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Virginia SOL Mathematics Textbook

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Chapter 7 — Exponents, Perfect Squares, and Powers of Ten

Standard: 6.NS.3 — The student will recognize and represent patterns with whole number exponents and perfect squares.

By the end of this chapter you will be able to:

Lessons: 7.1 Exponents and Repeated Multiplication · 7.2 Patterns with Bases and Exponents · 7.3 Perfect Squares · 7.4 Powers of Ten and Place Value


Lesson 7.1 — Exponents and Repeated Multiplication

A shorter way to write repeated multiplication

Multiplication is a shortcut for repeated addition: 5+5+5+55 + 5 + 5 + 5 is 4×54 \times 5. Exponents do the same job for repeated multiplication. Instead of writing 3×3×3×33 \times 3 \times 3 \times 3, write 343^4.

In 343^4, the base is the number being multiplied and the exponent is how many times the base is used as a factor. The whole expression is called a power.

Three to the fourth power labeled with its base and exponent, expanded as four factors of 3 equal to 81

34=3×3×3×3=813^4 = 3 \times 3 \times 3 \times 3 = 81

Writing 343^4 is exponential form. Writing 3×3×3×33 \times 3 \times 3 \times 3 is expanded form. Writing 8181 is the value of the power.

How to read powers

Power Read as Expanded form Value
232^3 two to the third power, or two cubed 2×2×22 \times 2 \times 2 88
525^2 five to the second power, or five squared 5×55 \times 5 2525
747^4 seven to the fourth power 7×7×7×77 \times 7 \times 7 \times 7 2,4012{,}401
10110^1 ten to the first power 1010 1010

An exponent of 22 is read squared and an exponent of 33 is read cubed. Those two names come from geometry: 525^2 is the number of unit squares in a 55-by-55 square, and 232^3 is the number of unit cubes in a 22-by-22-by-22 cube.

A 5 by 5 array of 25 unit squares beside a 2 by 2 by 2 cube of 8 unit cubes

The exponent is not a multiplier. 343^4 means 3×3×3×3=813 \times 3 \times 3 \times 3 = 81, not 3×4=123 \times 4 = 12. This is the single most common error with exponents.

Order matters

Swapping the base and the exponent usually changes the value:

43=4×4×4=6434=3×3×3×3=814^3 = 4 \times 4 \times 4 = 64 \qquad 3^4 = 3 \times 3 \times 3 \times 3 = 81

Two special cases are worth knowing. A base of 11 always gives 11, because multiplying 11 by itself any number of times stays 11. An exponent of 11 always gives the base itself, because the base is used exactly once.

18=181=81^8 = 1 \qquad 8^1 = 8

Worked examples

Example 1 — Exponential form

Write 6×6×66 \times 6 \times 6 using an exponent, then find its value.

The base is 66 and it appears as a factor 33 times, so the exponent is 33.

63=6×6×66^3 = 6 \times 6 \times 6

Multiply left to right: 6×6=366 \times 6 = 36, then 36×6=21636 \times 6 = 216.

Answer: 63=2166^3 = 216

Example 2 — Expanded form

Write 262^6 in expanded form and find its value.

26=2×2×2×2×2×22^6 = 2 \times 2 \times 2 \times 2 \times 2 \times 2

Multiply in pairs: 2×2=42 \times 2 = 4, 4×2=84 \times 2 = 8, 8×2=168 \times 2 = 16, 16×2=3216 \times 2 = 32, 32×2=6432 \times 2 = 64.

Answer: 6464

Example 3 — Comparing two powers with the same digits

Evaluate 434^3 and 343^4, then compare them.

43=4×4×4=6434=3×3×3×3=814^3 = 4 \times 4 \times 4 = 64 \qquad 3^4 = 3 \times 3 \times 3 \times 3 = 81

Since 81>6481 > 64:

Answer: 34>433^4 > 4^3

Example 4 — Squares and cubes

Evaluate 525^2 and 252^5.

52=5×5=2525=2×2×2×2×2=325^2 = 5 \times 5 = 25 \qquad 2^5 = 2 \times 2 \times 2 \times 2 \times 2 = 32

Answer: 2525 and 3232; the larger exponent wins here even though the base is smaller.

Example 5 — A power in context

Each time a sheet of paper is folded, the number of layers doubles. Starting from 1 layer, how many layers are there after 7 folds?

Each fold multiplies the layer count by 22, and there are 77 folds, so the number of layers is 272^7.

27=2×2×2×2×2×2×2=1282^7 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 128

Answer: 128128 layers

Guided practice

  1. Write 9×99 \times 9 using an exponent and find its value.
  2. Write 353^5 in expanded form and find its value.
  3. Evaluate 10310^3.
  4. Evaluate 181^8 and 818^1.
  5. Which is greater, 242^4 or 424^2? Show both values.

Independent practice

  1. Evaluate: a) 232^3 b) 535^3 c) 727^2 d) 12212^2
  2. Write in exponential form: a) 4×4×4×4×44 \times 4 \times 4 \times 4 \times 4 b) 11×1111 \times 11
  3. Write 646^4 in expanded form and find its value.
  4. Fill in <<, >>, or ==: 33    423^3 \ \underline{\ \ } \ 4^2
  5. Order from least to greatest: 252^5, 333^3, 525^2, 424^2.
  6. Application. A single bacterium doubles every hour. Starting with 1 bacterium, write the count after 6 hours as a power of 2 and find its value.
  7. Reasoning. Explain why 343^4 and 434^3 are not equal, using the meaning of base and exponent.

Exit ticket 7.1

  1. Evaluate 434^3.
  2. Write 8×8×88 \times 8 \times 8 using an exponent.
  3. Which is greater, 525^2 or 252^5?
  4. In 737^3, name the base and the exponent, and explain what each one tells you.

Lesson 7.2 — Patterns with Bases and Exponents

Building a power table

Listing the powers of a base in order reveals a pattern you can use to extend the list without starting over.

Exponent 2n2^n 3n3^n 4n4^n 5n5^n
11 22 33 44 55
22 44 99 1616 2525
33 88 2727 6464 125125
44 1616 8181 256256 625625
55 3232 243243
66 6464

Staircase of bars for the powers of two from 2 to 64, with times-two and divide-by-two arrows

Two rules come straight out of the table:

  1. Moving up one exponent multiplies by the base. Since 26=642^6 = 64, you get 27=64×2=1282^7 = 64 \times 2 = 128.
  2. Moving down one exponent divides by the base. Since 53=1255^3 = 125, you get 52=125÷5=255^2 = 125 \div 5 = 25.

Continuing rule 2 past an exponent of 11 gives a useful result. Because 51=55^1 = 5, the next step down is 5÷5=15 \div 5 = 1, so 50=15^0 = 1. The same reasoning works for any base other than zero.

Patterns in the ones digit

The ones digits of powers repeat in short cycles, which makes them easy to predict.

Base Ones digits of the first several powers Cycle
22 2,4,8,6,2,4,8,6,2, 4, 8, 6, 2, 4, 8, 6, \ldots length 4
44 4,6,4,6,4, 6, 4, 6, \ldots length 2
55 5,5,5,5, 5, 5, \ldots length 1
66 6,6,6,6, 6, 6, \ldots length 1
99 9,1,9,1,9, 1, 9, 1, \ldots length 2

Powers of 55 always end in 55 because any number ending in 55, multiplied by 55, ends in 55 again. Powers of 66 behave the same way.

Which powers are also perfect squares

Look down the column for 2n2^n: 44, 1616, 6464, and 256256 are all squares of whole numbers (222^2, 424^2, 828^2, 16216^2). Those are exactly the entries with even exponents. This connection sets up the next lesson.

Worked examples

Example 1 — Extending a power table

Complete the powers of 3 from 313^1 to 353^5 and describe the pattern.

31=3,32=9,33=27,34=81,35=2433^1 = 3, \quad 3^2 = 9, \quad 3^3 = 27, \quad 3^4 = 81, \quad 3^5 = 243

Each value is the one before it multiplied by 33: 9=3×39 = 3 \times 3, 27=9×327 = 9 \times 3, 81=27×381 = 27 \times 3, 243=81×3243 = 81 \times 3.

Answer: 33, 99, 2727, 8181, 243243; multiply by 3 to move to the next power.

Example 2 — Using the pattern instead of restarting

Given 26=642^6 = 64, find 272^7 and 282^8.

Multiply by the base each time.

27=64×2=12828=128×2=2562^7 = 64 \times 2 = 128 \qquad 2^8 = 128 \times 2 = 256

Answer: 128128 and 256256

Example 3 — Predicting a ones digit

What is the ones digit of 454^5?

The ones digits of 41,42,43,444^1, 4^2, 4^3, 4^4 are 4,6,4,64, 6, 4, 6, alternating. Odd exponents end in 44 and even exponents end in 66. Since 55 is odd, 454^5 ends in 44.

Checking: 45=1,0244^5 = 1{,}024.

Answer: 44

Example 4 — Extending a pattern downward

Use the powers of 5 to explain the value of 505^0.

53=125,52=125÷5=25,51=25÷5=5,50=5÷5=15^3 = 125, \quad 5^2 = 125 \div 5 = 25, \quad 5^1 = 25 \div 5 = 5, \quad 5^0 = 5 \div 5 = 1

Answer: 50=15^0 = 1, because each step down the table divides by the base.

Example 5 — Comparing two powers

Which is greater, 353^5 or 535^3?

35=24353=1253^5 = 243 \qquad 5^3 = 125

Answer: 353^5 is greater. A larger exponent can matter more than a larger base.

Guided practice

  1. Complete: 41=  4^1 = \underline{\ \ }, 42=  4^2 = \underline{\ \ }, 43=  4^3 = \underline{\ \ }, 44=  4^4 = \underline{\ \ }.
  2. Describe the rule that takes you from 212^1 to 222^2 to 232^3, and use it to find 262^6.
  3. Given 34=813^4 = 81, find 353^5 without expanding.
  4. What is the ones digit of 646^4?
  5. Given 103=1,00010^3 = 1{,}000, explain how to get 10210^2 from it.

Independent practice

  1. Complete the powers of 5 from 515^1 to 545^4.
  2. Given 28=2562^8 = 256, find 292^9 and 272^7.
  3. List the ones digits of 212^1 through 282^8, then predict the ones digit of 2122^{12}.
  4. Which is larger, 353^5 or 535^3? Show both values.
  5. Continue the pattern downward: 43=644^3 = 64, 42=  4^2 = \underline{\ \ }, 41=  4^1 = \underline{\ \ }, 40=  4^0 = \underline{\ \ }.
  6. Application. A single-elimination tournament starts with 64 teams, and each round cuts the field in half. Write 64 as a power of 2, and use the exponent to say how many rounds are played until one team remains.
  7. Reasoning. Explain why every power of 5 ends in the digit 5.

Exit ticket 7.2

  1. Complete: 31=  3^1 = \underline{\ \ }, 32=  3^2 = \underline{\ \ }, 33=  3^3 = \underline{\ \ }, 34=  3^4 = \underline{\ \ }.
  2. Given 210=1,0242^{10} = 1{,}024, find 2112^{11}.
  3. What is the ones digit of 939^3?
  4. Describe the rule that moves from one power of a base to the next power up.

Lesson 7.3 — Perfect Squares

Squares you can see

A perfect square is a whole number that can be written as a whole number multiplied by itself. The name comes from the picture: a perfect square is exactly the number of unit squares needed to build a square array with the same number of rows as columns.

Square arrays of unit squares for the first five perfect squares: 1, 4, 9, 16, and 25

A square array has equal rows and columns. If you can arrange a number of tiles into a square array with no tiles left over, the number is a perfect square, and the number of tiles along one side is the number that was squared.

The perfect squares from 1 to 400

nn 11 22 33 44 55 66 77 88 99 1010
n2n^2 11 44 99 1616 2525 3636 4949 6464 8181 100100
nn 1111 1212 1313 1414 1515 1616 1717 1818 1919 2020
n2n^2 121121 144144 169169 196196 225225 256256 289289 324324 361361 400400

Knowing this list by sight is worth the effort. It makes the justification work in this lesson quick.

The growth pattern

Look at the gaps between consecutive perfect squares:

1, 4, 9, 16, 25, 36,1, \ 4, \ 9, \ 16, \ 25, \ 36, \ldots gaps: 3, 5, 7, 9, 11,\text{gaps: } 3, \ 5, \ 7, \ 9, \ 11, \ldots

The gaps are the consecutive odd numbers. The model shows why: to grow a square array from 44-by-44 to 55-by-55, you add a new column of 4, a new row of 4, and one corner tile, which is 4+4+1=94 + 4 + 1 = 9.

A 5 by 5 grid shaded in L-shaped layers showing each perfect square grows by the next odd number

Justifying whether a number is a perfect square

To justify that a number is a perfect square, name the whole number that squares to it: 144144 is a perfect square because 12×12=14412 \times 12 = 144, so 144 tiles form a 12-by-12 array.

To justify that a number is not a perfect square, trap it between two consecutive perfect squares: 150150 lies between 144=122144 = 12^2 and 169=132169 = 13^2. Since there is no whole number between 12 and 13, no whole number squared gives 150.

Trapping is the whole argument. Saying "I tried some numbers and none worked" is not a justification. Naming the two consecutive squares on either side is, because it rules out every whole number at once.

Worked examples

Example 1 — Building the first perfect squares

Use square arrays to find the first four perfect squares.

A 11-by-11 array uses 1 tile. A 22-by-22 array uses 4. A 33-by-33 array uses 9. A 44-by-44 array uses 16.

Answer: 11, 44, 99, 1616

Example 2 — Justifying that a number is a perfect square

Is 144144 a perfect square? Justify your answer.

Test whole numbers near the size of the answer. 102=10010^2 = 100 is too small and 132=16913^2 = 169 is too large, so try 1212: 12×12=14412 \times 12 = 144.

Answer: Yes. 144=122144 = 12^2, so 144 tiles form a 12-by-12 square array.

Example 3 — Justifying that a number is not a perfect square

Is 150150 a perfect square? Justify your answer.

Find the consecutive perfect squares on either side: 122=14412^2 = 144 and 132=16913^2 = 169. Since 144<150<169144 < 150 < 169, any whole number squaring to 150 would have to be between 12 and 13.

Answer: No. There is no whole number between 12 and 13, so 150 is not a perfect square.

Example 4 — Using the odd-number pattern

The perfect square after 2525 is 3636. Show that the gap fits the odd-number pattern.

3625=1136 - 25 = 11

The gaps so far are 3,5,7,9,113, 5, 7, 9, 11 — consecutive odd numbers. Growing a 55-by-55 array into a 66-by-66 array adds a row of 5, a column of 5, and 1 corner tile: 5+5+1=115 + 5 + 1 = 11.

Answer: The gap is 1111, the next odd number, and the model explains it as 5+5+15 + 5 + 1.

Example 5 — Finding perfect squares in a range

List every perfect square between 200 and 300.

Work from the table: 142=19614^2 = 196 is below 200. Then 152=22515^2 = 225, 162=25616^2 = 256, and 172=28917^2 = 289 all fall in the range, and 182=32418^2 = 324 is above 300.

Answer: 225225, 256256, 289289

Guided practice

  1. List the first five perfect squares.
  2. Is 4949 a perfect square? Justify your answer.
  3. Is 6060 a perfect square? Justify your answer.
  4. Find 13213^2.
  5. Describe the square array that models 3636, including its side length.

Independent practice

  1. Evaluate: a) 828^2 b) 15215^2 c) 19219^2 d) 20220^2
  2. Which of these are perfect squares: 8181, 9090, 100100, 110110, 121121?
  3. Justify whether 324324 is a perfect square.
  4. Justify whether 250250 is a perfect square.
  5. List every perfect square between 100 and 200.
  6. Application. A square patio is built from 169 square tiles with none left over. How many tiles run along one side, and how many tiles form the border around the outside edge?
  7. Reasoning. Explain, using two consecutive perfect squares, why 200 cannot be a perfect square.

Exit ticket 7.3

  1. Find 16216^2.
  2. Is 196196 a perfect square? Justify your answer.
  3. Is 300300 a perfect square? Justify your answer.
  4. Explain how a square array shows whether a number is a perfect square.

Lesson 7.4 — Powers of Ten and Place Value

The pattern in the place-value chart

Our number system is built on tens. Each place is worth 10 times the place to its right, so every place value is a power of 10.

Place-value chart from ones to millions with each place written as a power of ten

Power Expanded form Value Number of zeros
10010^0 11 00
10110^1 1010 1010 11
10210^2 10×1010 \times 10 100100 22
10310^3 10×10×1010 \times 10 \times 10 1,0001{,}000 33
10410^4 10×10×10×1010 \times 10 \times 10 \times 10 10,00010{,}000 44
10510^5 10×10×10×10×1010 \times 10 \times 10 \times 10 \times 10 100,000100{,}000 55
10610^6 10×10×10×10×10×1010 \times 10 \times 10 \times 10 \times 10 \times 10 1,000,0001{,}000{,}000 66

The exponent equals the number of zeros. That happens because each extra factor of 10 shifts every digit one place to the left and drops a new zero into the ones place.

Reading the table downward multiplies by 10 each time; reading it upward divides by 10 each time. Dividing 1010 by 1010 gives 11, which is why 100=110^0 = 1 and why the ones place fits the pattern.

Expanded form with powers of ten

Every whole number can be written as a sum of digits times powers of ten. For 3,5073{,}507:

3,507=3×103+5×102+0×101+7×1003{,}507 = 3 \times 10^3 + 5 \times 10^2 + 0 \times 10^1 + 7 \times 10^0

Check it: 3,000+500+0+7=3,5073{,}000 + 500 + 0 + 7 = 3{,}507. Include the zero terms while you are learning the form — they keep each digit lined up with its place.

Multiplying by a power of ten

Multiplying by 10n10^n shifts every digit nn places to the left, which looks like writing nn zeros after the number:

27×103=27,0006×102=60027 \times 10^3 = 27{,}000 \qquad 6 \times 10^2 = 600

Worked examples

Example 1 — Evaluating a power of ten

Find 10510^5.

The exponent 5 means five factors of 10, so the value has five zeros.

105=10×10×10×10×10=100,00010^5 = 10 \times 10 \times 10 \times 10 \times 10 = 100{,}000

Answer: 100,000100{,}000

Example 2 — Writing a number as a power of ten

Write 1,000,0001{,}000{,}000 as a power of ten.

Count the zeros: there are six.

Answer: 10610^6

Example 3 — Expanded form with powers of ten

Write 4,0624{,}062 in expanded form using powers of ten.

The digits are 4 thousands, 0 hundreds, 6 tens, and 2 ones.

4,062=4×103+0×102+6×101+2×1004{,}062 = 4 \times 10^3 + 0 \times 10^2 + 6 \times 10^1 + 2 \times 10^0

Check: 4,000+0+60+2=4,0624{,}000 + 0 + 60 + 2 = 4{,}062.

Answer: 4×103+0×102+6×101+2×1004 \times 10^3 + 0 \times 10^2 + 6 \times 10^1 + 2 \times 10^0

Example 4 — Multiplying by a power of ten

Find 27×10327 \times 10^3.

103=1,00010^3 = 1{,}000, and multiplying by 1,000 shifts each digit three places left.

Answer: 27,00027{,}000

Example 5 — Reading the pattern downward

Use the pattern in the powers of ten to explain why 100=110^0 = 1.

103=1,000,102=1,000÷10=100,101=100÷10=10,100=10÷10=110^3 = 1{,}000, \quad 10^2 = 1{,}000 \div 10 = 100, \quad 10^1 = 100 \div 10 = 10, \quad 10^0 = 10 \div 10 = 1

Answer: Each step down divides by 10, and 10÷10=110 \div 10 = 1, so 100=110^0 = 1 continues the pattern.

Guided practice

  1. Evaluate 10410^4.
  2. Write 100,000100{,}000 as a power of ten.
  3. How many zeros are in 10710^7, and what is its value?
  4. Find 6×1026 \times 10^2.
  5. Write 512512 in expanded form using powers of ten.

Independent practice

  1. Evaluate: a) 10210^2 b) 10510^5 c) 10010^0 d) 10610^6
  2. Write as a power of ten: a) 1,0001{,}000 b) 10,000,00010{,}000{,}000
  3. Write 8,3048{,}304 in expanded form using powers of ten.
  4. Compute: a) 45×10445 \times 10^4 b) 7×1067 \times 10^6
  5. Which is greater, 10410^4 or 4104^{10}? Show both values.
  6. Application. A stadium seats 5×1045 \times 10^4 people. Write that in standard form, and compare it to 10510^5.
  7. Reasoning. Explain why the exponent on a power of 10 tells you the number of zeros in its standard form.

Exit ticket 7.4

  1. Evaluate 10310^3.
  2. Write 1,000,0001{,}000{,}000 as a power of ten.
  3. Write 2,7502{,}750 in expanded form using powers of ten.
  4. Explain how the place-value chart shows that each place is 10 times the place to its right.

Chapter 7 Review

Vocabulary. base · exponent · power · exponential form · expanded form · squared · cubed · perfect square · square array · power of 10

Part A — Patterns with bases and exponents (6.NS.3a)

  1. Evaluate: a) 262^6 b) 343^4 c) 535^3
  2. Write 7×7×7×77 \times 7 \times 7 \times 7 as a power and find its value.
  3. Given 27=1282^7 = 128, find 282^8 without expanding.
  4. Order from least to greatest: 333^3, 252^5, 424^2, 525^2.

Part B — Perfect squares with models (6.NS.3b)

  1. List every perfect square from 1 to 100.
  2. A square array uses 144 tiles. How many tiles are along one side?
  3. Find the gap between 1616 and 2525, and explain how the square-array model produces that gap.

Part C — Justifying perfect squares (6.NS.3c)

  1. Justify whether 289289 is a perfect square.
  2. Justify whether 130130 is a perfect square.
  3. List every perfect square between 300 and 400.

Part D — Powers of ten and place value (6.NS.3d)

  1. Evaluate 10410^4 and 10010^0.
  2. Write 3,2063{,}206 in expanded form using powers of ten.
  3. Compute 62×10362 \times 10^3.

Part E — Mixed application and reasoning

  1. Which is greater, 636^3 or 363^6? Show both values.
  2. A square garden has an area of 225 square feet. Find the side length and the perimeter.
  3. Is every power of 10 a perfect square? Justify your answer with examples.

Standards coverage check — Chapter 7

Knowledge and Skill Where it is taught Where it is practiced
6.NS.3a — recognize and represent patterns with bases and exponents that are whole numbers 7.1, 7.2 7.1 all sets; 7.2 all sets; Review Parts A, E
6.NS.3b — recognize and represent patterns of perfect squares using concrete and pictorial models 7.2, 7.3 7.2 independent practice; 7.3 all sets; Review Part B
6.NS.3c — justify if a number between 0 and 400 is a perfect square through modeling or mathematical reasoning 7.3 7.3 all sets; Review Parts C, E
6.NS.3d — recognize and represent powers of 10 with whole number exponents by examining patterns in place value 7.4 7.4 all sets; Review Parts D, E

Answer keys for every set in this chapter are in Appendix A.