4}\right)\left(\tfrac{8}{9}\right) in simplest form.
  3. Find 22.5÷4.5-22.5 \div 4.5.
  4. A quotient has exactly one negative number in it — either the dividend or the divisor, but not both. What is the sign of the quotient, and how do you know?

Lesson 4.3 — Estimating to Judge Whether an Answer Is Reasonable

Why estimate when you have a calculator

An estimate is an approximate answer found quickly with friendly numbers. Its purpose is not to replace the exact answer. Its purpose is to tell you, in advance, roughly where the exact answer must land — so that when the calculator returns something far away, you know a key was mistyped.

The two mistakes a calculator cannot catch for you are the two most common ones: a misplaced decimal point and a dropped negative sign. Both produce answers that are wildly wrong, and both are invisible unless you already know what to expect.

Three ways to estimate

Rounding. Round each number to a place that keeps one or two significant digits, then compute mentally. For 6.85×2.406.85 \times 2.40, round to 7×2.4=16.807 \times 2.4 = 16.80.

Compatible numbers. Change the numbers to ones that divide evenly. For 63.9÷7.163.9 \div 7.1, use 63÷7=963 \div 7 = 9. Compatible numbers are usually better than rounding for division, because rounding to the nearest ten often produces a division that is no easier than the original.

A low and a high estimate. Round both numbers down to get a value the answer must exceed, then round both up to get a value the answer must fall below. This gives a bracket — a range the exact answer is guaranteed to sit inside.

For 6.85×2.406.85 \times 2.40:

low: 6.5×2=13high: 7×2.5=17.5\text{low: } 6.5 \times 2 = 13 \qquad \text{high: } 7 \times 2.5 = 17.5

A number line showing the exact product 16.44 landing between a low estimate of 13 and a high estimate of 17.5

The exact product is 16.4416.44, which sits inside the bracket. A bracket is stronger than a single estimate because it converts "about right" into a claim you can actually test: any answer outside 1313 to 17.517.5 is definitely wrong.

Using an estimate to judge an answer

Once you have an estimate, judging takes one question: is the computed answer close to the estimate, and on the same side of zero?

Suppose a student reports 48.6÷0.6=8.148.6 \div 0.6 = 8.1. Estimate first. Dividing by 0.60.6 — a number smaller than 1 — must make the result bigger than 48.648.6, not smaller. A compatible-number estimate gives 48÷0.6=8048 \div 0.6 = 80. The reported answer is off by a factor of 10, which is the signature of a misplaced decimal point. The exact answer is 8181.

Dividing by a number less than 1 increases the result. This surprises people constantly. Ask how many 0.60.6s fit inside 48.648.6 — clearly many more than 48 of them would fit if the pieces were whole, so the count must be large.

Estimating with fractions

For fractions and mixed numbers, round to the nearest whole number, or to the nearest half when the fractions are small.

478+3112+211125+3+3=114\tfrac{7}{8} + 3\tfrac{1}{12} + 2\tfrac{11}{12} \approx 5 + 3 + 3 = 11

The exact sum, using a common denominator of 24, is 11724+7424+7024=26124=1078\tfrac{117}{24} + \tfrac{74}{24} + \tfrac{70}{24} = \tfrac{261}{24} = 10\tfrac{7}{8}. The estimate of 1111 was slightly high, which makes sense: two of the three numbers were rounded up.

Noticing which direction your estimate leans is part of the skill. If you rounded everything up, the true answer is below your estimate, and an answer above it is suspicious.

Worked examples

Example 1 — Estimate, then compute

Apples cost $2.40 per pound. Estimate the cost of 6.856.85 pounds, then find the exact cost.

Round 6.856.85 to 77.

7×2.40=16.807 \times 2.40 = 16.80

6.85×2.40=16.446.85 \times 2.40 = 16.44

The exact cost is a little under the estimate, as expected, since 6.856.85 was rounded up.

Answer: estimate $16.80; exact cost $16.44

Example 2 — Building a bracket

Give a low and a high estimate for 6.85×2.406.85 \times 2.40 and check that the exact answer falls inside.

Round both down, then both up.

low: 6.5×2=13high: 7×2.5=17.5\text{low: } 6.5 \times 2 = 13 \qquad \text{high: } 7 \times 2.5 = 17.5

Since 13<16.44<17.513 < 16.44 < 17.5, the exact answer lies inside the bracket.

Answer: the bracket is $13 to $17.50, and $16.44 falls inside it

Example 3 — Judging a reported answer

A student reports 9.7×4.2=40.749.7 \times 4.2 = 40.74. Is that reasonable?

Estimate with 10×4=4010 \times 4 = 40. The reported answer is very close to 40 and positive, as it should be.

9.7×4.2=40.749.7 \times 4.2 = 40.74

Answer: Reasonable, and in fact correct.

Example 4 — Catching a misplaced decimal point

A student reports 48.6÷0.6=8.148.6 \div 0.6 = 8.1. Judge the answer.

Dividing by a number less than 1 must produce a result larger than 48.648.6. A compatible estimate is 48÷0.6=8048 \div 0.6 = 80.

48.6÷0.6=8148.6 \div 0.6 = 81

The reported answer is one-tenth of the true value.

Answer: Unreasonable. The correct answer is 8181; the decimal point was misplaced.

Example 5 — Estimating a sum of mixed numbers

Estimate 478+3112+211124\tfrac{7}{8} + 3\tfrac{1}{12} + 2\tfrac{11}{12}, then find the exact sum.

Round each to the nearest whole number.

5+3+3=115 + 3 + 3 = 11

Now use a common denominator of 24.

11724+7424+7024=26124=878=1078\frac{117}{24} + \frac{74}{24} + \frac{70}{24} = \frac{261}{24} = \frac{87}{8} = 10\tfrac{7}{8}

Answer: estimate 1111; exact sum 107810\tfrac{7}{8}

Guided practice

  1. Estimate 8.9×3.18.9 \times 3.1 by rounding each factor to the nearest whole number, then compute the exact product.
  2. Estimate 19.6÷4.9-19.6 \div 4.9 using compatible numbers, then compute the exact quotient.
  3. Estimate 518+2785\tfrac{1}{8} + 2\tfrac{7}{8} by rounding each to the nearest whole number, then find the exact sum.
  4. A student reports 6.4×0.52=33.286.4 \times 0.52 = 33.28. Estimate the product and decide whether the report is reasonable. If it is not, give the correct answer.
  5. Give a low estimate and a high estimate for 3.7×4.63.7 \times 4.6, then compute the exact product and confirm it lands inside.

Independent practice

  1. For each, give an estimate and then the exact value. a) 12.3×4.812.3 \times 4.8 b) 44.8÷5.6-44.8 \div 5.6 c) 934+4189\tfrac{3}{4} + 4\tfrac{1}{8} d) 745×27\tfrac{4}{5} \times 2
  2. Build a bracket for 8.3×6.78.3 \times 6.7 by rounding both factors down and then both up. Compute the exact product and confirm it falls inside the bracket.
  3. Decide whether each reported answer is reasonable. Give a one-line estimate as your reason, and correct any that are wrong. a) 4.9×5.1=24.994.9 \times 5.1 = 24.99 b) 63.9÷7.1=9063.9 \div 7.1 = 90 c) 3.2×6.5=20.8-3.2 \times 6.5 = 20.8 d) 19.6+(4.85)=14.7519.6 + (-4.85) = 14.75
  4. Application. Gasoline costs $3.199 per gallon. Estimate the cost of 11.411.4 gallons, then compute the exact cost and round it to the nearest cent.
  5. Application. Five friends split a $97.35 bill equally. Estimate each share first, then compute it exactly. Explain how the estimate confirms your exact answer.
  6. Application. Four concert tickets cost $13.75 each, and parking costs $8.50. Use estimation to decide whether $60 is enough, then compute the exact total to confirm.
  7. Reasoning. Explain why rounding both numbers up always produces an estimate that is too high for a product of two positive numbers, and why a low-and-high pair is more useful than a single estimate.

Exit ticket 4.3

  1. Estimate 7.8×4.27.8 \times 4.2, then compute the exact product.
  2. A student reports 56.4÷7.05=8-56.4 \div 7.05 = 8. Is that reasonable? Give the correct answer.
  3. Give a low and a high estimate for 6.4×3.76.4 \times 3.7, then compute the exact product.
  4. Explain how an estimate can catch a misplaced decimal point that a calculator will not catch for you.

Lesson 4.4 — Multistep Problems in Context

A plan that works every time

A multistep problem requires more than one operation before you reach the answer. What makes them hard is not the arithmetic — a calculator handles that — but keeping track of what each number means and doing the steps in the right order.

Use the same four moves every time.

  1. Understand. Say in your own words what the question asks for, and name the unit of the answer: dollars, degrees, cups, feet.
  2. Estimate. Get a rough answer with friendly numbers before you compute anything.
  3. Solve. Do the steps in order, labeling each intermediate result with its unit and its meaning.
  4. Check. Compare with the estimate, and if you can, work backward from your answer to a number the problem gave you.

Step 4 is the one students skip and the one that catches the most errors.

Order matters

Consider a $78.60 dinner bill with a $12.60 coupon, split evenly among 3 people.

A bar model showing a total bill of 78.60 dollars, a 12.60 dollar coupon removed, and the remaining 66.00 dollars split into three shares of 22.00 dollars

Subtract the coupon first, then divide:

78.6012.60=66.0066.00÷3=22.0078.60 - 12.60 = 66.00 \qquad 66.00 \div 3 = 22.00

Dividing first and then subtracting would give a different — and wrong — answer, because it would take the whole $12.60 off each person's share instead of off the bill once. The bar model settles the question visually: the coupon is one piece of the whole bar, removed once, and only what remains gets divided into three equal parts.

When a problem involves an expression rather than a sequence of sentences, the order of operations decides for you. In 4.51.75×64.5 - 1.75 \times 6, the multiplication happens first:

4.510.5=64.5 - 10.5 = -6

Reading it as (4.51.75)×6(4.5 - 1.75) \times 6 would give 16.516.5, which is not just a different number — it answers a different question.

Rates over time

Many multistep problems combine a starting value with a rate applied over a period of time. The structure is almost always the same:

final value=starting value+(rate×time)\text{final value} = \text{starting value} + (\text{rate} \times \text{time})

The rate carries the sign. A temperature falling 1.751.75 degrees per hour for 6 hours, starting at 4.54.5°F:

4.5+(1.75)(6)=4.510.5=64.5 + (-1.75)(6) = 4.5 - 10.5 = -6

Writing the rate as a signed number, rather than remembering separately that it was a fall, is what keeps long chains from going wrong.

Worked examples

Example 1 — A bill, a coupon, and a split

A $78.60 dinner bill is reduced by a $12.60 coupon, and the rest is split evenly among 3 people. How much does each person pay?

Understand: the answer is in dollars per person. Estimate: about 66÷32266 \div 3 \approx 22.

Subtract the coupon from the whole bill first.

78.6012.60=66.0078.60 - 12.60 = 66.00

Then divide by 3.

66.00÷3=22.0066.00 \div 3 = 22.00

Check by working backward: 3×22.00+12.60=78.603 \times 22.00 + 12.60 = 78.60.

Answer: $22.00 each

Example 2 — A starting temperature and a falling rate

The temperature is 4.54.5°F and falls 1.751.75 degrees per hour for 6 hours. What is the temperature at the end?

Estimate: a fall of about 2×6=122 \times 6 = 12 degrees from about 5 lands near 7-7.

(1.75)(6)=10.5(-1.75)(6) = -10.5 4.5+(10.5)=64.5 + (-10.5) = -6

The exact answer, 6-6, is close to the estimate of 7-7 and on the same side of zero.

Answer: 6-6°F

Example 3 — Scaling a recipe and comparing to what you have

A recipe that serves 4 uses 2142\tfrac{1}{4} cups of flour. You need enough for 10 servings and you have 3123\tfrac{1}{2} cups. How much more flour do you need?

Scale by the factor 104=52\tfrac{10}{4} = \tfrac{5}{2}.

94×52=458=558 cups needed\frac{9}{4} \times \frac{5}{2} = \frac{45}{8} = 5\tfrac{5}{8} \text{ cups needed}

Subtract what you already have, written in eighths.

458288=178=218\frac{45}{8} - \frac{28}{8} = \frac{17}{8} = 2\tfrac{1}{8}

Answer: 2182\tfrac{1}{8} more cups

Example 4 — Repeated payments and a deposit

An account holds $212.40. Three automatic payments of $27.85 each post, then a $95.00 deposit arrives. What is the final balance?

Estimate: three payments of about $28 is about $84, so roughly 21284+95223212 - 84 + 95 \approx 223.

3×27.85=83.553 \times 27.85 = 83.55 212.4083.55=128.85212.40 - 83.55 = 128.85 128.85+95.00=223.85128.85 + 95.00 = 223.85

Answer: $223.85

Example 5 — Two rates in sequence

A drone hovers at 148.5148.5 ft. It descends at 12.7512.75 ft per second for 8 seconds, then rises at 6.56.5 ft per second for 4 seconds. What is its final height?

Compute each leg as rate times time, keeping signs.

(12.75)(8)=102(-12.75)(8) = -102 148.5102=46.5148.5 - 102 = 46.5 (6.5)(4)=26(6.5)(4) = 26 46.5+26=72.546.5 + 26 = 72.5

Answer: 72.572.5 ft

Guided practice

  1. A $44.80 bill is reduced by a $4.80 discount and split evenly among 4 people. Subtract first, then divide. How much does each person pay?
  2. The temperature is 3.5-3.5°C and rises 2.252.25°C per hour for 4 hours. Find the change first, then the final temperature.
  3. Cheese costs $6.40 per pound. What is the cost of 2342\tfrac{3}{4} pounds?
  4. A tank holds 20 gallons and loses 1.3751.375 gallons per hour for 6 hours. How much water remains?
  5. A 121212\tfrac{1}{2}-ft ribbon is cut into 58\tfrac{5}{8}-ft pieces. How many pieces are there?

Independent practice

  1. A phone plan costs $24.99 per month plus $0.045 for each extra minute. What is the bill in a month with 60 extra minutes?
  2. A hiker begins at an elevation of 2,150.52{,}150.5 ft and descends at 128.25128.25 ft per hour for 6 hours. What is her elevation at the end?
  3. Painting one room takes 1341\tfrac{3}{4} gallons of paint. You need to paint 3 rooms and you have 4124\tfrac{1}{2} gallons. How much more paint do you need?
  4. An account is overdrawn at $28.35-\$28.35. A $150.00 deposit arrives, and then four withdrawals of $22.50 each post. What is the final balance?
  5. Twenty shares of a stock are bought at $18.75 each. The price then falls $0.625 per day for 6 days. What is the new price per share, and what is the total loss on the 20 shares?
  6. Application. A class of 27 students goes on a field trip. Admission is $8.75 per student, and the bus costs $148.50, shared equally by the class. What does each student pay in total?
  7. Reasoning. For item 49, a student divided the $44.80 by 4 first and then subtracted the $4.80 discount from each share. Compute what that student would get, and explain in terms of the situation why the order matters.

Exit ticket 4.4

  1. A $56.40 bill is reduced by a $6.40 gift card and split evenly among 5 people. How much does each pay?
  2. The temperature is 2.52.5°F and falls 1.251.25°F per hour for 6 hours. What is the final temperature?
  3. A pot holds 8238\tfrac{2}{3} cups of soup, served in 23\tfrac{2}{3}-cup bowls. How many bowls can be filled?
  4. Describe the check you would use to confirm your answer to item 62 is reasonable.

Lesson 4.5 — Justifying a Solution

What a justification is

To justify a solution is to give someone else a reason to believe it — before they redo your arithmetic. "I used a calculator" is not a justification, because a calculator will produce a confident wrong answer just as fast as a right one.

A complete justification has three parts.

  1. An estimate that shows roughly where the answer had to land, including its sign.
  2. The operations you chose, and why each one matches something in the situation.
  3. An answer sentence with units that actually answers the question that was asked, plus a check when one is available.

That third part is easy to shortchange. The number 2222 is not an answer; "each person pays $22.00" is.

A worked justification

Problem. Three friends split a $47.25 bill after a $5.25 coupon. What does each pay?

Estimate. The bill is about $47 and the coupon about $5, leaving about $42. Split three ways, each share is about $14.

Operations. Subtract the coupon once, because it comes off the bill as a whole, not off each person. Then divide by 3, because the remainder is shared into 3 equal parts.

47.255.25=42.0042.00÷3=14.0047.25 - 5.25 = 42.00 \qquad 42.00 \div 3 = 14.00

Answer and check. Each friend pays $14.00. Working backward, 3×14.00+5.25=47.253 \times 14.00 + 5.25 = 47.25, which is the original bill.

The estimate, the reasoning, and the check each rule out a different kind of error: the estimate catches size and sign mistakes, the reasoning catches wrong-operation mistakes, and the check catches arithmetic slips.

Justifying why an answer must be negative

Sometimes the most important thing to justify is the sign. If a temperature of 1.51.5°F falls 2.52.5 degrees per hour for 3 hours, the total fall is 7.57.5 degrees — larger than the 1.51.5 degrees the temperature had above zero. So the result must be below zero before you compute anything:

1.57.5=61.5 - 7.5 = -6

An answer of 66°F would be arithmetically tidy and physically impossible. Reasoning about the sign in advance is what catches that.

Error analysis is justification in reverse

Finding someone else's mistake and naming it precisely is the same skill as justifying your own work. Consider 12.6+4.2×3-12.6 + 4.2 \times 3 evaluated as 25.2-25.2.

That student added first: 12.6+4.2=8.4-12.6 + 4.2 = -8.4, then multiplied by 3. But the order of operations requires multiplication first.

4.2×3=12.612.6+12.6=04.2 \times 3 = 12.6 \qquad -12.6 + 12.6 = 0

The correct value is 00. Notice the useful description is not "they got it wrong" but "they added before multiplying." Naming the specific move is what makes error analysis worth doing.

Worked examples

Example 1 — A complete justification

Three friends split a $47.25 bill after a $5.25 coupon. Justify the amount each pays.

Estimate: about $42÷3$14\$42 \div 3 \approx \$14. Subtract the coupon once from the whole bill, then divide by 3.

47.255.25=42.0047.25 - 5.25 = 42.00 42.00÷3=14.0042.00 \div 3 = 14.00

Check: 3×14.00+5.25=47.253 \times 14.00 + 5.25 = 47.25.

Answer: Each friend pays $14.00, confirmed by the estimate of $14 and by working backward to the original bill.

Example 2 — Justifying the choice of operation

A 6146\tfrac{1}{4}-pound bag of rice is repackaged into 58\tfrac{5}{8}-pound bags. Which operation applies, and why?

The question asks how many 58\tfrac58-pound portions fit inside 6146\tfrac14 pounds, which is a measuring question, so divide. Multiplying would answer a different question — the weight of 6146\tfrac14 portions.

254÷58=254×85=20020=10\frac{25}{4} \div \frac{5}{8} = \frac{25}{4} \times \frac{8}{5} = \frac{200}{20} = 10

Check: 10×58=508=61410 \times \tfrac58 = \tfrac{50}{8} = 6\tfrac14.

Answer: Division; there are 10 bags.

Example 3 — Error analysis with order of operations

A student evaluates 12.6+4.2×3-12.6 + 4.2 \times 3 and gets 25.2-25.2. Find and name the error.

The student added before multiplying. Multiplication comes first.

4.2×3=12.64.2 \times 3 = 12.6 12.6+12.6=0-12.6 + 12.6 = 0

Answer: The correct value is 00. The error was adding before multiplying.

Example 4 — Justifying with an estimate and a rounding instruction

A driver buys 14.614.6 gallons of gas at $3.125 per gallon. Justify the cost, rounded to the nearest cent.

Estimate: 15×3=4515 \times 3 = 45, so the cost is near $45.

14.6×3.125=45.62514.6 \times 3.125 = 45.625

Rounded to the nearest cent, that is $45.63.

Answer: $45.63, which matches the estimate of about $45.

Example 5 — Justifying the sign of a result

An account is overdrawn at $32.50-\$32.50. Four deposits of $12.75 each arrive. Justify whether the final balance is positive or negative, then find it.

Four deposits of about $13 total about $52, which is more than the $32.50 owed, so the balance must end positive.

4×12.75=51.004 \times 12.75 = 51.00 32.50+51.00=18.50-32.50 + 51.00 = 18.50

Answer: $18.50, positive as predicted

Guided practice

  1. Write a one-sentence estimate that justifies why 9.8×5.2=50.969.8 \times 5.2 = 50.96 is reasonable.
  2. A 6146\tfrac{1}{4}-pound bag of rice is repackaged into 58\tfrac{5}{8}-pound bags. Name the operation, explain why it is the right one, and find the number of bags.
  3. A student writes 5.6(2.4)=8.0-5.6 - (-2.4) = -8.0. Find the error, name it, and give the correct answer.
  4. The temperature is 1.51.5°F and falls 2.52.5°F per hour for 3 hours. Explain, before computing, why the answer must be negative. Then compute it.
  5. Five friends split $81.25 evenly. Write a justification with all three parts: estimate, operation with a reason, and an answer sentence.

Independent practice

  1. A student writes 23×(34)=112\tfrac{2}{3} \times \left(-\tfrac{3}{4}\right) = -\tfrac{1}{12}. Name the error and give the correct product.
  2. A student reports 18.6÷0.3=0.6218.6 \div 0.3 = 0.62. Use an estimate to show the answer is unreasonable, then give the correct quotient.
  3. Seven friends split a $103.60 bill after a $5.25 coupon. Write a complete justification: estimate, operations with reasons, computation, answer sentence, and check.
  4. Application. A pool loses 0.3750.375 inches of water per day to evaporation. Find the change in level after 12 days, and justify both the sign and the size of your answer.
  5. Application. A recipe uses 1131\tfrac{1}{3} cups of sugar for 8 servings. How much sugar is needed for 20 servings? Justify your scaling factor.
  6. Reasoning. Two students solve item 72 and get $14.05 and $14.50. Use estimation to decide which is right without redoing the division, and explain your reasoning.
  7. Reasoning. Explain why checking a solution by working backward is stronger evidence than saying "I used a calculator."

Exit ticket 4.5

  1. Write an estimate that justifies 6.1×3.9=23.79-6.1 \times 3.9 = -23.79 as reasonable, addressing both the size and the sign.
  2. A student writes 312÷12=1343\tfrac{1}{2} \div \tfrac{1}{2} = 1\tfrac{3}{4}. Name the error and give the correct quotient.
  3. Justify why four people splitting a $63.80 bill each pay $15.95. Include a check.
  4. Name the three parts of a complete justification.

Chapter 4 Review

Vocabulary. rational number · proper fraction · improper fraction · mixed number · thousandths place · common denominator · reciprocal · estimate · bracket · compatible numbers · multistep problem · justify

Part A — Adding and subtracting rational numbers (7.CE.1a)

  1. Evaluate. a) 14.75+6.5-14.75 + 6.5 b) 238156-2\tfrac{3}{8} - 1\tfrac{5}{6} c) 9.6(3.45)9.6 - (-3.45) d) 514+(712)5\tfrac{1}{4} + \left(-7\tfrac{1}{2}\right)
  2. An account balance is $52.80-\$52.80. A $140.00 deposit arrives, then a $36.45 withdrawal posts. What is the final balance?
  3. The temperature is 1.51.5°F. It falls 9.259.25 degrees, then rises 3.753.75 degrees. What is the final temperature?

Part B — Multiplying and dividing rational numbers (7.CE.1a)

  1. Evaluate. a) (8)(2.75)(-8)(2.75) b) (35)(56)\left(-\tfrac{3}{5}\right)\left(-\tfrac{5}{6}\right) c) 33.6÷(4.2)-33.6 \div (-4.2) d) 623÷(113)6\tfrac{2}{3} \div \left(-1\tfrac{1}{3}\right)
  2. A 9349\tfrac{3}{4}-ft rope is cut into 34\tfrac{3}{4}-ft pieces. How many pieces are there?
  3. A tank drains 2.1252.125 gallons per minute for 8 minutes. Write the change in volume as a signed number.

Part C — Estimating and judging reasonableness (7.CE.1a)

  1. Give an estimate and then the exact value. a) 11.8×5.111.8 \times 5.1 b) 71.4÷8.4-71.4 \div 8.4 c) 678+3186\tfrac{7}{8} + 3\tfrac{1}{8}
  2. Build a low-and-high bracket for 5.6×7.35.6 \times 7.3, then compute the exact product and confirm it falls inside.
  3. Which reported answers are unreasonable? Give an estimate as your reason and correct any that are wrong. a) 4.05×19.8=80.194.05 \times 19.8 = 80.19 b) 12.6÷0.3=4.212.6 \div 0.3 = 4.2 c) 7.5+2.25=9.75-7.5 + 2.25 = 9.75

Part D — Multistep problems in context (7.CE.1a)

  1. A $96.40 catering bill is reduced by a $14.40 coupon and split evenly among 4 people. How much does each pay?
  2. Twenty-four students take a field trip. Admission is $6.25 each, and the $114.00 bus fee is shared equally. What does each student pay in total?
  3. A soup recipe uses 3123\tfrac{1}{2} cups of stock for 6 servings. How much stock is needed for 15 servings?
  4. A drone at 96.596.5 ft descends at 14.2514.25 ft per second for 6 seconds, then rises 8.58.5 ft. What is its final height?

Part E — Mixed reasoning and justification (7.CE.1a)

  1. A student evaluates 18.4+6.2×2-18.4 + 6.2 \times 2 and gets 24.4-24.4. Name the error and give the correct value.
  2. Six friends split a $77.70 bill evenly. Write a complete justification: estimate, operation with a reason, computation, answer sentence, and check.
  3. Explain why estimating first is worth the time even when a calculator is allowed. Give one specific kind of error an estimate catches and a calculator does not.

Standards coverage check — Chapter 4

Knowledge and Skill Where it is taught Where it is practiced
7.CE.1a — estimate solutions to contextual problems with rational numbers 4.3; estimate step in 4.4 and 4.5 33–48; 54–60; 65, 69, 71, 72, 75, 77; Review 87–89, 95, 96
7.CE.1a — solve contextual problems using addition and subtraction of integers, fractions, mixed numbers, and decimals 4.1; chains of changes in 4.4 1–16; 49, 50, 52, 56, 57; Review 81–83, 90, 93
7.CE.1a — solve contextual problems using multiplication and division of integers, fractions, mixed numbers, and decimals 4.2; rate and scaling work in 4.4 17–32; 51, 53, 54, 55, 58, 59; Review 84–86, 91, 92
7.CE.1a — solve multistep contextual problems requiring more than one operation 4.4 49–64; 72, 73, 74; Review 90–93, 95
7.CE.1a — justify solutions, including the operations chosen and the meaning of the answer 4.5; check step in 4.4 12, 28, 44, 48, 60, 64; 65–80; Review 94–96
7.CE.1a — work within the stated bounds: fractions positive or negative; decimals positive or negative, to the thousandths place 4.1 opening; 4.2; 4.4 throughout; thousandths appear in 10, 25, 41, 52, 54, 58, 73, 86

Answer keys for every set in this chapter are in Appendix A.