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Virginia SOL Mathematics Textbook

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Chapter 12 — Angles of Convex Polygons

Standard: G.PC.2 (a, b, c)

G.PC.2 — verbatim. The student will verify relationships and solve problems involving the number of sides and measures of angles of convex polygons. Students will demonstrate the following Knowledge and Skills: a) Solve problems involving the number of sides of a regular polygon given the measures of the interior and exterior angles of the polygon. b) Justify the relationship between the sum of the measures of the interior and exterior angles of a convex polygon and solve problems involving the sum of the measures of the angles. c) Justify the relationship between the measure of each interior and exterior angle of a regular polygon and solve problems involving the measures of the angles.

By the end of this chapter you will be able to:

Lessons: 12.1 Convex Polygons and the Interior Angle Sum · 12.2 Exterior Angles · 12.3 Regular Polygons, One Angle at a Time · 12.4 Working Backwards to nn

Why this chapter matters. The standard says justify twice, and that is the whole point. Both of this chapter's relationships have a one-picture reason — cut the polygon into triangles, or walk once around its boundary — and a student who has those two pictures can rebuild both formulas from scratch. A student who has only memorised (n2)180(n-2)180 has one formula and no way to check it.

Two formulas, and they are not interchangeable.

  • The interior sum (n2)180°(n-2)180° and the exterior sum 360°360° hold for every convex polygon, regular or not.
  • Each interior angle (n2)180°n\dfrac{(n-2)180°}{n} and each exterior angle 360°n\dfrac{360°}{n} need the polygon to be regular — otherwise there is no single "each."

Reading a value out of the wrong row is the most common error in this chapter, and Lesson 12.3 exists to keep the two apart.

Conventions this chapter fixes.

  • Convex only. Every result here assumes every interior angle is less than 180°180°. A figure with a vertex pushed inward is outside the chapter, and Lesson 12.1 shows one so you know what is being excluded.
  • Regular means all sides congruent and all angles congruent. Equal angles alone is not regular — a non-square rectangle has four equal angles.
  • One interior and one exterior angle at the same vertex are supplementary. They sit on a straight line, so they total 180°180°. This is the hinge that converts every question in the chapter into every other.
  • nn must be a whole number. A regular polygon has a whole number of sides, so an angle that produces a fraction describes no polygon. Lesson 12.4 drills this.
  • Exterior angle means one per vertex — the angle between a side and the extension of the side next to it. There are two such angles at each vertex and they are congruent, so "the" exterior angle is unambiguous.
  • Item numbering runs straight through the chapter, from 1 in Lesson 12.1 to 112 at the end of Lesson 12.4.

Lesson 12.1 — Convex Polygons and the Interior Angle Sum

What convex rules out

A convex pentagon beside a non-convex hexagon whose inward vertex is marked 270 degrees

A polygon is convex when every interior angle is less than 180°180° — equivalently, when no vertex is pushed inward. The figure on the right has a vertex of 270°270°, so it is not convex, and nothing in this chapter applies to it.

A quicker test: in a convex polygon, every diagonal stays inside the figure. In the right-hand figure, a diagonal across the notch leaves it.

The justification: cut it into triangles

A convex heptagon with every diagonal drawn from one vertex, splitting it into five numbered triangles

Pick one vertex and draw every diagonal from it. In a 77-gon you get 5 triangles — and the triangles' angles are exactly the polygon's angles, with nothing added and nothing left over.

Each triangle contributes 180°180°, so:

5×180°=900°5 \times 180° = 900°

Count the triangles in general: from one vertex you can reach every vertex except itself and its two neighbours, so you draw n3n-3 diagonals, which cut the polygon into n2n-2 triangles.

Interior angle sum. For any convex polygon with nn sides, sum of interior angles=(n2)180°\text{sum of interior angles} = (n-2) \cdot 180°

This is a justification, not a formula to trust. If you forget the formula, draw the polygon, cut it from one vertex, and count.

The sum depends on nn alone

A table of n, number of triangles, and interior angle sum from triangle to dodecagon

Sides nn Triangles Sum
3 1 180°180°
4 2 360°360°
5 3 540°540°
6 4 720°720°
8 6 1080°1080°
10 8 1440°1440°
12 10 1800°1800°

Two things worth noticing. The sum grows by exactly 180°180° each time a side is added, because each new side adds one triangle. And nothing here mentions regular — a lopsided hexagon and a perfect one both total 720°720°.

Finding a missing angle

If you know all but one angle, subtract from the sum.

Angles given with algebra

A convex quadrilateral with angles labelled x, 2x, 3x, and 4x, and the equation solved beneath

The sum is the equation. A quadrilateral totals 360°360°, so:

x+2x+3x+4x=360°    10x=360°    x=36°x + 2x + 3x + 4x = 360° \;\Rightarrow\; 10x = 360° \;\Rightarrow\; x = 36°

giving 36°36°, 72°72°, 108°108°, and 144°144°. Notice the labels are not drawn to scale — the arithmetic settles the answer, not the picture.

Worked examples

Example 1 — A sum

Find the interior angle sum of a convex decagon.

Answer: (102)180°=8×180°=1440°(10-2)180° = 8 \times 180° = 1440°.

Example 2 — A missing angle

Four angles of a convex pentagon are 100°100°, 120°120°, 95°95°, and 130°130°. Find the fifth.

Answer: The sum is 540°540°, and 100+120+95+130=445100 + 120 + 95 + 130 = 445, so the fifth is 540445=95°540 - 445 = 95°.

Example 3 — Backwards to nn

A convex polygon's interior angles total 1800°1800°. How many sides?

Answer: (n2)180=1800n2=10n=12(n-2)180 = 1800 \Rightarrow n - 2 = 10 \Rightarrow n = 12.

Example 4 — With algebra

The angles of a convex quadrilateral are in the ratio 3:4:5:63:4:5:6. Find them.

Answer: 3x+4x+5x+6x=36018x=360x=203x + 4x + 5x + 6x = 360 \Rightarrow 18x = 360 \Rightarrow x = 20, so the angles are 60°60°, 80°80°, 100°100°, and 120°120°.

Example 5 — Not convex

Does (n2)180°(n-2)180° apply to a figure with a 250°250° vertex?

Answer: Not in this course. The relationship is stated for convex polygons, and a 250°250° angle means the figure is not convex.

Guided practice

  1. Use the convex figure. Give the definition of convex in your own words.
  2. On that figure, give the measure of the marked angle on the right and say what it proves.
  3. Use the triangle-cut figure. How many triangles, and from how many diagonals?
  4. On that figure, give the sum and the arithmetic that produced it.
  5. Explain why the triangles' angles are exactly the polygon's angles, with nothing left over.
  6. Use the sum table. By how much does the sum grow when one side is added, and why?

Independent practice

Find the interior angle sum.

  1. A convex quadrilateral.
  2. A convex hexagon.
  3. A convex nonagon (99 sides).
  4. A convex 1515-gon.
  5. A convex 2020-gon.

Find the number of sides.

  1. The interior angles total 900°900°.
  2. The interior angles total 1260°1260°.
  3. The interior angles total 2340°2340°.
  4. The interior angles total 3240°3240°.

Find the missing angle.

  1. Four angles of a convex pentagon are 100°100°, 120°120°, 95°95°, and 130°130°.
  2. Three angles of a convex quadrilateral are 85°85°, 95°95°, and 100°100°.
  3. Five angles of a convex hexagon are 110°110°, 130°130°, 120°120°, 140°140°, and 100°100°.
  4. Six angles of a convex heptagon are 120°120°, 130°130°, 140°140°, 125°125°, 135°135°, and 110°110°.

With algebra.

  1. The angles of a convex quadrilateral are in the ratio 3:4:5:63:4:5:6. Find all four.
  2. The angles of a convex quadrilateral are in the ratio 2:3:4:62:3:4:6. Find all four.
  3. Application. A garden bed is a convex hexagon. A landscaper measures five of its corners as 115°115°, 125°125°, 130°130°, 105°105°, and 120°120°. Give the sixth, and say how you know without measuring it.
  4. Error analysis. A student computes the interior angle sum of a hexagon as 6×180°=1080°6 \times 180° = 1080°. Identify the error and give the correct sum.
  5. Reasoning. Explain why the interior angle sum does not depend on whether the polygon is regular.

Exit ticket 12.1

  1. Give the interior angle sum of a convex octagon.
  2. A convex polygon's angles total 1440°1440°. How many sides?
  3. Three angles of a convex quadrilateral are 70°70°, 110°110°, and 95°95°. Find the fourth.
  4. In one sentence, justify (n2)180°(n-2)180° without stating the formula.

Lesson 12.2 — Exterior Angles

What an exterior angle is

A regular pentagon with one interior angle and one exterior angle marked, and the side extended with a dashed ray

An exterior angle sits between one side and the extension of the side next to it — that is what the dashed ray is for.

Because a side and its own extension form a straight line:

At every vertex, the interior angle and the exterior angle are supplementary. interior+exterior=180°\text{interior} + \text{exterior} = 180°

That single fact converts every interior question in this chapter into an exterior one, and back. It is the most useful line in the chapter.

The justification: walk around once

A hexagon with all six exterior angles marked, beside the same six angles stacked at one point to fill a circle

Imagine walking around the boundary. At each corner you turn — and the amount you turn is exactly the exterior angle. Walk the whole way around and you finish facing the direction you started, having made one complete turn.

Exterior angle sum. For any convex polygon, sum of exterior angles=360°\text{sum of exterior angles} = 360°

Notice what is not in that statement: nn. A triangle's three exterior angles total 360°360°; a 2020-gon's twenty exterior angles total 360°360°. More angles, each smaller, same total.

It really does not need regularity

An irregular convex pentagon with all five interior angles measured and both totals computed

Not one of that pentagon's five angles equals another, and the totals still come out at 540°540° and 360°360°. Neither relationship needs the polygon to be regular. That word only matters when you want one angle, which is the next lesson.

Worked examples

Example 1 — Supplementary

An interior angle of a convex polygon is 115°115°. Give the exterior angle at that vertex.

Answer: 180115=65°180 - 115 = 65°.

Example 2 — The sum

Give the sum of the exterior angles of a convex 1717-gon.

Answer: 360°360°. The number of sides does not enter.

Example 3 — A missing exterior angle

Four exterior angles of a convex pentagon are 80°80°, 65°65°, 70°70°, and 75°75°. Find the fifth.

Answer: 80+65+70+75=29080 + 65 + 70 + 75 = 290, so the fifth is 360290=70°360 - 290 = 70°.

Example 4 — Both directions

A convex polygon has an exterior angle of 40°40° at one vertex. Give the interior angle there.

Answer: 18040=140°180 - 40 = 140°.

Example 5 — Why 360

Justify the exterior angle sum in one sentence.

Answer: Walking once around the boundary turns you through each exterior angle exactly once and returns you to your starting direction, which is one full turn of 360°360°.

Guided practice

  1. Use the exterior-angle figure. Say what the dashed ray is, and why it is needed.
  2. On that figure, give the two angle measures and their sum.
  3. Explain why an interior and an exterior angle at the same vertex are always supplementary.
  4. Use the walking figure. Say what you turn through at each corner.
  5. On that figure, say why one trip around the boundary is 360°360°.
  6. Use the irregular pentagon. Give its two totals, and say what the figure is there to prove.

Independent practice

  1. Give the exterior angle sum of a convex triangle.
  2. Give the exterior angle sum of a convex 1212-gon.
  3. Give the exterior angle sum of a convex 3030-gon.
  4. An interior angle is 115°115°. Give the exterior angle at that vertex.
  5. An interior angle is 140°140°. Give the exterior angle at that vertex.
  6. An exterior angle is 40°40°. Give the interior angle at that vertex.
  7. An exterior angle is 24°24°. Give the interior angle at that vertex.
  8. Four exterior angles of a convex pentagon are 80°80°, 65°65°, 70°70°, and 75°75°. Find the fifth.
  9. Five exterior angles of a convex hexagon are 70°70°, 55°55°, 60°60°, 65°65°, and 50°50°. Find the sixth.
  10. Three exterior angles of a convex quadrilateral are 95°95°, 85°85°, and 100°100°. Find the fourth.
  11. A convex polygon has 99 sides. Give the sum of its exterior angles and the sum of its interior angles.
  12. A convex polygon's interior angles total 1080°1080°. Give the sum of its exterior angles.
  13. Application. A robot drives once around a convex flower bed and returns to its starting point facing its starting direction. Give the total of all the turns it made, and say why it does not depend on the number of corners.
  14. Application. A convex quadrilateral gate has interior angles 95°95°, 85°85°, 100°100°, and 80°80°. Give all four exterior angles and check their total.
  15. Error analysis. A student writes "a hexagon has 66 sides, so its exterior angles total 6×60°=360°6 \times 60° = 360°; a pentagon has 55, so its exterior angles total 5×60°=300°5 \times 60° = 300°." Identify the error.
  16. Error analysis. A student says the exterior angles of an irregular pentagon cannot total 360°360° because the angles are all different. Correct them.
  17. Reasoning. Explain why adding a side to a convex polygon increases the interior sum but leaves the exterior sum unchanged.
  18. Reasoning. Explain why the exterior angle sum being 360°360° means the interior angles of an nn-gon must total 180n360180n - 360, and check that this matches (n2)180(n-2)180.

Exit ticket 12.2

  1. Give the exterior angle sum of any convex polygon.
  2. An interior angle is 128°128°. Give the exterior angle at that vertex.
  3. Five exterior angles of a convex hexagon are 60°60°, 70°70°, 50°50°, 80°80°, and 45°45°. Find the sixth.
  4. Justify the 360°360° in one sentence.

Lesson 12.3 — Regular Polygons, One Angle at a Time

Divide, but only when it is regular

A regular pentagon with all five interior angles marked 108 degrees and one exterior angle marked 72

In a regular polygon all the interior angles are equal, so each one is the sum divided by nn:

Each angle of a regular nn-gon. each interior=(n2)180°neach exterior=360°n\text{each interior} = \frac{(n-2) \cdot 180°}{n} \qquad \text{each exterior} = \frac{360°}{n}

For a regular pentagon: 540°÷5=108°540° \div 5 = 108° and 360°÷5=72°360° \div 5 = 72°. The two check against each other — 108+72=180108 + 72 = 180, exactly as a supplementary pair at any vertex must.

The exterior formula is the easier one. 360÷n360 \div n needs no sum computed first, and the interior angle is then one subtraction away.

As nn grows

Regular hexagon, octagon, and decagon side by side with each interior and exterior angle given

interior exterior
regular hexagon 120°120° 60°60°
regular octagon 135°135° 45°45°
regular decagon 144°144° 36°36°

The interior angle grows toward 180°180° and the exterior shrinks toward 0° — the polygon is flattening out toward a circle. The two always add to 180°180°, and the exterior angles always total 360°360°, however large nn gets.

The reference table, and the trap in it

A table of n, interior sum, each interior angle, and each exterior angle

nn interior sum each interior each exterior
3 180°180° 60°60° 120°120°
4 360°360° 90°90° 90°90°
5 540°540° 108°108° 72°72°
6 720°720° 120°120° 60°60°
8 1080°1080° 135°135° 45°45°
10 1440°1440° 144°144° 36°36°
12 1800°1800° 150°150° 30°30°

Column two applies to every convex polygon. Columns three and four apply only to regular ones. An irregular hexagon has an interior sum of 720°720° — but it has no single "each interior angle" at all, so the question has no answer for it.

Why hexagons tile and pentagons do not

A regular octagon marked 135 degrees beside three regular hexagons meeting at a point

Shapes meeting around a point must fill exactly 360°360°. Three regular hexagons do it: 3×120°=360°3 \times 120° = 360°. Regular pentagons cannot — 360÷108360 \div 108 is not a whole number, so no number of them closes the gap.

Worked examples

Example 1 — Each interior

Give each interior angle of a regular octagon.

Answer: (82)180°8=1080°8=135°\dfrac{(8-2)180°}{8} = \dfrac{1080°}{8} = 135°.

Example 2 — Each exterior, the fast way

Give each exterior angle of a regular 1212-gon.

Answer: 360°÷12=30°360° \div 12 = 30°.

Example 3 — Interior from exterior

Give each interior angle of that regular 1212-gon.

Answer: 18030=150°180 - 30 = 150°.

Example 4 — Not regular

An irregular hexagon has an interior sum of 720°720°. What is each interior angle?

Answer: The question has no answer. Without equal angles there is no single "each" — only the total is determined.

Example 5 — Tiling

Can regular octagons tile a floor by themselves?

Answer: No. Each interior angle is 135°135°, and 360÷135=83360 \div 135 = \tfrac83, not a whole number, so they cannot meet exactly around a point.

Guided practice

  1. Use the regular pentagon figure. Give each interior angle and the arithmetic.
  2. On that figure, give each exterior angle and the arithmetic.
  3. On that figure, check the two against each other and say what the check confirms.
  4. Use the three-polygon figure. Say what happens to each angle as nn grows, and why.
  5. Use the reference table. Which columns need the polygon to be regular, and which do not?
  6. Use the tiling figure. Explain why three hexagons close and pentagons do not.

Independent practice

Give each interior angle of a regular polygon with:

  1. 66 sides.
  2. 99 sides.
  3. 1010 sides.
  4. 1515 sides.
  5. 2020 sides.

Give each exterior angle of a regular polygon with:

  1. 88 sides.

  2. 1212 sides.

  3. 1818 sides.

  4. 2424 sides.

  5. 3636 sides.

  6. A regular polygon has each exterior angle 45°45°. Give each interior angle.

  7. A regular polygon has each interior angle 160°160°. Give each exterior angle.

  8. Give the interior sum and each interior angle of a regular 1212-gon.

  9. An irregular octagon has an interior sum of 1080°1080°. Give each interior angle, or say why you cannot.

  10. Application. A stop sign is a regular octagon. Give the measure of one of its corners, and give the angle a saw must be set to if it cuts along the extension of one edge.

  11. Application. A tiler wants a floor of identical regular polygons with no gaps. Show that squares work and that regular pentagons do not.

  12. Error analysis. A student finds each interior angle of a regular pentagon by computing 360°÷5=72°360° \div 5 = 72°. Identify the error and give the correct value.

  13. Reasoning. Explain why each interior angle of a regular polygon is always less than 180°180°, no matter how large nn is.

Exit ticket 12.3

  1. Give each interior angle of a regular hexagon.
  2. Give each exterior angle of a regular 2020-gon.
  3. Give each interior angle of that same 2020-gon.
  4. An irregular pentagon has an interior sum of 540°540°. Give each interior angle, or say why you cannot.

Lesson 12.4 — Working Backwards to nn

From an exterior angle: one division

A table of four exterior angles, each divided into 360 to give the number of sides

The exterior angles always total 360°360°, so in a regular polygon:

n=360°each exterior anglen = \frac{360°}{\text{each exterior angle}}

There is no nn hiding on the other side of the equation — one division and you are done. If each exterior angle is 24°24°, then n=360÷24=15n = 360 \div 24 = 15.

From an interior angle: subtract first

A table converting an interior angle to an exterior angle and then to n, with the last row producing a non-integer

Given an interior angle, go through the exterior angle:

Step one: e=180ie = 180 - i. Step two: n=360÷en = 360 \div e.

For i=156°i = 156°: e=24°e = 24°, so n=15n = 15. Going straight at the interior angle means solving (n2)180n=i\dfrac{(n-2)180}{n} = i, which reaches the same answer through more algebra.

The case with no answer

nn must be a whole number. A regular polygon has a whole number of sides.

If i=145°i = 145°, then e=35°e = 35° and 360÷3510.3360 \div 35 \approx 10.3 — not a whole number. There is no regular polygon with a 145°145° interior angle. "About 1010" is not the answer; "no such polygon" is.

This is the item that decides whether you have understood the lesson rather than memorised the division.

Worked examples

Example 1 — From an exterior angle

Each exterior angle of a regular polygon is 36°36°. Find nn.

Answer: n=360÷36=10n = 360 \div 36 = 10. A decagon.

Example 2 — From an interior angle

Each interior angle of a regular polygon is 162°162°. Find nn.

Answer: e=180162=18°e = 180 - 162 = 18°, so n=360÷18=20n = 360 \div 18 = 20.

Example 3 — No such polygon

Each interior angle of a regular polygon is 130°130°. Find nn.

Answer: e=50°e = 50°, and 360÷50=7.2360 \div 50 = 7.2, which is not a whole number. No such regular polygon exists.

Example 4 — From the sum

The interior angles of a convex polygon total 1980°1980°. Find nn.

Answer: (n2)180=1980n2=11n=13(n-2)180 = 1980 \Rightarrow n - 2 = 11 \Rightarrow n = 13.

Example 5 — Choosing the route

Each interior angle of a regular polygon is 150°150°. Which is faster — the interior formula or the exterior route?

Answer: The exterior route. e=30°e = 30° and n=12n = 12, in two steps. The interior formula needs (n2)180n=150\dfrac{(n-2)180}{n} = 150, cross-multiplied and rearranged, to reach the same 1212.

Guided practice

  1. Use the exterior table. Give the one-line rule for finding nn from an exterior angle.
  2. On that table, say why the exterior angle is the easier door in.
  3. Use the interior table. Give the two steps, in order.
  4. On that table, say what happens in the shaded row and what the correct answer is.
  5. Explain why nn has to be a whole number.
  6. Explain why going straight at the interior angle gives the same answer as the two-step route.

Independent practice

Find nn from each exterior angle of a regular polygon.

  1. 72°72°.
  2. 40°40°.
  3. 30°30°.
  4. 20°20°.
  5. 12°12°.

Find nn from each interior angle of a regular polygon.

  1. 108°108°.
  2. 135°135°.
  3. 144°144°.
  4. 156°156°.
  5. 165°165°.

Decide whether a regular polygon exists, and give nn if it does.

  1. Each exterior angle is 7°.

  2. Each interior angle is 145°145°.

  3. Each interior angle is 100°100°.

  4. Each interior angle is 170°170°.

  5. The interior angles of a convex polygon total 1980°1980°. Find nn.

  6. A regular polygon has each interior angle three times each exterior angle. Find nn.

  7. Application. A machinist must cut identical regular polygon plates whose corners are 150°150°. How many sides, and what angle does the cutting guide make with the edge?

  8. Error analysis. A student is told each interior angle is 145°145° and answers "about a 1010-gon." Explain why that is wrong rather than merely imprecise.

Exit ticket 12.4

  1. Each exterior angle of a regular polygon is 24°24°. Find nn.
  2. Each interior angle of a regular polygon is 150°150°. Find nn.
  3. Each interior angle of a regular polygon is 130°130°. Find nn, or say why you cannot.
  4. Give the two-step route from an interior angle to nn.

Chapter 12 Review

Vocabulary. polygon · convex · non-convex · regular · interior angle · exterior angle · supplementary · interior angle sum · nn-gon · diagonal · vertex · tile

Review 1 (G.PC.2b). A convex heptagon.

Review 2 (G.PC.2c). For a regular polygon with 1818 sides:

Review 3 (G.PC.2a). A designer is choosing a regular polygon for a paving stone.


Standards coverage check — Chapter 12

Knowledge and Skill Where it is taught Where it is practiced Where it is applied in context
G.PC.2a — solve problems involving the number of sides of a regular polygon given the measures of the interior and exterior angles 12.4 (both directions, and the whole-number requirement) 91–106, 108–112 107; Review 3
G.PC.2b — justify the relationship between the sum of the measures of the interior and exterior angles of a convex polygon, and solve problems involving the sum 12.1 (the triangle cut, and what convex rules out); 12.2 (walking the boundary; the irregular pentagon) 1–21, 23–28; 29–46, 49–56 22; 47, 48; Review 1
G.PC.2c — justify the relationship between the measure of each interior and exterior angle of a regular polygon, and solve problems involving the measures 12.3 (dividing by nn, and when you may not) 57–76, 79–84 77, 78; Review 2

Supporting items: 24, 51, 52, 80, 89, and 90 are the reasoning items, and 51 and 52 together carry the chapter's structural idea — the exterior sum is constant while the interior sum grows, and each relationship implies the other, since 180n360=(n2)180180n - 360 = (n-2)180. The error analyses target the recurring failures: multiplying by nn instead of n2n-2 (23), thinking the exterior sum depends on nn (49), thinking irregularity breaks the totals (50), using 360÷n360 \div n for an interior angle (79), and reporting a decimal number of sides instead of "no such polygon" (108).

Boundaries respected. Every result is stated for convex polygons, and Lesson 12.1 shows a non-convex figure so the restriction is visible rather than silent. The distinction the standard draws between a sum (bullet b, any convex polygon) and each angle (bullet c, regular only) is kept in force throughout, including an item — 76 — whose correct answer is that the question cannot be answered. Nothing here needs area, apothem, or trigonometry; those are not in G.PC.2, and the tiling items are settled by angle arithmetic alone.

Answer keys for every item in this chapter are in Appendix A.