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Virginia SOL Mathematics Textbook

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Chapter 4 — Sides and Angles of a Triangle

Standard: G.TR.1 (a, b, c, d, e)

G.TR.1 — verbatim. The student will determine the relationships between the measures of angles and lengths of sides in triangles, including problems in context. Students will demonstrate the following Knowledge and Skills: a) Given the lengths of three segments, determine whether a triangle could be formed. b) Given the lengths of two sides of a triangle, determine the range in which the length of the third side must lie. c) Order the sides of a triangle by their lengths when given information about the measures of the angles. d) Order the angles of a triangle by their measures when given information about the lengths of the sides. e) Solve for interior and exterior angles of a triangle, when given two angles.

By the end of this chapter you will be able to:

Lessons: 4.1 The Angle Sum and the Exterior Angle · 4.2 Ordering the Sides from the Angles · 4.3 Ordering the Angles from the Sides · 4.4 Does a Triangle Exist? · 4.5 The Range for a Third Side, and Problems in Context

Why this chapter matters. Every remaining chapter about triangles assumes what is here. Chapter 5 proves triangles congruent, which needs the angle sum to fill in a third angle. Chapter 7 proves them similar, which uses the angle sum to turn two matching angles into three. Chapter 8's Pythagorean work is about a specific triangle whose angles you already know sum correctly. And the ordering relationships — biggest angle faces the longest side, and the reverse — are the quickest sanity check you own: if a computed answer puts the long side across from the small angle, something is wrong before you check the arithmetic.

Scope note. The standard is about the two-way relationship between a triangle's angles and its sides, plus the question of whether a triangle exists at all. Bullet e names the angle work directly — solve for interior and exterior angles of a triangle, when given two angles — which is exactly Lesson 4.1. The contextual problems in Lesson 4.5 come from the standard's opening clause, "including problems in context," rather than from any single bullet. No trigonometry appears here. Ordering tells you which side is longest; it never tells you how long. Finding an actual length from angles is Chapter 9's job, under G.TR.4.

Conventions this chapter fixes.

  • A triangle's vertices are capital letters; the side opposite a vertex takes the matching lowercase letter. In ABC\triangle ABC, side aa is BC\overline{BC}, side bb is AC\overline{AC}, and side cc is AB\overline{AB}. Every ordering question in this chapter is really a question about which side is opposite which angle.
  • An ordering answer is written as a chain: c<b<ac < b < a, or C<B<A\angle C < \angle B < \angle A. When two are equal, the chain says so: A=B>C\angle A = \angle B > \angle C. Forcing a strict order onto a tie is wrong.
  • The Triangle Inequality is strict. Three lengths form a triangle when the two shorter ones add to more than the longest — not "at least."
  • A range for a third side is an open interval, written 3<x<173 < x < 17 and graphed with open circles at both ends.
  • Figures in this book are drawn to scale unless labelled otherwise, but a drawing is never a reason. The reason is the theorem.
  • Item numbering runs straight through the chapter, from 1 in Lesson 4.1 to 108 at the end of Lesson 4.5.

Lesson 4.1 — The Angle Sum and the Exterior Angle

The angle sum, and why it is true

Triangle Angle Sum Theorem. The measures of the three interior angles of a triangle sum to 180°180°.

You have used this since Grade 8. Here is the proof, and it is Chapter 2 doing the work.

Triangle ABC with angles 54, 71, and 55 degrees, and a dashed line drawn through vertex C parallel to side AB, with the 54 degree and 71 degree angles reappearing at C on either side of the 55 degree angle

Proof.

Statements Reasons
1. Draw the line through CC parallel to AB\overline{AB} 1. Through a point not on a line, exactly one parallel line exists
2. A\angle A \cong the angle at CC on the left 2. Alternate interior angles are congruent
3. B\angle B \cong the angle at CC on the right 3. Alternate interior angles are congruent
4. The three angles at CC form a straight angle 4. Definition of a straight angle
5. mA+mC+mB=180°m\angle A + m\angle C + m\angle B = 180° 5. Substitution into the straight angle

The auxiliary parallel line is the whole idea. Everything else is Chapter 2's alternate interior angles theorem, used twice.

Two consequences worth naming right away:

The exterior angle

Extend one side of a triangle past a vertex and you get an exterior angle. The two angles of the triangle not adjacent to it are its remote interior angles.

Triangle ABC with angles 48, 62, and 70 degrees, with side AB extended past B and the exterior angle at B marked 118 degrees

Exterior Angle Theorem. The measure of an exterior angle of a triangle equals the sum of its two remote interior angles.

In the figure, the exterior angle at BB measures 118°118°, and 48°+70°=118°48° + 70° = 118°.

The reason is short: the exterior angle and B\angle B form a linear pair, so the exterior angle is 180°mB180° - m\angle B. The angle sum says the other two angles also total 180°mB180° - m\angle B. Both equal the same thing, so they equal each other.

An exterior angle is therefore larger than either of its remote interior angles — a fact Lesson 4.4 leans on quietly, and one that Chapter 5's indirect proofs use directly.

Using both

An A-frame roof drawn as a triangle with a 44 degree peak at P, tick marks showing the two rafters are congruent, a 68 degree angle at L, and a question mark at R, with the horizontal base labeled tie beam

An A-frame with a 44°44° peak has two rafters of equal length, so the two base angles are equal. Subtracting the peak leaves 180°44°=136°180° - 44° = 136° for the two of them, and halving gives 68°68° each.

That last step used a fact this chapter proves properly in Lesson 4.3: equal sides face equal angles. For now, take it from the tick marks.

Worked examples

Example 1 — The third angle

Two angles of a triangle measure 37°37° and 88°88°. Find the third.

Answer: 180°37°88°=55°180° - 37° - 88° = 55°.

Example 2 — An exterior angle

An exterior angle of a triangle measures 125°125°, and one remote interior angle measures 60°60°. Find the other remote interior angle.

Answer: 125°60°=65°125° - 60° = 65°.

Example 3 — Working backwards

The exterior angle at BB measures 140°140°. Find mBm\angle B.

Answer: 180°140°=40°180° - 140° = 40° — the exterior angle and B\angle B form a linear pair.

Example 4 — With algebra

The angles of a triangle measure (2x)°(2x)°, (3x)°(3x)°, and (4x)°(4x)°. Find all three.

Answer: 2x+3x+4x=1802x + 3x + 4x = 180, so 9x=1809x = 180 and x=20x = 20. The angles are 40°40°, 60°60°, and 80°80°.

Example 5 — An impossible claim

A student says a triangle has angles of 95°95° and 102°102°. Respond.

Answer: Impossible — those two already total 197°>180°197° > 180°, leaving nothing for the third angle. A triangle can have at most one angle of 90°90° or more.

Guided practice

  1. Use the angle-sum figure. What are the three angle measures, and what do they sum to?
  2. On that same figure, which theorem from Chapter 2 justifies the two angles reappearing at CC?
  3. Why does the proof draw the auxiliary line parallel to AB\overline{AB} rather than any line through CC?
  4. Use the exterior-angle figure. What is the exterior angle's measure, and which two angles are its remote interior angles?
  5. Verify the Exterior Angle Theorem on that figure by adding.
  6. Use the A-frame figure. What is the peak angle, and how were the two base angles found?

Independent practice

  1. Find the third angle. a) 42°42° and 63°63° b) 90°90° and 37°37° c) 58°58° and 58°58°
  2. An exterior angle measures 132°132°. Find the adjacent interior angle.
  3. An exterior angle measures 105°105° and one remote interior angle measures 47°47°. Find the other remote interior angle.
  4. The angles of a triangle measure (x)°(x)°, (2x+10)°(2x + 10)°, and (3x4)°(3x - 4)°. Find xx and all three angles.
  5. The angles of a triangle measure (5x)°(5x)°, (6x)°(6x)°, and (7x)°(7x)°. Find all three, and classify the triangle by its angles.
  6. An exterior angle at CC measures (5y+10)°(5y + 10)° and the two remote interior angles measure (3y)°(3y)° and (y+26)°(y + 26)°. Find yy and the exterior angle.
  7. Application. A roof truss has a peak of 52°52° and two equal rafters. Find each base angle.
  8. Application. A triangular garden bed has one angle of 105°105°. The other two are equal. Find them.
  9. Error analysis. A student says a triangle can have angles of 90°90°, 90°90°, and 0°. Explain what is wrong.
  10. Error analysis. A student says the exterior angle at BB equals mBm\angle B plus one other angle. Correct the statement.
  11. Reasoning. Explain why an exterior angle is always larger than either of its remote interior angles.
  12. Reasoning. A triangle has an angle of 120°120°. What do you immediately know about the other two, without any calculation?

Exit ticket 4.1

  1. Two angles measure 71°71° and 46°46°. Find the third.
  2. An exterior angle measures 118°118°. Find the adjacent interior angle and the sum of the two remote interior angles.
  3. Can a triangle have angles of 88°88° and 94°94°? Justify.
  4. State the Exterior Angle Theorem in one sentence.

Lesson 4.2 — Ordering the Sides from the Angles

The rule

In any triangle, the longest side is opposite the largest angle, and the shortest side is opposite the smallest angle.

Triangle ABC with angles 35, 85, and 60 degrees, and its sides labeled c, a, and b, with side b opposite the 85 degree angle at B

Read the figure carefully, because the labelling convention is doing half the work. Side aa is opposite A\angle A, side bb is opposite B\angle B, side cc is opposite C\angle C. Here:

The rule is intuitive once you picture it: to open an angle wider, you have to swing its two sides apart, and the piece joining their far ends has to stretch to keep up.

Find the third angle first

The single most common error in this lesson is ordering from two angles when three were needed.

Two panels of the same triangle DEF. In the left panel only two angles are marked, 57 degrees at D and 44 degrees at E, with a question mark at F. In the right panel the third angle is filled in as 79 degrees and the sides are labeled f, d, and e

Given mD=57°m\angle D = 57° and mE=44°m\angle E = 44°, you cannot order anything yet — the unnamed third angle might be the largest, and here it is. Fill it in first:

mF=180°57°44°=79°m\angle F = 180° - 57° - 44° = 79°

Now the angles rank E<D<F\angle E < \angle D < \angle F, so the sides rank e<d<fe < d < f.

Habit worth building: write the angles in a row, sort them, then replace each angle with its opposite side. Two mechanical steps beat one clever one.

Answering the question that was asked

Ordering questions come in three shapes, and they want different answers:

Question Answer looks like
"Order the sides from shortest to longest." a<c<ba < c < b
"Which side is longest?" side bb, or AC\overline{AC}
"Name the shortest side of ABC\triangle ABC." BC\overline{BC}

Notice the third row. When a problem names segments rather than lowercase letters, translate: the side opposite A\angle A is BC\overline{BC}, because BB and CC are the two vertices that are not AA.

Worked examples

Example 1 — Straight ordering

In PQR\triangle PQR, mP=40°m\angle P = 40°, mQ=95°m\angle Q = 95°, mR=45°m\angle R = 45°. Order the sides.

Answer: Angles rank P<R<Q\angle P < \angle R < \angle Q, so sides rank p<r<qp < r < q.

Example 2 — Find the third first

In ABC\triangle ABC, mA=71°m\angle A = 71° and mB=33°m\angle B = 33°. Order the sides.

Answer: mC=180°71°33°=76°m\angle C = 180° - 71° - 33° = 76°. Angles rank B<A<C\angle B < \angle A < \angle C, so sides rank b<a<cb < a < c.

Example 3 — Naming segments

In the triangle of Example 2, which segment is the longest?

Answer: Side cc, which is AB\overline{AB} — the side opposite C\angle C.

Example 4 — A right triangle

In a right triangle, which side is always the longest?

Answer: The hypotenuse. The right angle is 90°90° and the other two angles sum to 90°90°, so each is smaller than the right angle; the side opposite the right angle is therefore the longest.

Example 5 — With a tie

In XYZ\triangle XYZ, mX=50°m\angle X = 50° and mY=50°m\angle Y = 50°. Order the sides.

Answer: mZ=80°m\angle Z = 80°. Angles rank X=Y<Z\angle X = \angle Y < \angle Z, so sides rank x=y<zx = y < z. Write the equality; do not invent an order between xx and yy.

Guided practice

  1. Use the longest-side figure. Which angle is largest, and which side is opposite it?
  2. On that same figure, which angle is smallest, and which side is opposite it?
  3. Write the full side ordering for that figure.
  4. Use the find-the-third-angle figure. Why can you not order the sides from the left panel alone?
  5. Compute the third angle in that figure, then write the angle ordering.
  6. Write the side ordering that follows.

Independent practice

  1. Order the sides from shortest to longest. a) mA=30°m\angle A = 30°, mB=60°m\angle B = 60°, mC=90°m\angle C = 90° b) mD=100°m\angle D = 100°, mE=45°m\angle E = 45°, mF=35°m\angle F = 35° c) mP=62°m\angle P = 62°, mQ=62°m\angle Q = 62°, mR=56°m\angle R = 56°
  2. Find the third angle, then order the sides. a) mA=55°m\angle A = 55°, mB=65°m\angle B = 65° b) mX=28°m\angle X = 28°, mY=34°m\angle Y = 34° c) mJ=90°m\angle J = 90°, mK=52°m\angle K = 52°
  3. In RST\triangle RST, mR=47°m\angle R = 47° and mS=47°m\angle S = 47°. Name the longest side as a segment.
  4. In ABC\triangle ABC, mA=25°m\angle A = 25° and mC=115°m\angle C = 115°. Name the shortest side as a segment.
  5. A triangle has angles 89°89°, 46°46°, and 45°45°. Which side is longest? Is the triangle a right triangle?
  6. In DEF\triangle DEF, an exterior angle at FF measures 130°130° and mD=62°m\angle D = 62°. Order the sides of DEF\triangle DEF.
  7. Application. A triangular sail has corner angles of 95°95°, 50°50°, and 35°35°. Which edge needs the longest piece of rope along it?
  8. Application. A triangular plot has angles 72°72°, 72°72°, and 36°36°. The owner wants to fence the shortest side first. Which side is it, and how do you know?
  9. Error analysis. Given mA=60°m\angle A = 60° and mB=70°m\angle B = 70°, a student writes a<ba < b and stops, saying bb is the longest side. Identify the error.
  10. Error analysis. In ABC\triangle ABC with mA=80°m\angle A = 80°, a student says AB\overline{AB} is the longest side. Explain the mistake.
  11. Reasoning. Explain in your own words why a larger angle must face a longer side.
  12. Reasoning. In a triangle with angles 60°60°, 60°60°, 60°60°, what is the side ordering, and what does that tell you about the triangle?

Exit ticket 4.2

  1. mA=45°m\angle A = 45°, mB=55°m\angle B = 55°, mC=80°m\angle C = 80°. Order the sides.
  2. mP=38°m\angle P = 38° and mQ=52°m\angle Q = 52°. Find mRm\angle R and name the longest side.
  3. In XYZ\triangle XYZ, which side is opposite Y\angle Y? Write it as a segment.
  4. State the ordering rule in one sentence.

Lesson 4.3 — Ordering the Angles from the Sides

The rule, read backwards

In any triangle, the largest angle is opposite the longest side, and the smallest angle is opposite the shortest side.

This is Lesson 4.2's rule with the hypothesis and conclusion swapped — its converse — and unlike most converses you met in Chapter 1, this one is true and is a theorem in its own right.

Triangle ABC with side lengths marked c = 5, b = 6, and a = 9, and each angle marked with a single arc

Sides rank c<b<ac < b < a, that is 5<6<95 < 6 < 9. So the angles rank

C<B<A\angle C < \angle B < \angle A

and you never needed a single angle measure to say so. That is the point of the lesson: the ordering is available directly from the side lengths.

Ties

Two triangles. The first is isosceles with sides 7, 7, and 4, tick marks on the two congruent sides, and arcs on the two angles opposite them. The second is equilateral with all sides 5 and all angles 60 degrees

Write the ties. An answer of "C<A<B\angle C < \angle A < \angle B" for the isosceles triangle is wrong, not merely imprecise — it claims a difference the figure does not have.

Both directions at once

The two lessons together say the ordering of the angles and the ordering of the opposite sides are the same ordering. So you can start from whichever you are given:

Given Do this
Three angles Rank them; the opposite sides rank the same way
Two angles Find the third from the angle sum, then rank
Three sides Rank them; the opposite angles rank the same way
Two sides only You cannot rank all three — the third side is not determined

That last row matters. Two sides do not fix a triangle; Lesson 4.5 shows how much freedom the third side has.

Worked examples

Example 1 — Straight ordering

In ABC\triangle ABC, a=12a = 12, b=7b = 7, c=9c = 9. Order the angles.

Answer: Sides rank b<c<ab < c < a, so angles rank B<C<A\angle B < \angle C < \angle A.

Example 2 — Segments instead of letters

In PQR\triangle PQR, PQ=8PQ = 8, QR=5QR = 5, PR=11PR = 11. Order the angles.

Answer: QR\overline{QR} is opposite P\angle P, PR\overline{PR} is opposite Q\angle Q, and PQ\overline{PQ} is opposite R\angle R. Sides rank QR<PQ<PRQR < PQ < PR, so angles rank P<R<Q\angle P < \angle R < \angle Q.

Example 3 — Isosceles

A triangle has sides 1010, 1010, and 66. Order the angles.

Answer: The two angles opposite the 1010s are equal and are both larger than the angle opposite the 66. Writing the vertices so that c=6c = 6: C<A=B\angle C < \angle A = \angle B.

Example 4 — Naming the largest

In DEF\triangle DEF, DE=14DE = 14, EF=9EF = 9, DF=11DF = 11. Which angle is largest?

Answer: DE\overline{DE} is longest and is opposite F\angle F, so F\angle F is largest.

Example 5 — A quick check

A student computes the angles of a triangle with sides 33, 44, 55 and gets \angle opposite the 33 as the largest. Respond.

Answer: Impossible. The largest angle must be opposite the longest side, which is 55. The answer contradicts the ordering rule before any arithmetic is checked.

Guided practice

  1. Use the ordering-from-sides figure. What are the three side lengths?
  2. Rank the sides, then rank the angles.
  3. Which angle is largest, and which side is it opposite?
  4. Use the isosceles-and-equilateral figure. Which two angles of the isosceles triangle are equal, and why?
  5. What is each angle of the equilateral triangle, and how do you know?
  6. Why is "C<A<B\angle C < \angle A < \angle B" a wrong answer for the isosceles triangle?

Independent practice

  1. Order the angles from smallest to largest. a) a=4a = 4, b=9b = 9, c=7c = 7 b) a=15a = 15, b=15b = 15, c=8c = 8 c) a=6a = 6, b=6b = 6, c=6c = 6
  2. In ABC\triangle ABC, AB=13AB = 13, BC=8BC = 8, AC=10AC = 10. Order the angles.
  3. In XYZ\triangle XYZ, XY=5XY = 5, YZ=12YZ = 12, XZ=12XZ = 12. Order the angles and note any tie.
  4. Which angle is largest in a triangle with sides 2121, 1717, and 2929?
  5. Which angle is smallest in PQR\triangle PQR with PQ=30PQ = 30, QR=24QR = 24, PR=26PR = 26?
  6. A triangle has sides 99, 1212, and 1515. Order the angles, and predict what kind of triangle it is.
  7. In DEF\triangle DEF, d=11d = 11, e=11e = 11, f=11f = 11. Give the angle ordering and each angle measure.
  8. Application. A triangular brace has sides 1818 in, 2424 in, and 3030 in. At which corner is the widest opening, and which side is across from it?
  9. Application. A triangular flowerbed has two sides of 1212 ft and one of 77 ft. Which corner angle is smallest?
  10. Error analysis. A student is told a=8a = 8, b=5b = 5, c=5c = 5 and writes A<B<C\angle A < \angle B < \angle C. Identify the two errors.
  11. Reasoning. Explain why an equilateral triangle must be equiangular, using the ordering rule and the angle sum together.
  12. Reasoning. You are given only two side lengths of a triangle. Explain why you cannot order all three angles.

Exit ticket 4.3

  1. a=7a = 7, b=4b = 4, c=9c = 9. Order the angles.
  2. A triangle has sides 66, 66, and 1010. Order the angles, showing the tie.
  3. In ABC\triangle ABC, AC\overline{AC} is the longest side. Which angle is largest?
  4. State the ordering rule in one sentence, and say how it relates to the rule in Lesson 4.2.

Lesson 4.4 — Does a Triangle Exist?

The Triangle Inequality

Not every three lengths make a triangle. Two short pieces at the ends of a long one may simply never reach each other.

Two panels. The left shows a triangle with sides 4, 5, and 6 and the note 4 plus 5 equals 9, greater than 6. The right shows a segment of length 9 with a 4 and a 3 swinging from its ends, their compass arcs failing to meet, and the note 3 plus 4 equals 7, less than 9

Triangle Inequality Theorem. Three positive lengths form a triangle if and only if the sum of any two is greater than the third.

The right-hand panel is the picture of the failure. Swing the 44 from one end of the 99 and the 33 from the other, and their arcs never cross — the two together span only 77, and the gap is 99.

One comparison is enough

The theorem names three comparisons, but you only ever have to check one.

Sort the three lengths and check that the two shorter ones add to more than the longest.

If that holds, the other two comparisons are automatic: the longest plus either other length is certainly bigger than the remaining one, because the longest already is. So the whole test is: sort, add the two small ones, compare.

The boundary case

A single horizontal segment of length 8 with a point marked 3 units from the left end, showing a 3 and a 5 lying flat along it, with the note 3 plus 5 equals 8

What if the two shorter lengths add to exactly the longest? Then the arcs meet in exactly one place — right on the long segment. The "triangle" flattens: no height, no area, and no angles to speak of. This is a degenerate triangle, and it is not a triangle.

That is why the inequality is strict. 3+5=83 + 5 = 8 fails the test, just as 3+4=7<93 + 4 = 7 < 9 does. When a problem's numbers land exactly on the boundary, the answer is "no triangle."

Worked examples

Example 1 — A quick yes

Can 77, 99, and 1212 form a triangle?

Answer: Sorted: 77, 99, 1212. 7+9=16>127 + 9 = 16 > 12 ✓ — yes.

Example 2 — A quick no

Can 22, 66, and 99 form a triangle?

Answer: Sorted: 22, 66, 99. 2+6=8<92 + 6 = 8 < 9 ✗ — no.

Example 3 — The boundary

Can 55, 88, and 1313 form a triangle?

Answer: 5+8=135 + 8 = 13, which is equal to the longest, not greater. No triangle — this is the degenerate case.

Example 4 — Two equal sides

Can 44, 44, and 99 form a triangle?

Answer: 4+4=8<94 + 4 = 8 < 9 ✗ — no. Two congruent sides do not guarantee a triangle.

Example 5 — Choosing a possible third length

Two sides measure 66 and 1010. Which of 33, 55, 1515, 1717 could be the third side?

Answer: 55 and 1515 work. 33 fails (3+6=9<103 + 6 = 9 < 10), and 1717 fails (6+10=16<176 + 10 = 16 < 17). Lesson 4.5 turns this into a single interval instead of a case-by-case check.

Guided practice

  1. Use the inequality figure, left panel. What are the three lengths, and what comparison is shown?
  2. Use the right panel. Why do the two arcs never cross?
  3. State the Triangle Inequality Theorem in your own words.
  4. Explain why checking only the two shorter lengths against the longest is enough.
  5. Use the degenerate figure. What do 33 and 55 add to, and what does the figure look like as a result?
  6. Why is the inequality strict rather than "greater than or equal to"?

Independent practice

  1. Decide whether a triangle exists, showing the comparison you used. a) 55, 77, 1111 b) 88, 33, 44 c) 1010, 1010, 1919 d) 66, 66, 1212
  2. Decide whether a triangle exists. a) 2.52.5, 3.53.5, 55 b) 1414, 99, 2222 c) 11, 11, 11
  3. Two sides are 99 and 44. Which of 44, 55, 1212, 1313 could be the third side?
  4. Two sides are 1111 and 1111. Which of 11, 2121, 2222, 2323 could be the third side?
  5. A triangle has sides xx, 88, and 1515 with xx a whole number. What is the smallest possible xx?
  6. Using item 77, what is the largest possible whole-number xx?
  7. A student is given 66, 88, and 1010 and checks 6+10>86 + 10 > 8 and 8+10>68 + 10 > 6, then stops. Which comparison actually decides the question, and what is the answer?
  8. Application. Three straight boards measure 1818 in, 2525 in, and 4646 in. Can they be joined end to end into a triangular frame? Show the comparison.
  9. Application. A camp needs a triangular sail from three cut ropes of 1212 ft, 1616 ft, and 2828 ft. Will it work? If not, by how much would the longest rope need to be shortened?
  10. Error analysis. A student says 44, 99, 1313 forms a triangle because 4+13>94 + 13 > 9. Identify the error and give the correct answer.
  11. Reasoning. Explain why two congruent sides of length ss can never form a triangle with a third side of length 2s2s or more.
  12. Reasoning. Explain what goes wrong geometrically in the boundary case, and why "degenerate" is a fair name for it.

Exit ticket 4.4

  1. Can 66, 77, and 1414 form a triangle? Show the comparison.
  2. Can 99, 1212, and 2020 form a triangle?
  3. Can 55, 55, and 1010 form a triangle? Explain what is special about this case.
  4. State the single comparison that decides the question, and say why the other two are unnecessary.

Lesson 4.5 — The Range for a Third Side, and Problems in Context

Turning the test into an interval

Lesson 4.4 checked one candidate at a time. G.TR.1b asks for all of them at once.

Suppose two sides measure 77 and 1010, and call the third side xx. The Triangle Inequality gives three conditions:

7+10>xx<177 + 10 > x \quad \Rightarrow \quad x < 17 7+x>10x>37 + x > 10 \quad \Rightarrow \quad x > 3 10+x>7x>3 (automatic, since x is a length)10 + x > 7 \quad \Rightarrow \quad x > -3 \ \text{(automatic, since $x$ is a length)}

Two of them bite, and together they give an interval.

A number line from 0 to 20 with an open circle at 3, an open circle at 17, and the segment between them shaded, labeled 3 is less than x is less than 17

Third-Side Range. If two sides measure pp and qq, the third side xx satisfies pq<x<p+q|p - q| < x < p + q

In words: greater than the difference, less than the sum. Both endpoints are excluded, and both circles on the graph are open, because either endpoint would flatten the triangle into the degenerate case of Lesson 4.4.

For 77 and 1010: the difference is 33, the sum is 1717, and the range is 3<x<173 < x < 17.

Whole-number answers

Problems often ask for whole-number possibilities. From 3<x<173 < x < 17, the whole numbers are 44 through 1616 — that is 1313 values. Do not include 33 or 1717.

A common follow-up asks for the largest or smallest possible whole-number side. From this range, the smallest is 44 and the largest is 1616.

Problems in context

A triangle labeled A, B, C with a 62 degree angle at A, a 74 degree angle at B, a question mark at C, and the three sides labeled anchor line, mast, and cable, with a horizontal ground line beneath

The standard's opening clause — "including problems in context" — is where the chapter's pieces get chosen rather than practiced. The support triangle above gives two angles, so:

mC=180°62°74°=44°m\angle C = 180° - 62° - 74° = 44°

C\angle C is the smallest angle, so the side opposite it — the anchor line — is the shortest of the three pieces. A question about which piece needs the least material is answered without measuring anything.

Deciding which tool a context problem wants:

The problem gives you Use
Two angles, asks for the third Angle sum (4.1)
An exterior angle and one remote interior angle Exterior Angle Theorem (4.1)
Angles, asks which side is longest/shortest Ordering, angles → sides (4.2)
Side lengths, asks which angle is largest/smallest Ordering, sides → angles (4.3)
Three lengths, asks "will it work?" Triangle Inequality (4.4)
Two lengths, asks what the third could be Third-side range (4.5)

Worked examples

Example 1 — A range

Two sides measure 55 and 1212. Give the range for the third side.

Answer: 125=712 - 5 = 7 and 12+5=1712 + 5 = 17, so 7<x<177 < x < 17.

Example 2 — Whole numbers

How many whole-number lengths are possible in Example 1?

Answer: 88 through 1616, which is 99 values.

Example 3 — Equal sides

Two sides measure 99 and 99. Give the range for the third.

Answer: 99=0|9 - 9| = 0 and 9+9=189 + 9 = 18, so 0<x<180 < x < 18. The lower bound is 00 because the two given sides are equal, and any positive length shorter than 1818 works.

Example 4 — Ordering in context

A triangular shelf bracket has angles 34°34°, 56°56°, and 90°90°. Which edge is longest?

Answer: The edge opposite the 90°90° angle — the hypotenuse.

Example 5 — Choosing the tool

A frame uses two struts of 2020 cm and 3232 cm plus a crosspiece. The shop has crosspieces of 1010, 1515, 4040, and 5555 cm. Which will work?

Answer: The range is 3220=1232 - 20 = 12 to 32+20=5232 + 20 = 52, so 12<x<5212 < x < 52. The 1515 cm and 4040 cm crosspieces work; 1010 and 5555 do not.

Guided practice

  1. Use the third-side-range figure. What are the two known sides, and what is the range?
  2. Why are both circles open rather than closed?
  3. Give the whole-number values allowed by that range, and count them.
  4. Use the context figure. What is mCm\angle C?
  5. Which side is the shortest, and which relationship told you?
  6. If the angle at AA were 70°70° instead, what would mCm\angle C become, and would the shortest side change?

Independent practice

  1. Give the range for the third side. a) 66 and 1010 b) 44 and 44 c) 1515 and 2222
  2. Give the range for the third side, and the number of whole-number possibilities. a) 88 and 1111 b) 55 and 1313
  3. Two sides are 99 and 1616. What are the smallest and largest whole-number lengths the third side could be?
  4. A triangle has sides xx, 1212, and 1919. Write the range for xx and give the whole-number count.
  5. Application. A triangular sign has angles 48°48°, 48°48°, and 84°84°. Which edge is longest, and which two are equal?
  6. Application. A bracing triangle has two struts of 1414 in and 99 in. A supplier sells crosspieces in whole inches. List the possible crosspiece lengths.
  7. Application. A trail forms a triangle. Two legs are 3.53.5 km and 5.25.2 km. Between what two distances must the third leg lie?
  8. Application. A truss has one angle of 96°96° and another of 42°42°. Order its three sides, shortest to longest, naming them as segments of ABC\triangle ABC with mA=96°m\angle A = 96° and mB=42°m\angle B = 42°.
  9. Error analysis. Asked for the range with sides 77 and 99, a student writes 7<x<97 < x < 9. Identify the error and give the correct range.
  10. Reasoning. Explain why the lower bound of the range is the difference of the two sides, using the picture of two arcs swinging from the ends of a segment.

Exit ticket 4.5

  1. Two sides measure 1111 and 66. Give the range for the third side.
  2. How many whole-number values are possible in item 105?
  3. A triangle has angles 27°27°, 63°63°, and 90°90°. Order the sides from shortest to longest.
  4. Name the relationship you would use for each: (i) two sides given, asked what the third could be; (ii) three angles given, asked which side is longest; (iii) three lengths given, asked whether a triangle exists.

Chapter 4 Review

Vocabulary. interior angle · exterior angle · remote interior angles · Triangle Angle Sum Theorem · Exterior Angle Theorem · opposite side · ordering · Triangle Inequality Theorem · degenerate triangle · third-side range · isosceles · equilateral · equiangular

Review 1 (G.TR.1 a, e). In ABC\triangle ABC, mA=41°m\angle A = 41° and the exterior angle at CC measures 118°118°.

Review 2 (G.TR.1 b, c, d). A triangle has two sides measuring 1313 and 66.

Review 3 (G.TR.1 e). A triangular roof brace is built from three pieces. Two of the corner angles measure 53°53° and 89°89°.


Standards coverage check — Chapter 4

Knowledge and Skill Where it is taught Where it is practiced Where it is applied in context
G.TR.1a — given three segment lengths, determine whether a triangle could be formed 4.4 (the inequality, the one-comparison shortcut, the degenerate case) 67–79, 82–88 80, 81; Review 3
G.TR.1b — given two sides, determine the range the third side must lie in 4.5 (deriving the interval, open endpoints, whole-number counts) 89–91, 95–98, 103–106 100, 101; Review 2, Review 3
G.TR.1c — order the sides by length, given the angle measures 4.2 (the rule, the opposite-side convention, find-the-third-angle-first) 23–34, 37–44; 107 35, 36; Review 1, Review 3
G.TR.1d — order the angles by measure, given the side lengths 4.3 (the converse rule, ties in isosceles and equilateral triangles) 45–57, 60–66 58, 59; Review 2
G.TR.1e — solve for interior and exterior angles, given two angles 4.1 (angle sum, exterior angle, and the proof of each) 1–12, 15–22; 92, 94 13, 14; Review 1
opening clause — "including problems in context" 4.5 (choosing which relationship a problem wants) 93, 108 99, 102; Review 3

Supporting items: 3, 17, 18, 39, 40, 61, 62, 83, 84, and 104 are the reasoning items; 62 and 104 together make the point that two sides leave the third undetermined, which is what Lesson 4.5 quantifies. The error analyses target the five recurring mistakes: claiming a triangle with two angles of 90°90° or more (15), adding the adjacent rather than the remote interior angles to an exterior angle (16), ordering from two angles without finding the third (37), naming a side by the vertex it touches rather than the vertex it faces (38), inverting the ordering or missing a tie (60), checking a comparison that cannot fail (79, 82), and reading the range as "between the two given sides" (103).

Boundaries respected. No item asks for an actual side length from angle measures — that requires trigonometry, which is Chapter 9 under G.TR.4. No item asks for a triangle congruence or similarity claim; those are Chapters 5 through 7. The angle sum and exterior angle theorems are bullet e itself, and their proofs draw only on Chapter 2's parallel-line results. Ordering answers are always chains, never numeric angle measures inferred from side lengths.

Answer keys for every item in this chapter are in Appendix A.