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Virginia SOL Mathematics Textbook

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Chapter 14 — Circles: Arc Length and Sector Area

Standard: G.PC.3 (a, d, e)

G.PC.3 — verbatim. The student will solve problems, including those in context, by applying properties of circles. Students will demonstrate the following Knowledge and Skills: a) Determine the proportional relationship between the arc length or area of a sector and other parts of a circle. b) Solve for arc measures and angles in a circle formed by central angles. c) Solve for arc measures and angles in a circle involving inscribed angles. d) Calculate the length of an arc of a circle. e) Calculate the area of a sector of a circle.

By the end of this chapter you will be able to:

Lessons: 14.1 The Fraction of a Circle · 14.2 Arc Length · 14.3 Sector Area · 14.4 Putting It Together

Why this chapter matters. Chapter 13 measured arcs in degrees. Degrees answer how far round the circle you have gone, and they say nothing at all about how far you have walked. This chapter gives an arc a length, and gives the region between two radii an area. Both come from one number — the fraction n360\frac{n}{360} — applied to two different totals.

Scope note. This chapter is G.PC.3 a, d, and e. The two angle rules — central and inscribed — are Chapter 13, and you will need them, because you cannot find a fraction of a circle until you know the central angle.

There is nothing new to memorise beyond one fraction. Virginia's Geometry End-of-Course test supplies a formula sheet with C=2πrC = 2\pi r and A=πr2A = \pi r^2 on it. What the sheet cannot do is tell you which one the question is asking about. That decision is the assessed skill.

Conventions this chapter fixes.

  • Arc measure is in degrees. Arc length is in the units of the radius. They are different quantities with different units, and the same arc has both.
  • Exact before approximate. 4π4\pi is the answer; 12.5712.57 is the answer rounded. Give the answer in terms of π\pi first, then, if the question asks for a decimal, round to the nearest hundredth and write about.
  • Reduce the fraction first. 72360\frac{72}{360} is 15\frac{1}{5}, and one fifth of a circumference is easier to compute — and far easier to check — than seventy-two three-hundred-sixtieths of one.
  • An area is in square units. A sector area reported in plain centimetres has lost track of what it measures.
  • nn always means the central angle in degrees, and rr always means the radius.
  • Item numbering runs straight through the chapter, from 1 in Lesson 14.1 to 112 at the end of Lesson 14.4.

Lesson 14.1 — The Fraction of a Circle

Measure is not length

Two circles of radius 3 and radius 6, each with a 60 degree arc marked, showing equal measures and unequal lengths

Two circles. Both arcs measure 60°60°. The arcs are not the same size.

small circle large circle
radius 33 66
arc measure 60°60° 60°60°
arc length π\pi 2π2\pi

Measure answers how far round the circle. It is a share of a full turn, so it does not care how big the circle is.

Length answers how far along the arc. It is a distance, in the same units as the radius, and it grows with the circle.

The most common error in this standard is answering "the arc is 6060" when 6060 is the measure and the length is π\pi. Before writing anything, decide which of the two the question wants — and check your units at the end.

The fraction

A circle with a 90 degree sector shaded, labelled as one quarter of the circle

A central angle of n° opens onto

n360\frac{n}{360}

of the circle. That single fraction is the whole of G.PC.3a, and everything else in this chapter is that fraction applied to something:

A 90°90° angle opens onto 90360=14\frac{90}{360} = \frac{1}{4} of the circle. So its arc is a quarter of the way round, and its sector is a quarter of the inside.

Reduce first

A table of central angles from 30 to 240 degrees with each fraction of the circle reduced to lowest terms

angle fraction lowest terms
30°30° 30360\tfrac{30}{360} 112\tfrac{1}{12}
45°45° 45360\tfrac{45}{360} 18\tfrac{1}{8}
60°60° 60360\tfrac{60}{360} 16\tfrac{1}{6}
72°72° 72360\tfrac{72}{360} 15\tfrac{1}{5}
90°90° 90360\tfrac{90}{360} 14\tfrac{1}{4}
120°120° 120360\tfrac{120}{360} 13\tfrac{1}{3}
180°180° 180360\tfrac{180}{360} 12\tfrac{1}{2}
240°240° 240360\tfrac{240}{360} 23\tfrac{2}{3}

Reducing is not tidiness. "One fifth of the circle" is a sentence you can check against a picture; "seventy-two three-hundred-sixtieths of the circle" is not.

A sector, and what it is not

A sector is the region bounded by two radii and the arc between them — the pizza slice, cheese included.

An arc is only the curved edge — the crust, with no cheese.

The same nn and the same rr give you both. Which one you are being asked for is a question about the words, not about the arithmetic.

Worked examples

Example 1 — The fraction

Give the fraction of the circle opened onto by a 40°40° central angle.

Answer: 40360=19\frac{40}{360} = \frac{1}{9}.

Example 2 — Reducing

Give the fraction for 135°135°.

Answer: 135360=38\frac{135}{360} = \frac{3}{8}.

Example 3 — Backwards

A sector is 16\frac{1}{6} of its circle. Give the central angle.

Answer: 16\frac{1}{6} of 360=60°360 = 60°.

Example 4 — Measure or length?

Circle PP has radius 44 and circle QQ has radius 4040. Each has an arc of measure 50°50°. Compare the measures, then the lengths.

Answer: The measures are equal — both 50°50°. The lengths are not: circle QQ's arc is ten times as long, because its radius is ten times as big.

Example 5 — Naming the region

A slice of pie is cut from the centre. Name the region, and name its curved edge.

Answer: The region is a sector; its curved edge is an arc.

Guided practice

  1. Use the two-circle figure. Give the arc measure in each circle.
  2. On that figure, give the arc length in each circle, and say why they differ.
  3. On that figure, say what would happen to both numbers if the radius were tripled.
  4. Use the fraction figure. Give the central angle and the fraction it opens onto.
  5. On that figure, say what that fraction is a fraction of, for an arc and for a sector.
  6. Use the fraction table. Give the reduced fraction for 72°72° and say what it means in words.

Independent practice

Give each fraction in lowest terms.

  1. 60°60°
  2. 90°90°
  3. 120°120°
  4. 45°45°
  5. 30°30°
  6. 180°180°
  7. 240°240°
  8. 270°270°
  9. 80°80°
  10. 100°100°

Give the central angle.

  1. A sector is 14\frac{1}{4} of its circle.

  2. A sector is 13\frac{1}{3} of its circle.

  3. A sector is 25\frac{2}{5} of its circle.

  4. A sector is 56\frac{5}{6} of its circle.

  5. Name the region bounded by two radii and the arc between them.

  6. Name the curved edge of that region on its own.

  7. Circle AA has radius 22 and circle BB has radius 1818. Each has a 70°70° arc. Compare the two arc measures.

  8. Application. A circular running track is marked into 88 equal lanes' worth of arc by radial lines. Give the fraction of the track in one section, and its central angle.

  9. Error analysis. A student is asked for the length of a 50°50° arc and answers "5050." Say what they gave instead, and what else they needed to know to answer the question asked.

  10. Reasoning. Explain why two arcs can have equal measure and unequal length, but two arcs in the same circle with equal measure must have equal length.

Exit ticket 14.1

  1. Give the fraction of a circle opened onto by a 150°150° central angle, in lowest terms.
  2. State, in one sentence each, what arc measure tells you and what arc length tells you.

Lesson 14.2 — Arc Length

Where the formula comes from

A whole circle labelled with circumference 18 pi beside the same circle with a 40 degree sector, arc length 2 pi

All the way round a circle is the circumference:

C=2πrC = 2\pi r

An arc of n° is n360\frac{n}{360} of the way round. So it is that fraction of the circumference:

Arc length L=n360×2πrL = \frac{n}{360} \times 2\pi r

This is not a second formula to learn. It is the circumference, cut down by the fraction from Lesson 14.1.

A worked one, with the units watched

A circle of radius 9 centimetres with a 40 degree arc from A to B, worked through to an arc length of 2 pi centimetres

Radius 99 cm, central angle 40°40°.

40360=19C=2π(9)=18π cm\frac{40}{360} = \frac{1}{9} \qquad C = 2\pi(9) = 18\pi \text{ cm}

L=19×18π=2π cm6.28 cmL = \frac{1}{9} \times 18\pi = 2\pi \text{ cm} \approx 6.28 \text{ cm}

The units are centimetres — the same units as the radius, because a length is a length. The measure of that arc is 40°40°, which is not a number of centimetres at all.

The same angle in different circles

A table of four circles of radius 3, 6, 9, and 12 showing each 60 degree arc as one sixth of its own circumference

radius circumference length of a 60°60° arc
33 6π6\pi π\pi
66 12π12\pi 2π2\pi
99 18π18\pi 3π3\pi
1212 24π24\pi 4π4\pi

Every row is 16\frac{1}{6} of its own circumference. The measure is 60°60° in all four. The length triples when the radius triples: arc length is proportional to the radius.

That is exactly why the measure alone can never tell you a length. You need rr as well.

Going backwards

The formula has three letters in it. Given any two, you can find the third — write the formula, substitute, and solve.

π\pi cancels every time, which is the practical reason to keep answers in terms of π\pi until the last step.

Worked examples

Example 1 — Straight ahead

Radius 1212, central angle 60°60°. Give the arc length.

Answer: 60360=16\frac{60}{360} = \frac{1}{6}, and C=24πC = 24\pi, so L=16(24π)=4πL = \frac{1}{6}(24\pi) = 4\pi.

Example 2 — As a decimal

Give the answer to Example 1 to the nearest hundredth.

Answer: 4π12.574\pi \approx 12.57.

Example 3 — A semicircle

Radius 1414, central angle 180°180°. Give the arc length.

Answer: 180360=12\frac{180}{360} = \frac{1}{2} and C=28πC = 28\pi, so L=14πL = 14\pi.

Example 4 — Find the angle

An arc of a circle of radius 1818 has length 10π10\pi. Give the central angle.

Answer: n360(36π)=10πn10=10n=100°\frac{n}{360}(36\pi) = 10\pi \Rightarrow \frac{n}{10} = 10 \Rightarrow n = 100°.

Example 5 — Find the radius

A 45°45° arc has length 2π2\pi. Give the radius.

Answer: 18(2πr)=2ππr4=2πr=8\frac{1}{8}(2\pi r) = 2\pi \Rightarrow \frac{\pi r}{4} = 2\pi \Rightarrow r = 8.

Guided practice

  1. Use the derivation figure. Give the circumference of the whole circle.
  2. On that figure, give the fraction and the arc length, and say how the two are connected.
  3. Use the worked figure. Give the units of the arc length, and say why they are those units.
  4. On that figure, say what the number 4040 measures, and in what units.
  5. Use the four-circle table. Give the arc length when the radius is 99.
  6. On that table, say what happens to the arc length when the radius is doubled.

Independent practice

Give the arc length in terms of π\pi.

  1. r=10r = 10, n=90°n = 90°
  2. r=6r = 6, n=120°n = 120°
  3. r=15r = 15, n=72°n = 72°
  4. r=8r = 8, n=45°n = 45°
  5. r=24r = 24, n=30°n = 30°
  6. r=20r = 20, n=54°n = 54°
  7. r=21r = 21, n=120°n = 120°
  8. r=5r = 5, n=216°n = 216°

Give the arc length to the nearest hundredth.

  1. r=9r = 9, n=40°n = 40°
  2. r=12r = 12, n=60°n = 60°
  3. r=10r = 10, n=90°n = 90°

Find the missing quantity.

  1. A circle of radius 1212 has an arc of length 4π4\pi. Give the central angle.
  2. A circle of radius 1010 has an arc of length 5π5\pi. Give the central angle.
  3. A circle of radius 2424 has an arc of length 4π4\pi. Give the central angle.
  4. A 60°60° arc has length 4π4\pi. Give the radius.
  5. A 120°120° arc has length 4π4\pi. Give the radius.
  6. A 72°72° arc has length 6π6\pi. Give the radius.
  7. Application. A circular garden path has radius 3030 feet. A section of it is bounded by a 144°144° central angle. Give the length of that section in terms of π\pi, then to the nearest hundredth.
  8. Error analysis. A student calculates a 90°90° arc in a circle of radius 88 as 90360×π(8)2=16π\frac{90}{360} \times \pi(8)^2 = 16\pi. Identify the mistake and give the correct arc length.
  9. Reasoning. Two arcs have the same length. Explain why their measures need not be equal, and give a pair of examples that shows it.

Exit ticket 14.2

  1. Give the length of a 120°120° arc in a circle of radius 66, in terms of π\pi.
  2. A 30°30° arc has length 4π4\pi. Give the radius.

Lesson 14.3 — Sector Area

Where this formula comes from

A whole circle of radius 12 with area 144 pi beside the same circle with a 60 degree sector of area 24 pi

The whole circle has area

A=πr2A = \pi r^2

A sector of n° is n360\frac{n}{360} of the circle. So it is that fraction of the area:

Sector area Asector=n360×πr2A_{\text{sector}} = \frac{n}{360} \times \pi r^2

Same fraction as the arc. Different total.

A worked one

A circle of radius 12 inches with a 60 degree sector POQ worked through to an area of 24 pi square inches

Radius 1212 in, central angle 60°60°.

60360=16A=π(12)2=144π in2\frac{60}{360} = \frac{1}{6} \qquad A = \pi(12)^2 = 144\pi \text{ in}^2

Asector=16×144π=24π in275.40 in2A_{\text{sector}} = \frac{1}{6} \times 144\pi = 24\pi \text{ in}^2 \approx 75.40 \text{ in}^2

Square inches. The radius is squared in the formula, and the units are squared with it.

The check that always works

Put n=360n = 360 into either formula. You should get the whole circle back:

360360×2πr=2πr360360×πr2=πr2\frac{360}{360} \times 2\pi r = 2\pi r \qquad \frac{360}{360} \times \pi r^2 = \pi r^2

If a sector answer comes out bigger than πr2\pi r^2, it is wrong, and you can see that without knowing the right answer.

Going backwards

Given the sector area and one of nn or rr, solve for the other. Finding rr needs a square root at the end, because the formula squares it.

Worked examples

Example 1 — Straight ahead

Radius 1010, central angle 90°90°. Give the sector area.

Answer: 14×100π=25π\frac{1}{4} \times 100\pi = 25\pi.

Example 2 — A third

Radius 66, central angle 120°120°. Give the sector area.

Answer: 13×36π=12π\frac{1}{3} \times 36\pi = 12\pi.

Example 3 — As a decimal

Give the answer to Example 2 to the nearest hundredth.

Answer: 12π37.7012\pi \approx 37.70.

Example 4 — Find the angle

A sector of a circle of radius 1515 has area 45π45\pi. Give the central angle.

Answer: π(15)2=225π\pi(15)^2 = 225\pi, and 45π225π=15\frac{45\pi}{225\pi} = \frac{1}{5}, so n=15(360)=72°n = \frac{1}{5}(360) = 72°.

Example 5 — Find the radius

A 90°90° sector has area 36π36\pi. Give the radius.

Answer: 14πr2=36ππr2=144πr2=144r=12\frac{1}{4}\pi r^2 = 36\pi \Rightarrow \pi r^2 = 144\pi \Rightarrow r^2 = 144 \Rightarrow r = 12.

Guided practice

  1. Use the derivation figure. Give the area of the whole circle.
  2. On that figure, give the fraction and the sector area, and say how they are connected.
  3. Use the worked figure. Give the units of the sector area, and say why they are squared.
  4. On that figure, say which quantity gets squared in the formula and which does not.
  5. State the check that a sector area can never fail.
  6. Say what is different between the arc length formula and the sector area formula, and what is the same.

Independent practice

Give the sector area in terms of π\pi.

  1. r=12r = 12, n=60°n = 60°
  2. r=10r = 10, n=90°n = 90°
  3. r=9r = 9, n=40°n = 40°
  4. r=6r = 6, n=120°n = 120°
  5. r=15r = 15, n=72°n = 72°
  6. r=8r = 8, n=45°n = 45°
  7. r=24r = 24, n=30°n = 30°
  8. r=20r = 20, n=54°n = 54°
  9. r=14r = 14, n=180°n = 180°
  10. r=21r = 21, n=120°n = 120°

Give the sector area to the nearest hundredth.

  1. r=10r = 10, n=90°n = 90°
  2. r=6r = 6, n=120°n = 120°

Find the missing quantity.

  1. A circle of radius 1212 has a sector of area 24π24\pi. Give the central angle.
  2. A circle of radius 99 has a sector of area 9π9\pi. Give the central angle.
  3. A circle of radius 2424 has a sector of area 48π48\pi. Give the central angle.
  4. A 60°60° sector has area 24π24\pi. Give the radius.
  5. A 120°120° sector has area 48π48\pi. Give the radius.
  6. Application. A lawn sprinkler on a post sprays water 1515 feet and sweeps through 72°72°. Give the area it waters in terms of π\pi, then to the nearest hundredth.
  7. Error analysis. A student finds the area of a 45°45° sector of a circle of radius 88 as 45360×2π(8)=2π\frac{45}{360} \times 2\pi(8) = 2\pi. Identify the mistake and give the correct sector area. Say which unit would have caught it.
  8. Reasoning. A sector's central angle is doubled and its radius is left alone. Say what happens to its area, and explain why the answer is not "it is squared."

Exit ticket 14.3

  1. Give the area of a 45°45° sector of a circle of radius 88, in terms of π\pi.
  2. A 90°90° sector has area 25π25\pi. Give the radius.

Lesson 14.4 — Putting It Together

One figure, two answers

One 90 degree sector of a circle of radius 10 metres, labelled with an arc of 5 pi metres and a sector area of 25 pi square metres

One sector. One fraction. Two different questions:

the question the total the answer the units
how long is the curved edge? C=20πC = 20\pi 5π5\pi metres
how much region is inside? A=100πA = 100\pi 25π25\pi square metres

The fraction is 14\frac{1}{4} in both rows. Everything else follows from which total the question wanted.

The whole chapter on one page

A table giving arc measure, arc length, and sector area with their formulas and units

you want formula units
arc measure the central angle itself degrees
arc length n360×2πr\frac{n}{360} \times 2\pi r same as rr
sector area n360×πr2\frac{n}{360} \times \pi r^2 square units

Read the units off your answer and check them against the question. Metres where the question wanted square metres means you used the wrong row.

Both directions

Two circles showing an arc length used to recover the central angle and to recover the radius

Whichever letter is missing, the method is the same: write the formula, substitute what you know, solve.

n360(18π)=2πn=40°40360(2πr)=2πr=9\frac{n}{360}(18\pi) = 2\pi \Rightarrow n = 40° \qquad \frac{40}{360}(2\pi r) = 2\pi \Rightarrow r = 9

Changing the radius

Two circles of radius 6 and 12, each with a 90 degree sector, showing the arc doubling and the sector area quadrupling

Double the radius, keep the angle:

radius 66 radius 1212 factor
arc length 3π3\pi 6π6\pi ×2\times 2
sector area 9π9\pi 36π36\pi ×4\times 4

The arc doubles. The sector area is four times as big.

A length carries one factor of rr; an area carries two. You will meet this again in Chapter 17, where the same idea is applied to solids.

In context

Three panels: one slice of an eight-slice pizza, a minute hand sweeping 20 minutes, and a sprinkler covering a 72 degree sector

Every one is the same fraction of a circle. The word that decides the formula is the one naming what is being measured — a distance along the edge, or a region inside.

Worked examples

Example 1 — Which one?

"How much fence is needed for the curved side of a 60°60° garden bed of radius 99 m?" Name the quantity and give it.

Answer: An arc length: 16(18π)=3π\frac{1}{6}(18\pi) = 3\pi m.

Example 2 — Which one?

"How much turf is needed for that garden bed?" Name the quantity and give it.

Answer: A sector area: 16(81π)=27π2\frac{1}{6}(81\pi) = \frac{27\pi}{2} m².

Example 3 — Both

A 90°90° sector has radius 1010. Give the arc length and the sector area.

Answer: Arc 14(20π)=5π\frac{1}{4}(20\pi) = 5\pi; sector 14(100π)=25π\frac{1}{4}(100\pi) = 25\pi.

Example 4 — Perimeter of a sector

Give the distance all the way round the sector in Example 3.

Answer: The boundary is two radii plus the arc: 10+10+5π=20+5π10 + 10 + 5\pi = 20 + 5\pi. Not 5π5\pi — an arc is only part of the boundary.

Example 5 — Scaling

A sector's radius is multiplied by 33 and its angle is unchanged. Give the factor for its arc length and for its area.

Answer: Arc ×3\times 3; area ×9\times 9.

Guided practice

  1. Use the one-sector figure. Give the arc length and the sector area, with units.
  2. On that figure, say which of the two answers a question about fencing would want.
  3. Use the formula board. Say what tells you which row you are on.
  4. Use the backwards figure. Give the equation you would write to find the radius.
  5. Use the doubling figure. Give the factor for the arc and the factor for the area.
  6. Use the context figure. Say which of the three quantities is an area, and how you know.

Independent practice

For each, name the quantity — arc length or sector area — and give it in terms of π\pi.

  1. The curved edge of a 90°90° sector of radius 1212.

  2. The region inside a 90°90° sector of radius 1212.

  3. The curved edge of a 30°30° sector of radius 2424.

  4. The region inside a 30°30° sector of radius 2424.

  5. The curved edge of a 72°72° sector of radius 1515.

  6. The region inside a 72°72° sector of radius 1515.

  7. A 60°60° sector has radius 1212. Give its arc length and its sector area.

  8. A 120°120° sector has radius 66. Give its arc length and its sector area.

  9. Give the perimeter of a 60°60° sector of radius 1212, in terms of π\pi.

  10. Give the perimeter of a 90°90° sector of radius 1010, in terms of π\pi.

  11. A sector's radius is doubled, angle unchanged. Give the factor for its arc length.

  12. A sector's radius is doubled, angle unchanged. Give the factor for its area.

  13. A sector's angle is doubled, radius unchanged. Give the factor for its arc length and for its area.

  14. A sector's radius is halved, angle unchanged. Give the factor for its area.

  15. Application. A pizza of radius 88 in is cut into 88 equal slices. Give the crust length of one slice and the area of one slice, both in terms of π\pi.

  16. Application. A minute hand is 1212 cm long. Give the distance its tip travels in 2020 minutes, in terms of π\pi.

  17. Application. A sprinkler reaches 1515 ft and sweeps 72°72°. Give the watered area in terms of π\pi, then to the nearest hundredth.

  18. Error analysis. A student is asked for the perimeter of a 90°90° sector of radius 1010 and answers 5π5\pi. Say what they gave, and give the perimeter.

  19. Reasoning. Explain why the units alone are enough to tell you whether an answer belongs to arc length or to sector area.

  20. Reasoning. Explain why doubling the radius does not double the sector area, using the formula rather than the picture.

Exit ticket 14.4

  1. A 120°120° sector has radius 2121. Give its arc length and its sector area, in terms of π\pi.
  2. Give the one question to ask before choosing between the two formulas.

Chapter 14 Review

Vocabulary. circumference · area of a circle · arc measure · arc length · sector · sector area · central angle · proportional · exact form · perimeter of a sector

Review 1 (G.PC.3a). A circle has radius 1818, and a central angle of 100°100° is drawn.

Review 2 (G.PC.3d). A circle of radius 2020 has an arc of length 6π6\pi.

Review 3 (G.PC.3 d, e). A 120°120° sector is cut from a circle of radius 66.


Standards coverage check — Chapter 14

Knowledge and Skill Where it is taught Where it is practiced Where it is applied in context
G.PC.3a — determine the proportional relationship between the arc length or area of a sector and other parts of a circle 14.1 (measure against length; the fraction n360\tfrac{n}{360}; reducing); 14.2 (arc length proportional to rr); 14.4 (changing the radius) 1–23, 25, 26; 33, 34, 54; 101–104, 109, 110 24; 52; 105–107; Review 1, Review 2
G.PC.3d — calculate the length of an arc of a circle 14.2 (the formula, its derivation, and both reverse directions); 14.4 (choosing between the two) 29–51, 53–56; 85–89, 91, 93, 95, 97–100, 108 52; 105, 106; Review 2, Review 3
G.PC.3e — calculate the area of a sector of a circle 14.3 (the formula, its derivation, the n=360n = 360 check, and both reverse directions); 14.4 (choosing between the two) 57–79, 81–84; 90, 92, 94, 96–98 80; 107; Review 1, Review 3

Supporting items: 26, 54, 82, 109, and 110 are the reasoning items. Item 109 carries the chapter's organising claim — that the units of an answer identify which quantity it is, so a unit check catches the chapter's central error without knowing the right answer. The error analyses target the recurring failures: reporting a measure when a length was asked for (25), using πr2\pi r^2 inside the arc length formula (53), using 2πr2\pi r inside the sector area formula (81), and mistaking an arc for the whole boundary of a sector (108).

Boundaries respected. This chapter teaches the proportional relationship (a), arc length (d), and sector area (e), and relies on the central angle work of Chapter 13 without re-teaching it. Radians do not appear — every angle in this volume is in degrees, as Chapter 13 fixed. The area of a circular segment — the region between a chord and its arc — is not named anywhere in G.PC.3 and is not taught here; every region in this chapter is bounded by two radii and an arc. Answers are exact in terms of π\pi first, with decimals given only where a question asks for one.

Answer keys for every item in this chapter are in Appendix A.