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Virginia SOL Mathematics Textbook

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Chapter 16 — Quadratic Functions

Standard: A.F.2 (b, c, d, g)

A.F.2 — verbatim. The student will investigate, analyze, and compare characteristics of functions, including quadratic, and exponential functions, and model quadratic and exponential relationships. Students will demonstrate the following Knowledge and Skills: b) Given an equation or graph, determine key characteristics of a quadratic function including xx-intercepts (zeros), yy-intercept, vertex (maximum or minimum), and domain and range (including when restricted by context); interpret key characteristics as related to contextual situations, where applicable. c) Graph a quadratic function, f(x)f(x), in two variables using a variety of strategies, including transformations f(x)+kf(x) + k and kf(x)kf(x), where kk is limited to rational values. d) Make connections between the algebraic (standard and factored forms) and graphical representation of a quadratic function. g) For any value, xx, in the domain of ff, determine f(x)f(x) of a quadratic or exponential function. Determine xx given any value f(x)f(x) in the range of ff of a quadratic function. Explain the meaning of xx and f(x)f(x) in context.

By the end of this chapter you will be able to:

Lessons: 16.1 Vertex, Axis, and Opening · 16.2 Intercepts, Zeros, and the Vertex Formula · 16.3 Domain and Range, Including Context · 16.4 Transformations f(x)+kf(x) + k and kf(x)kf(x) · 16.5 Standard Form, Factored Form, and the Graph · 16.6 Evaluating f(x)f(x) and Finding xx

Why this chapter matters. Chapter 15 asked when a quadratic expression equals zero. This chapter asks what the related function looks like and what it tells you. The zeros are still there — they are the xx-intercepts of the parabola — but now they sit beside a vertex that is a highest or lowest point, a yy-intercept that starts a story, and a domain and range that may be cut down by the situation. Those characteristics are what a height model, a revenue model, or an arch model actually report. Learning to read them off an equation and off a graph is the skill A.F.2b demands; graphing by the two named transformations, connecting two algebraic forms to one picture, and evaluating or solving f(x)=cf(x) = c complete the chapter.

Scope note. This chapter studies quadratic functions. Transformations are limited exactly as A.F.2c states: f(x)+kf(x) + k and kf(x)kf(x), with kk rational. Horizontal shifts of the parent are not taught as a transformation rule here; when a vertex is off the yy-axis, find it with the vertex formula or from factored form, then plot. Exponential functions are A.F.2 e, f, and g in Chapter 17. Comparing linear, quadratic, and exponential families is A.F.2h in Chapter 18. Solving quadratic equations as an end in itself was Chapter 15; this chapter uses those solving skills to find zeros and to recover xx from f(x)=cf(x) = c. Completing the square as an expression rewrite (vertex form) was Chapter 14; vertex form may appear as a reading aid, but the graphing strategies this chapter practices are the two A.F.2c names plus plotting from characteristics.

Conventions this chapter fixes.

  • A quadratic function is written f(x)=ax2+bx+cf(x) = ax^2 + bx + c or y=ax2+bx+cy = ax^2 + bx + c with a0a \neq 0. Its graph is a parabola.
  • An intercept is a point: the yy-intercept is (0,c)(0, c); each xx-intercept is (r,0)(r, 0). A zero is a number: the xx-coordinate of an xx-intercept. Chapter 15 fixed the three-name habit (zero / root / xx-intercept); this chapter keeps it.
  • The vertex is the turning point (h,k)(h, k). If a>0a > 0, the parabola opens up and the vertex is a minimum. If a<0a < 0, it opens down and the vertex is a maximum.
  • The axis of symmetry is the vertical line x=hx = h. For y=ax2+bx+cy = ax^2 + bx + c, h=b2ah = -\dfrac{b}{2a} and k=f(h)k = f(h).
  • Domains and ranges of continuous graphs are described in words or with inequalities such as y4y \ge -4 or 0t30 \le t \le 3, as in Chapters 4 and 5. Interval notation is never required.
  • Item numbering runs straight through the chapter, from 1 in Lesson 16.1 to 126 at the end of the review. It does not restart at each lesson.

Calculator note. Algebra 1 has no no-calculator standards, and the Desmos Virginia Graphing Calculator is available for the entire End-of-Course test. Use technology the way this volume always does: to confirm a vertex, intercept, or evaluation you already produced. Entering y=x22x3y = x^2 - 2x - 3 and reading the minimum at (1,4)(1, -4) is a good habit. What technology cannot do alone is explain what that minimum means in a story — that is still your job.


Lesson 16.1 — Vertex, Axis, and Opening

The shape is a parabola

A quadratic function has the form

f(x)=ax2+bx+c(a0)f(x) = ax^2 + bx + c \quad (a \neq 0)

Its graph is a parabola — a smooth U-shaped curve. The sign of aa decides which way the U faces.

The parabola y equals x squared minus 4x minus 5 with its vertex at 2 comma negative 9 marked, a dashed vertical axis of symmetry at x equals 2, and a note that the curve opens upward because a is positive

The figure shows y=x24x5y = x^2 - 4x - 5. The leading coefficient is a=1>0a = 1 > 0, so the curve opens up. The lowest point on the curve is the vertex (2,9)(2, -9). The dashed vertical line through that point is the axis of symmetry, x=2x = 2. Every point on one side of the axis has a mirror match on the other side — that is what "symmetry" means here.

Minimum or maximum

The vertex is never just a point; it is either a floor or a ceiling.

Two panels: left, y equals x squared minus 4 opening upward with a minimum at 0 comma negative 4; right, y equals negative x squared plus 4 opening downward with a maximum at 0 comma 4

The left panel of the figure never drops below 4-4. The right panel never rises above 44. That single fact will decide the range in Lesson 16.3.

The parent quadratic

Every parabola in this chapter is related to the parent function

y=x2y = x^2

The parent parabola y equals x squared with vertex at the origin, axis x equals 0, domain all reals, and range y greater than or equal to 0

The parent opens up, has vertex (0,0)(0, 0), axis x=0x = 0, domain all real numbers, and range y0y \ge 0. Lesson 16.4 will move and stretch this parent using the two transformations A.F.2c allows. For now, treat it as the reference picture: when a quadratic looks "taller," "wider," "higher," or "upside down," you are comparing it to y=x2y = x^2.

Worked examples

Example 1 — Opening and vertex type

Does f(x)=3x2+5x1f(x) = -3x^2 + 5x - 1 open up or down? Is its vertex a max or a min?

a=3<0a = -3 < 0, so the parabola opens down.

Answer: Opens down; the vertex is a maximum.

Example 2 — Reading the figure

Using the vertex-and-axis figure, name the vertex and the axis of symmetry of y=x24x5y = x^2 - 4x - 5.

Answer: Vertex (2,9)(2, -9); axis x=2x = 2.

Example 3 — Parent characteristics

Give the vertex, axis, domain, and range of y=x2y = x^2.

Answer: Vertex (0,0)(0, 0); axis x=0x = 0; domain all real numbers; range y0y \ge 0.

Example 4 — Max versus min from a picture

Using the opens-up / opens-down figure, which function has a maximum, and what is it?

Answer: y=x2+4y = -x^2 + 4 has a maximum of 44 at the vertex (0,4)(0, 4).

Example 5 — Axis as a mirror

The vertex of a parabola is (3,2)(3, -2) and the point (5,1)(5, 1) lies on the curve. Name another point that must also lie on the curve.

The axis is x=3x = 3. The input 55 is 22 units right of 33, so its mirror is 22 units left: x=1x = 1. The output stays 11.

Answer: (1,1)(1, 1).

Guided practice

  1. Use the vertex-and-axis figure. Name the equation, the vertex, and the axis of symmetry.
  2. Does that parabola open up or down? How do you know from the equation?
  3. Use the opens-up / opens-down figure. For y=x24y = x^2 - 4, is the vertex a max or a min? What are its coordinates?
  4. For y=x2+4y = -x^2 + 4 in that same figure, is the vertex a max or a min? What are its coordinates?
  5. Use the parent figure. State the vertex, axis, domain, and range of y=x2y = x^2.
  6. Explain in one sentence why the axis of symmetry of a parabola is a vertical line through the vertex.

Independent practice

  1. For each function, say whether it opens up or down, and whether the vertex is a max or a min. a) f(x)=2x23x+1f(x) = 2x^2 - 3x + 1 b) g(x)=x2+4g(x) = -x^2 + 4 c) h(x)=12x27h(x) = \tfrac12 x^2 - 7 d) y=5x2+xy = -5x^2 + x
  2. A parabola has vertex (4,1)(4, -1) and passes through (6,3)(6, 3). Name another point on the parabola, and explain.
  3. Sketch y=x2y = x^2 from memory (or use technology), then mark the vertex and the axis.
  4. Reasoning. Why can a quadratic function never open "sideways"? Connect your answer to the definition y=ax2+bx+cy = ax^2 + bx + c.
  5. Error analysis. A student says y=x2+4y = -x^2 + 4 has a minimum at (0,4)(0, 4) because the vertex is the "bottom." Identify the error.
  6. The graph of y=x24x5y = x^2 - 4x - 5 is shown in the vertex-and-axis figure. Name one pair of points that are mirrors across the axis (you may read approximate grid points if needed, or compute f(0)f(0) and f(4)f(4)).
  7. Application. A ball's height is modeled by h(t)=16t2+32t+6h(t) = -16t^2 + 32t + 6. Without finding the vertex yet, say whether the height has a maximum or a minimum, and why.
  8. Compare y=x2y = x^2 and y=x2y = -x^2. How are the graphs related, and what happens to the vertex?
  9. Technology. Enter y=x24x5y = x^2 - 4x - 5 on a graphing calculator or graphing site. Confirm the vertex at (2,9)(2, -9) and the axis x=2x = 2. Name the window you used.
  10. Explain why aa cannot be 00 if the graph is to be a parabola.

Exit ticket 16.1

  1. Does f(x)=4x2x9f(x) = 4x^2 - x - 9 open up or down? Is the vertex a max or a min?
  2. The vertex of a parabola is (2,5)(-2, 5) and a<0a < 0. Write the equation of the axis of symmetry, and say whether 55 is a maximum or a minimum value.
  3. Give the vertex and axis of the parent y=x2y = x^2.
  4. In one sentence, say what the axis of symmetry does for the graph.

Lesson 16.2 — Intercepts, Zeros, and the Vertex Formula

Every characteristic A.F.2b names

A.F.2b asks for five characteristics of a quadratic, given an equation or a graph:

  1. xx-intercepts (zeros)
  2. yy-intercept
  3. vertex (and whether it is a max or a min)
  4. domain
  5. range

The parabola y equals x squared minus 2x minus 3 with zeros at negative 1 and 3, y-intercept at 0 comma negative 3, vertex minimum at 1 comma negative 4, axis x equals 1, domain all reals, and range y greater than or equal to negative 4

The figure packs all five onto y=x22x3y = x^2 - 2x - 3 at once. Read it top to bottom: zeros at (1,0)(-1, 0) and (3,0)(3, 0); yy-intercept (0,3)(0, -3); vertex (minimum) (1,4)(1, -4); domain all real numbers; range y4y \ge -4. One careful look at a graph can hand you the whole list. The rest of this lesson shows how to get the same list from the equation alone.

Finding the pieces from y=ax2+bx+cy = ax^2 + bx + c

Characteristic How to find it
yy-intercept Evaluate at x=0x = 0: the point is (0,c)(0, c).
Zeros / xx-intercepts Solve ax2+bx+c=0ax^2 + bx + c = 0 (factor, square roots, or the quadratic formula — Chapter 15).
Axis x=hx = h where h=b2ah = -\dfrac{b}{2a}.
Vertex (h,k)(h, k) where k=f(h)k = f(h). Then read max or min from the sign of aa.

For y=x22x3y = x^2 - 2x - 3:

That matches the figure exactly. Algebra and the graph are required to agree.

Worked examples

Example 1 — yy-intercept

Find the yy-intercept of f(x)=2x25x+7f(x) = 2x^2 - 5x + 7.

f(0)=7f(0) = 7.

Answer: (0,7)(0, 7).

Example 2 — Zeros by factoring

Find the zeros of f(x)=x22x3f(x) = x^2 - 2x - 3.

(x3)(x+1)=0(x - 3)(x + 1) = 0, so x=3x = 3 or x=1x = -1.

Answer: Zeros 1-1 and 33; xx-intercepts (1,0)(-1, 0) and (3,0)(3, 0).

Example 3 — Vertex formula

Find the vertex of f(x)=x22x3f(x) = x^2 - 2x - 3.

h=22=1h = -\dfrac{-2}{2} = 1, k=f(1)=4k = f(1) = -4.

Answer: (1,4)(1, -4), a minimum.

Example 4 — No real zeros

Find the zeros of g(x)=x2+1g(x) = x^2 + 1.

x2+1=0x^2 + 1 = 0 has no real solutions (Chapter 15). The graph never meets the xx-axis.

Answer: No real zeros; no xx-intercepts.

Example 5 — Reading a graph

Using the all-characteristics figure, name the zeros, yy-intercept, and vertex of y=x22x3y = x^2 - 2x - 3.

Answer: Zeros 1-1 and 33; yy-intercept (0,3)(0, -3); vertex (1,4)(1, -4).

Guided practice

  1. Use the all-characteristics figure. List the zeros, yy-intercept, vertex, domain, and range of y=x22x3y = x^2 - 2x - 3.
  2. For f(x)=x22x3f(x) = x^2 - 2x - 3, show the algebra that produces h=1h = 1 and k=4k = -4.
  3. Find the yy-intercept of y=3x2+4x8y = -3x^2 + 4x - 8.
  4. Find the zeros of y=x25x+6y = x^2 - 5x + 6 by factoring, and write the xx-intercepts as points.
  5. Find the vertex of y=x26x+5y = x^2 - 6x + 5. Say whether it is a max or a min.
  6. Explain the difference between a zero and an xx-intercept, using y=x22x3y = x^2 - 2x - 3 as the example.

Independent practice

  1. For each function, find the yy-intercept. a) f(x)=x2+9x2f(x) = x^2 + 9x - 2 b) g(x)=4x2+11g(x) = -4x^2 + 11 c) h(x)=3x2xh(x) = 3x^2 - x
  2. Find the zeros and xx-intercepts. a) y=x29y = x^2 - 9 b) y=x2+2x15y = x^2 + 2x - 15 c) y=(x4)(x+1)y = (x - 4)(x + 1)
  3. Find the axis and vertex. State max or min. a) y=x24x+1y = x^2 - 4x + 1 b) y=2x2+8x3y = -2x^2 + 8x - 3 c) y=x2+6x+10y = x^2 + 6x + 10
  4. Use the all-characteristics figure. Verify each labeled feature by algebra: zeros by factoring, yy-intercept by evaluating at 00, vertex by the formula.
  5. Reasoning. A parabola has zeros at x=2x = -2 and x=6x = 6. Where is the axis of symmetry? Explain without finding aa, bb, or cc.
  6. Error analysis. A student finds h=b2ah = -\dfrac{b}{2a} for y=x24x5y = x^2 - 4x - 5 and gets h=2h = -2. Identify the error and give the correct hh.
  7. Application. Revenue in dollars from selling xx items is R(x)=x2+40xR(x) = -x^2 + 40x. Find the yy-intercept and interpret it. Then find the vertex and interpret the maximum revenue.
  8. Find all key characteristics of y=x2+4y = -x^2 + 4 using the opens-up / opens-down figure and algebra.
  9. Technology. Enter y=x22x3y = x^2 - 2x - 3. Use the zero and minimum features to confirm the figure. Report the values.
  10. A quadratic has vertex (2,9)(2, -9) and yy-intercept (0,5)(0, -5). Could it be y=x24x5y = x^2 - 4x - 5? Check both claims.

Exit ticket 16.2

  1. Find the yy-intercept and zeros of f(x)=x2x6f(x) = x^2 - x - 6.
  2. Find the vertex of f(x)=x2x6f(x) = x^2 - x - 6. Is it a max or a min?
  3. A parabola has xx-intercepts (3,0)(-3, 0) and (5,0)(5, 0). What is the axis of symmetry?
  4. In one sentence, say how the vertex formula h=b2ah = -\dfrac{b}{2a} is related to the axis of symmetry.

Lesson 16.3 — Domain and Range, Including Context

The default answers

For an unrestricted quadratic y=ax2+bx+cy = ax^2 + bx + c:

That is the same habit Chapter 5 used for lines, adapted to a curve with a floor or a ceiling. The all-characteristics figure already showed it: y=x22x3y = x^2 - 2x - 3 has domain all reals and range y4y \ge -4.

When a story cuts the domain down

An equation accepts every real input. A situation usually does not.

A projectile height graph h equals negative 16 t squared plus 48 t from throw at 0 comma 0 through a maximum at 1.5 comma 36 to landing at 3 comma 0, with domain 0 to 3 seconds and range 0 to 36 feet labeled

A ball thrown from ground level with

h(t)=16t2+48th(t) = -16t^2 + 48t

reaches a maximum of 3636 feet at t=1.5t = 1.5 seconds and lands at t=3t = 3 seconds. The equation would accept t=1t = -1 or t=10t = 10. The story only runs from throw to landing:

Both endpoints are included: the throw and the landing are real moments, and ground level is a real height.

The habit is the same as in Chapter 5. Ask the equation for the domain and you get all real numbers. Ask the situation, and you get the truth.

Worked examples

Example 1 — From the equation

Give the domain and range of f(x)=x22x3f(x) = x^2 - 2x - 3.

Vertex (1,4)(1, -4), a>0a > 0.

Answer: Domain: all real numbers. Range: y4y \ge -4.

Example 2 — Opens down

Give the domain and range of g(x)=x2+4g(x) = -x^2 + 4.

Vertex (0,4)(0, 4), a<0a < 0.

Answer: Domain: all real numbers. Range: y4y \le 4.

Example 3 — Context

Using the projectile figure, state the domain and range of h(t)=16t2+48th(t) = -16t^2 + 48t in context, with units.

Answer: Domain 0t30 \le t \le 3 seconds; range 0h360 \le h \le 36 feet.

Example 4 — Why the equation differs

What domain would the equation 16t2+48t-16t^2 + 48t have, ignoring the story?

Answer: All real numbers. The story, not the algebra, cuts it to 0t30 \le t \le 3.

Example 5 — Interpreting the vertex in context

What does the point (1.5,36)(1.5, 36) mean for the ball?

Answer: At 1.51.5 seconds after the throw, the ball reaches its maximum height of 3636 feet.

Guided practice

  1. Give the domain and range of y=x22x3y = x^2 - 2x - 3 from the all-characteristics figure.
  2. Give the domain and range of y=x2+4y = -x^2 + 4 from the opens-up / opens-down figure.
  3. Use the projectile figure. State the domain and range in context, with units.
  4. In that same figure, what do the points (0,0)(0, 0), (1.5,36)(1.5, 36), and (3,0)(3, 0) mean in the story?
  5. Explain why the domain of the projectile equation is all real numbers, while the domain in context is not.
  6. Give the domain and range of y=x2y = x^2 from the parent figure.

Independent practice

  1. Give the domain and range of each (unrestricted) function. a) f(x)=x2+6x+5f(x) = x^2 + 6x + 5 b) g(x)=2x2+8xg(x) = -2x^2 + 8x c) h(x)=x29h(x) = x^2 - 9 d) y=x21y = -x^2 - 1
  2. Application. A ball's height in feet is h(t)=16t2+48th(t) = -16t^2 + 48t. Using the projectile figure, interpret the domain, range, and vertex in one sentence each, with units.
  3. Application. An arch is modeled by y=x2+6xy = -x^2 + 6x for 0x60 \le x \le 6, with xx in meters along the ground and yy in meters of height. Find the vertex, then give the domain and range in context.
  4. Reasoning. Why is the range of an upward-opening parabola never "all real numbers"?
  5. Error analysis. A student says the range of y=x22x3y = x^2 - 2x - 3 is y0y \ge 0 because "height cannot be negative." Identify the error. (The function is not a height model.)
  6. A revenue function R(x)=x2+40xR(x) = -x^2 + 40x models dollars of revenue from xx items sold, for 0x400 \le x \le 40. Find the vertex, then give domain and range in context.
  7. Compare the domain and range of y=x24y = x^2 - 4 (unrestricted) with the domain and range of the same equation restricted to 2x2-2 \le x \le 2.
  8. Technology. Graph h=16t2+48th = -16t^2 + 48t with a window that shows 0t30 \le t \le 3. Confirm the maximum near (1.5,36)(1.5, 36).
  9. Sketch y=x2+9y = -x^2 + 9 and shade the region of the plane that represents its range.
  10. Explain. In two sentences, say how context can change the domain of a quadratic without changing the equation.

Exit ticket 16.3

  1. Give the domain and range of f(x)=x28x+12f(x) = x^2 - 8x + 12.
  2. Give the domain and range of g(x)=x2+5g(x) = -x^2 + 5.
  3. Using the projectile figure, write the domain in context and explain what each endpoint means.
  4. Why does an unrestricted quadratic always have domain all real numbers?

Lesson 16.4 — Transformations f(x)+kf(x) + k and kf(x)kf(x)

What A.F.2c allows

A.F.2c asks you to graph a quadratic using a variety of strategies, including the transformations

f(x)+kandkf(x)f(x) + k \qquad \text{and} \qquad kf(x)

with kk limited to rational values. Starting from the parent f(x)=x2f(x) = x^2, those two moves are a vertical shift and a vertical stretch / shrink / reflection.

Horizontal shifts are not on the A.F.2c list. When a vertex is not on the yy-axis, use the vertex formula or factored form (Lessons 16.2 and 16.5), then plot — do not invent a horizontal-shift rule for this standard.

Vertical shifts: f(x)+kf(x) + k

Three parabolas: parent y equals x squared in black, y equals x squared plus 3 shifted up in blue, and y equals x squared minus 4 shifted down in red, all sharing axis x equals 0

Adding a constant moves every point of the parent straight up or down.

The axis stays x=0x = 0. The shape does not change — only the height of the vertex.

Vertical stretches, shrinks, and reflections: kf(x)kf(x)

Four parabolas through the origin: parent y equals x squared, stretch y equals 2x squared, shrink y equals one-half x squared, and reflection y equals negative x squared

Multiplying by a rational kk scales every output.

The vertex of y=kx2y = kx^2 stays at (0,0)(0, 0). Combining a stretch with a shift gives y=kx2+cy = kx^2 + c, still covered by the two named moves applied in sequence.

Graphing strategies this lesson practices

  1. From the parent by transformations when the equation is y=kx2+cy = kx^2 + c.
  2. From characteristics when b0b \neq 0: find vertex, intercepts, then sketch (Lesson 16.2).
  3. With technology to confirm either sketch.

Four blank coordinate grids labeled a through d for sketching transformed and general quadratics

The blank grids are for practice sketches in the workbook and independent practice.

Worked examples

Example 1 — Shift

Describe how to obtain y=x2+5y = x^2 + 5 from y=x2y = x^2, and give the new vertex.

Answer: Shift up 55. Vertex (0,5)(0, 5).

Example 2 — Stretch

Describe how to obtain y=3x2y = 3x^2 from y=x2y = x^2. Is the graph narrower or wider?

Answer: Multiply outputs by 33 (stretch). Narrower.

Example 3 — Reflect and shift

Describe y=x2+4y = -x^2 + 4 as transformations of the parent, and give the vertex.

Reflect across the xx-axis, then shift up 44.

Answer: Vertex (0,4)(0, 4), a maximum. (Matches the opens-down panel of figure 3.)

Example 4 — Rational shrink

Compare y=12x2y = \tfrac12 x^2 to the parent at x=2x = 2.

Parent: 22=42^2 = 4. Transformed: 124=2\tfrac12 \cdot 4 = 2. The point (2,4)(2, 4) moves to (2,2)(2, 2).

Answer: Every output is halved; the graph is wider.

Example 5 — When transformations alone are not enough

Can you graph y=x24x5y = x^2 - 4x - 5 using only f(x)+kf(x) + k and kf(x)kf(x) applied to y=x2y = x^2?

No. Those two moves keep the axis at x=0x = 0. This parabola has axis x=2x = 2. Use the vertex formula and intercepts instead (figure 1).

Answer: Use characteristics (or technology), not parent transformations alone.

Guided practice

  1. Use the vertical-shift figure. Describe how y=x2+3y = x^2 + 3 and y=x24y = x^2 - 4 come from the parent, and name each vertex.
  2. Use the vertical-stretch figure. Match each equation y=2x2y = 2x^2, y=12x2y = \tfrac12 x^2, and y=x2y = -x^2 to stretch, shrink, or reflect.
  3. Starting from y=x2y = x^2, describe the transformations that produce y=2x2y = -2x^2.
  4. Starting from y=x2y = x^2, describe the transformations that produce y=12x23y = \tfrac12 x^2 - 3.
  5. On a blank grid, sketch y=x2+2y = x^2 + 2 and y=x2+2y = -x^2 + 2. Label the vertices.
  6. Explain why y=(x3)2y = (x - 3)^2 is not an A.F.2c transformation of the parent in this chapter's sense, even though it is a quadratic.

Independent practice

  1. Describe each as a transformation of y=x2y = x^2, and give the vertex. a) y=x27y = x^2 - 7 b) y=4x2y = 4x^2 c) y=x2+1y = -x^2 + 1 d) y=13x2+2y = \tfrac13 x^2 + 2
  2. Graph each on a blank grid (or with technology, then sketch). a) y=x2+4y = x^2 + 4 b) y=3x2y = -3x^2 c) y=12x22y = \tfrac12 x^2 - 2
  3. Reasoning. How can you tell from the equation y=kx2+cy = kx^2 + c whether the graph is narrower or wider than the parent?
  4. Error analysis. A student says y=x24xy = x^2 - 4x is the parent shifted left 44. Identify the error, and give the correct vertex using the formula.
  5. Application. A mirror is shaped like y=14x2y = \tfrac14 x^2 with distances in feet. Compared with y=x2y = x^2, is this mirror wider or narrower? What is its vertex?
  6. Graph y=x24x5y = x^2 - 4x - 5 by finding the vertex and intercepts (use figure 1 as a check), not by parent transformations.
  7. For y=x2+4y = -x^2 + 4, list the transformation sequence from the parent and confirm the range is y4y \le 4.
  8. Technology. Graph y=x2y = x^2, y=2x2y = 2x^2, and y=12x2y = \tfrac12 x^2 in the same window. Describe what you see.
  9. Write an equation for a parabola that is the parent reflected and shifted down 66.
  10. On a blank grid, sketch y=2x23y = 2x^2 - 3. Mark the vertex and yy-intercept.

Exit ticket 16.4

  1. Describe how to obtain y=x25y = x^2 - 5 from y=x2y = x^2.
  2. Describe how to obtain y=12x2y = \tfrac12 x^2 from y=x2y = x^2. Is it wider or narrower?
  3. Give the vertex of y=x2+9y = -x^2 + 9. Is it a max or a min?
  4. Why can f(x)+kf(x) + k and kf(x)kf(x) alone not produce y=x26x+5y = x^2 - 6x + 5 from the parent?

Lesson 16.5 — Standard Form, Factored Form, and the Graph

Two writings, one curve

A.F.2d asks you to connect the algebraic representations — standard form and factored form — to the graphical representation of a quadratic.

standard: y=ax2+bx+cfactored: y=a(xr)(xs)\text{standard: } y = ax^2 + bx + c \qquad \text{factored: } y = a(x - r)(x - s)

The parabola y equals x squared minus 6x plus 5, also written as y equals open parenthesis x minus 1 close parenthesis open parenthesis x minus 5 close parenthesis, with the same zeros at 1 and 5, same y-intercept 0 comma 5, and vertex 3 comma negative 4

The figure shows one curve with two writings: y=x26x+5y = x^2 - 6x + 5 and y=(x1)(x5)y = (x - 1)(x - 5). Expand the factored form:

(x1)(x5)=x26x+5(x - 1)(x - 5) = x^2 - 6x + 5

and you recover the standard form. Factor the standard form and you recover the factored form. Both name the same zeros, the same yy-intercept, and the same vertex.

What each form hands you for free

A two-panel reference: standard form hands you the y-intercept and opening direction for free and needs the vertex formula and solving for zeros; factored form hands you the zeros and opening for free and finds the axis as the midpoint of the zeros

Need Prefer
yy-intercept quickly Standard — read cc
Zeros / xx-intercepts quickly Factored — read rr and ss
Opening direction Either — read the sign of aa
Axis / vertex Factored: axis is x=r+s2x = \dfrac{r + s}{2}; standard: h=b2ah = -\dfrac{b}{2a}

Chapter 14 proved the forms are equal by expanding. This lesson uses that equality to read the graph.

Worked examples

Example 1 — From factored to graph

For y=(x1)(x5)y = (x - 1)(x - 5), name the zeros, axis, and yy-intercept.

Zeros 11 and 55. Axis x=1+52=3x = \dfrac{1 + 5}{2} = 3. yy-intercept: (01)(05)=5(0 - 1)(0 - 5) = 5, so (0,5)(0, 5).

Answer: Zeros 11, 55; axis x=3x = 3; yy-intercept (0,5)(0, 5). (Matches figure 8.)

Example 2 — From standard to factored

Write y=x26x+5y = x^2 - 6x + 5 in factored form.

x26x+5=(x1)(x5)x^2 - 6x + 5 = (x - 1)(x - 5).

Answer: y=(x1)(x5)y = (x - 1)(x - 5).

Example 3 — Vertex from factored form

Find the vertex of y=(x1)(x5)y = (x - 1)(x - 5).

Axis x=3x = 3. k=(31)(35)=(2)(2)=4k = (3 - 1)(3 - 5) = (2)(-2) = -4.

Answer: (3,4)(3, -4), a minimum.

Example 4 — Leading coefficient not 11

For y=2(x+1)(x3)y = -2(x + 1)(x - 3), name the zeros and opening direction.

Zeros x=1x = -1 and x=3x = 3. a=2<0a = -2 < 0, so opens down (maximum at the vertex).

Answer: Zeros 1-1 and 33; opens down.

Example 5 — Matching forms to features

Which form makes the yy-intercept of y=x26x+5y = x^2 - 6x + 5 obvious? Which makes the zeros obvious?

Answer: Standard makes (0,5)(0, 5) obvious. Factored makes zeros 11 and 55 obvious.

Guided practice

  1. Use the standard-and-factored figure. Write both forms of the graphed quadratic, and list the zeros and yy-intercept.
  2. Expand (x1)(x5)(x - 1)(x - 5) and confirm it matches the standard form in the figure.
  3. Use the forms-reference figure. For standard form, what is "free"? For factored form, what is "free"?
  4. Given y=(x+2)(x4)y = (x + 2)(x - 4), find the zeros, axis, yy-intercept, and vertex.
  5. Write y=x2+2x15y = x^2 + 2x - 15 in factored form, then name the zeros from that form.
  6. Explain in one or two sentences why expanding and factoring are reverse operations for connecting the two forms to one graph.

Independent practice

  1. For each factored form, name zeros, axis, yy-intercept, and vertex. a) y=(x2)(x6)y = (x - 2)(x - 6) b) y=(x+3)(x+1)y = (x + 3)(x + 1) c) y=(x1)(x5)y = - (x - 1)(x - 5)
  2. Write each in factored form (over the integers), then graph by characteristics on a blank grid. a) y=x25x+6y = x^2 - 5x + 6 b) y=x29y = x^2 - 9 c) y=x2+x12y = x^2 + x - 12
  3. Reasoning. A graph crosses the xx-axis at 4-4 and 22 and crosses the yy-axis at 8-8. Write a factored form with a=1a = 1 that matches the zeros, then check whether the yy-intercept is 8-8. If not, adjust aa.
  4. Error analysis. A student writes y=x26x+5y = x^2 - 6x + 5 as y=(x6)(x+5)y = (x - 6)(x + 5). Expand to show the error, and give the correct factorization.
  5. Application. A rectangular garden has width xx meters and length (10x)(10 - x) meters, so area A(x)=x(10x)A(x) = x(10 - x). Write AA in standard form, find the vertex, and interpret the maximum area in context.
  6. Connect y=x22x3y = x^2 - 2x - 3 (figure 2) to factored form, and verify the zeros match the graph.
  7. For y=2(x1)(x5)y = 2(x - 1)(x - 5), how do the zeros compare with figure 8? How does the vertex's yy-coordinate change?
  8. Technology. Enter both y=x26x+5y = x^2 - 6x + 5 and y=(x1)(x5)y = (x - 1)(x - 5) on the same graph. Confirm they coincide.
  9. Write a quadratic in standard form that has zeros 1-1 and 44 and yy-intercept 4-4.
  10. On a blank grid, sketch y=(x+2)(x4)y = (x + 2)(x - 4). Label zeros, yy-intercept, and vertex.

Exit ticket 16.5

  1. Write y=x26x+5y = x^2 - 6x + 5 in factored form.
  2. From y=(x1)(x5)y = (x - 1)(x - 5), name the zeros and the axis of symmetry.
  3. Find the vertex of y=(x1)(x5)y = (x - 1)(x - 5).
  4. Which form hands you the yy-intercept for free? Which hands you the zeros for free?

Lesson 16.6 — Evaluating f(x)f(x) and Finding xx

Two directions on the same curve

A.F.2g (quadratic half) asks two related skills:

  1. Given xx in the domain, determine f(x)f(x).
  2. Given a value of f(x)f(x) in the range, determine xx (every input that works).
  3. Explain what xx and f(x)f(x) mean in context.

The parabola f of x equals x squared minus 4x plus 3 with f of 5 equals 8 marked, and a dashed line at height 3 meeting the curve at x equals 0 and x equals 4

Evaluating reads a height at a chosen input: f(5)=2520+3=8f(5) = 25 - 20 + 3 = 8. Solving f(x)=3f(x) = 3 finds every input at that height. From the figure — or from algebra —

x24x+3=3    x24x=0    x(x4)=0x^2 - 4x + 3 = 3 \implies x^2 - 4x = 0 \implies x(x - 4) = 0

so x=0x = 0 or x=4x = 4. A horizontal line through a height on a parabola often meets the curve twice. That is expected, not a mistake.

In context

If h(t)h(t) is height in feet after tt seconds, then:

Reject a solution that the story cannot use (negative time, and so on), with a stated reason — the same discipline as Chapter 15.

Worked examples

Example 1 — Evaluate

For f(x)=x24x+3f(x) = x^2 - 4x + 3, find f(5)f(5) and f(0)f(0).

f(5)=8f(5) = 8, f(0)=3f(0) = 3.

Answer: f(5)=8f(5) = 8; f(0)=3f(0) = 3.

Example 2 — Find xx

Solve f(x)=3f(x) = 3 for f(x)=x24x+3f(x) = x^2 - 4x + 3.

Answer: x=0x = 0 or x=4x = 4.

Example 3 — Find xx with two irrational answers

For g(x)=x22x3g(x) = x^2 - 2x - 3, solve g(x)=5g(x) = 5.

x22x3=5    x22x8=0    (x4)(x+2)=0x^2 - 2x - 3 = 5 \implies x^2 - 2x - 8 = 0 \implies (x - 4)(x + 2) = 0.

Answer: x=4x = 4 or x=2x = -2.

Example 4 — Context

Using h(t)=16t2+48th(t) = -16t^2 + 48t, find h(1)h(1) and explain. Then solve h(t)=32h(t) = 32 and interpret.

h(1)=16+48=32h(1) = -16 + 48 = 32: at 11 second, the height is 3232 feet.

16t2+48t=32    16t248t+32=0    t23t+2=0    (t1)(t2)=0-16t^2 + 48t = 32 \implies 16t^2 - 48t + 32 = 0 \implies t^2 - 3t + 2 = 0 \implies (t - 1)(t - 2) = 0.

Answer: t=1t = 1 or t=2t = 2 seconds — once going up, once coming down — the height is 3232 feet.

Example 5 — Output not in range

Does f(x)=x24x+3f(x) = x^2 - 4x + 3 ever equal 5-5?

The minimum is f(2)=1f(2) = -1. The range is y1y \ge -1, so 5-5 is not an output.

Answer: No real xx; 5-5 is not in the range.

Guided practice

  1. Use the evaluating figure. Find f(5)f(5) from the graph and by substitution.
  2. Using that same figure, solve f(x)=3f(x) = 3 and mark both inputs.
  3. For f(x)=x24x+3f(x) = x^2 - 4x + 3, find f(2)f(2) (the vertex height) and f(1)f(1).
  4. Solve f(x)=0f(x) = 0 for that same ff. How do the solutions relate to the xx-intercepts?
  5. Using h(t)=16t2+48th(t) = -16t^2 + 48t, find h(1.5)h(1.5) and explain what it means.
  6. Explain in one or two sentences why solving f(x)=cf(x) = c for a quadratic can give two answers.

Independent practice

  1. Let f(x)=x26x+5f(x) = x^2 - 6x + 5. a) Find f(0)f(0), f(3)f(3), and f(7)f(7). b) Solve f(x)=5f(x) = 5. c) Solve f(x)=4f(x) = -4.
  2. Let g(x)=x2+4g(x) = -x^2 + 4. a) Find g(0)g(0) and g(1)g(1). b) Solve g(x)=0g(x) = 0. c) Solve g(x)=3g(x) = 3.
  3. Application. Using h(t)=16t2+48th(t) = -16t^2 + 48t and the projectile figure, find h(0.5)h(0.5) and explain. Then solve h(t)=0h(t) = 0 and interpret both solutions in context.
  4. Application. Revenue R(x)=x2+40xR(x) = -x^2 + 40x dollars from xx items. Find R(10)R(10) and explain. Then find every xx for which R(x)=300R(x) = 300, and interpret.
  5. Reasoning. Why does f(x)=x24x+3f(x) = x^2 - 4x + 3 fail to equal 5-5 for any real xx? Connect your answer to the vertex.
  6. Error analysis. A student solves f(x)=3f(x) = 3 for f(x)=x24x+3f(x) = x^2 - 4x + 3 and reports only x=0x = 0. What did the student miss?
  7. Solve f(x)=8f(x) = 8 for f(x)=x24x+3f(x) = x^2 - 4x + 3. Confirm one solution with the evaluating figure.
  8. Technology. For f(x)=x24x+3f(x) = x^2 - 4x + 3, use a table or trace feature to confirm f(5)=8f(5) = 8 and the two inputs for f(x)=3f(x) = 3.
  9. A ball's height is h(t)=16t2+32t+48h(t) = -16t^2 + 32t + 48. Find h(0)h(0) and explain. Solve h(t)=48h(t) = 48 and interpret; reject any impossible time with a reason.
  10. On a blank grid, sketch y=x24x+3y = x^2 - 4x + 3, draw the line y=3y = 3, and mark the intersection inputs.

Exit ticket 16.6

  1. For f(x)=x24x+3f(x) = x^2 - 4x + 3, find f(6)f(6).
  2. Solve f(x)=3f(x) = 3 for that same ff.
  3. Using h(t)=16t2+48th(t) = -16t^2 + 48t, explain what h(1)=32h(1) = 32 means in a sentence.
  4. Why can a quadratic f(x)=cf(x) = c have two solutions while a linear f(x)=cf(x) = c has at most one?

Chapter 16 Review

Vocabulary. quadratic function · parabola · parent function y=x2y = x^2 · vertex · axis of symmetry · maximum · minimum · opens up · opens down · zero · xx-intercept · yy-intercept · domain · range · context restriction · vertical shift f(x)+kf(x) + k · vertical stretch / shrink / reflection kf(x)kf(x) · standard form · factored form · evaluate · solve f(x)=cf(x) = c

A.F.2 b, c, d, and g (quadratic) ask different kinds of question, so this review is organized by bullet.

Part A — Key characteristics (A.F.2b)

  1. For y=x22x3y = x^2 - 2x - 3, list zeros, yy-intercept, vertex (max or min), domain, and range.
  2. For h(t)=16t2+48th(t) = -16t^2 + 48t in the projectile context, give domain and range in context and interpret the vertex.

Part B — Graphing and transformations (A.F.2c)

  1. Describe y=2x2+3y = -2x^2 + 3 as transformations of y=x2y = x^2, and give the vertex.
  2. Graph y=12x24y = \tfrac12 x^2 - 4 on a blank grid by transformations, and graph y=x24x5y = x^2 - 4x - 5 by characteristics. Say which strategy you used for each.

Part C — Standard and factored forms (A.F.2d)

  1. Write y=x26x+5y = x^2 - 6x + 5 in factored form. Show that both forms give the same zeros and the same yy-intercept, matching figure 8.

Part D — Evaluate and recover xx (A.F.2g)

  1. For f(x)=x24x+3f(x) = x^2 - 4x + 3, find f(5)f(5) and solve f(x)=3f(x) = 3. Then, for h(t)=16t2+48th(t) = -16t^2 + 48t, explain what each solution of h(t)=32h(t) = 32 means in context.

Standards coverage check — Chapter 16

Knowledge and Skill Aspect Where it is taught Where it is practiced Where it is interpreted in context
A.F.2b — key characteristics from equation or graph Vertex / axis / max vs min 16.1 (fig1, fig3, fig5) 1–20, 25, 29, 34, 38, 121 13, 33, 48, 122
A.F.2b Zeros / xx-intercepts / yy-intercept 16.2 (fig2) 21–40, 121 33, 109
A.F.2b Domain and range 16.3 (fig2, fig4) 41–60, 121, 122 43, 44, 48, 49, 52, 59, 122
A.F.2b Interpret in context 16.3 (fig4); 16.6 13, 33, 48, 49, 52, 91, 105, 109, 110, 115, 122, 126 48, 49, 91, 109, 110, 122, 126
A.F.2c — graph using strategies including f(x)+kf(x)+k and kf(x)kf(x) Vertical shift / stretch / reflect 16.4 (fig5–fig7, fig10) 61–80, 123, 124 71
A.F.2c Graph by characteristics when b0b \neq 0 16.4; 16.2 72, 76, 124
A.F.2d — connect standard and factored forms to the graph Expand / factor; read features 16.5 (fig8, fig11) 81–100, 125 91
A.F.2g — determine f(x)f(x); for quadratic, determine xx given f(x)f(x); explain in context Evaluate / solve f(x)=cf(x)=c / explain 16.6 (fig9) 101–120, 126 105, 109, 110, 115, 119, 126

Supporting items: 6, 10, 16, 20, 26, 31, 40, 45, 50, 56, 60, 66, 69, 80, 86, 100, 106, 111, 120 are reasoning items aimed at the chapter's structural ideas — axis as mirror, why a0a \neq 0, zero versus intercept, midpoint axis from two zeros, context versus equation domain, and why A.F.2c transformations cannot move the axis. Error analyses 11, 32, 51, 70, 90, 112 target the most common failures: calling a maximum a minimum, dropping the sign in b2a-\dfrac{b}{2a}, treating a non-context graph as a height, inventing a horizontal shift, mis-factoring, and dropping one solution of f(x)=cf(x) = c.

Boundaries respected. Transformations are limited to f(x)+kf(x) + k and kf(x)kf(x) with rational kk; no item teaches a horizontal-shift transformation rule for the parent. Exponential functions are never introduced (Chapter 17). Family comparison of linear, quadratic, and exponential is never asked (Chapter 18). Solving quadratic equations is used as a tool for zeros and for f(x)=cf(x) = c, not re-taught as Chapter 15's end goal. Vertex form may appear as a reading aid from Chapter 14, but the graphing strategies practiced are A.F.2c's two named moves plus plotting from characteristics.

Answer keys for every item in this chapter are in Appendix A.