MathBored

Virginia SOL Mathematics Textbook

Geometry Workbook — Chapter 16: Surface Area and Volume of Solids

SOL G.DF.1 (a, b, c, d) · Companion to Textbook Chapter 16

Each page below is one Canva page. Headings are sized for direct paste: page title as H1, section labels as H2. Figures referenced by filename live in ../figures/. Every numbered item is the same problem as in the textbook, so one answer key serves both. Item numbers run continuously from 1 to 124.


PAGE 1 — Chapter opener

Chapter 16 · Surface Area and Volume of Solids

Standard G.DF.1 (a, b, c, d)

In this chapter you will:

Words to know: cross section · prism · cylinder · cone · pyramid · sphere · hemisphere · apex · slant height · lateral surface · composite solid

Conventions: a slant height ll is always found with the Pythagorean Theorem, never given directly. Answers with π\pi stay an exact coefficient, never a rounded decimal. A composite solid's surface area adds each piece's full surface area, then subtracts the shared face TWICE.


PAGE 2 — The whole chapter on one page

One Idea, Five Solids

solid volume needs surface area needs
rectangular prism ll, ww, hh same three, doubled three ways
triangular prism triangle's area, depth triangle's area and perimeter, depth
cylinder rr, hh rr, hh
cone rr, hh rr, and ll — found from rr and hh
square pyramid bb, hh bb, and ll — found from bb and hh
sphere rr only rr only

Every "surface area needs" column that mentions ll is a formula the EOC formula sheet cannot finish for you — ll always has to be found first, with the Pythagorean Theorem.


PAGE 3 — Cuts parallel to the base

16.1 The Simplest Cut

FIGURE: fig1-cross-sections-parallel-to-the-base.png (full width)

Fill in.

prism → ______________    cylinder → ______________    cone → ______________    sphere → ______________

Which one of these four shrinks as the cut moves toward the top? ______________


PAGE 4 — Cuts through the axis or the apex

16.1 A Different Kind of Cut

FIGURE: fig2-cross-sections-through-the-apex.png (full width)

Fill in.

cylinder through its axis → ______________    cone through its apex → ______________    pyramid through its apex → ______________


PAGE 5 — Guided practice 16.1

Work Through It

  1. Name the shape from the prism's cut, and say whether it stays the same size everywhere. ______
  2. Name the shape from the cylinder's cut and the cone's cut. What's the one difference? ______
  3. Name the shape from the sphere's cut. Why doesn't a sphere need the word "parallel"? ______
  4. Name the shape from the cylinder cut through its axis. ______
  5. Name the shape from the cone and the pyramid cut through the apex. What do the two cuts have in common? ______
  6. What single fact about the cutting plane decides which family of shapes results? ______

PAGE 6 — Name the shape

16.1 Name It

Name the two-dimensional shape produced by each cut.

  1. A cylinder is cut by a plane parallel to its base. ______
  2. A cylinder is cut by a plane containing its axis. ______
  3. A cone is cut by a plane parallel to its base, partway up. ______
  4. A cone is cut through its apex, perpendicular to its base. ______
  5. A square pyramid is cut through its apex, perpendicular to its base. ______
  6. A square pyramid is cut by a plane parallel to its base. ______
  7. A rectangular prism is cut by a plane parallel to one of its rectangular faces. ______
  8. A triangular prism is cut by a plane parallel to its triangular base. ______

PAGE 7 — Name it, and explain it

16.1 Finish the Set

  1. A triangular prism is cut by a plane parallel to one of its rectangular side faces. ______

  2. A sphere is cut by a plane through its center. ______

  3. A sphere is cut by a plane that misses the center. ______

  4. A cylinder is cut by a plane parallel to its base, close to one end. ______

  5. Application. A carpenter saws through a triangular-prism doorstop, parallel to its triangular ends. Name the exposed shape. ______

  6. Error analysis. A student claims a cone's parallel cross section is always the same size as the base. Explain the error. ______

  7. Reasoning. Why is a sphere's cross section always a circle, while a cylinder's or cone's is only a circle for cuts parallel to the base? ______

Exit ticket 16.1

  1. A plane cuts a cylinder parallel to its base. Name the shape, and say whether its size depends on where the cut is made. ______
  2. A plane cuts a square pyramid through its apex. Name the shape. ______

PAGE 8 — A rectangular prism

16.2 Three Pairs of Matching Faces

FIGURE: fig3-rectangular-prism.png (full width)

V=lwhSA=2(lw+lh+wh)V = lwh \qquad SA = 2(lw+lh+wh)

Volume multiplies the three edges once. Surface area adds all six faces — three matching pairs, so each product is doubled.


PAGE 9 — A triangular prism

16.2 Area Times Depth

FIGURE: fig4-triangular-prism.png (full width)

V=(area)(depth)SA=2(area)+(perimeter)(depth)V = (\text{area})(\text{depth}) \qquad SA = 2(\text{area}) + (\text{perimeter})(\text{depth})

The triangle's equal side is not given — it's the hypotenuse of the right triangle formed by half the base and the height.


PAGE 10 — Guided practice 16.2

Work Through It

  1. Identify ll, ww, hh on the rectangular prism, and give VV. ______
  2. Give its SASA, and explain why lwlw, lhlh, whwh are each doubled. ______
  3. Identify the base, height, and depth on the triangular prism, and give the triangle's area. ______
  4. Explain how the equal side of 55 was found, and give the perimeter. ______
  5. Give the triangular prism's volume. ______
  6. Give its surface area, and name the "two matching ends." ______

PAGE 11 — Rectangular prisms

16.2 Find V and SA

Find the volume and surface area.

  1. l=2l=2, w=3w=3, h=4h=4 ______
  2. l=5l=5, w=4w=4, h=3h=3 ______
  3. l=7l=7, w=3w=3, h=2h=2 ______
  4. l=9l=9, w=5w=5, h=2h=2 ______
  5. a cube with edge length 66 ______
  6. l=8l=8, w=4w=4, h=5h=5 ______
  7. l=10l=10, w=2w=2, h=2h=2 ______
  8. l=12l=12, w=5w=5, h=3h=3 ______

PAGE 12 — Triangular prisms

16.2 Find the Leg First

Find the equal side, then the volume and surface area.

  1. base 1212, height 88, depth 55 ______

  2. base 1010, height 1212, depth 77 ______

  3. base 1616, height 1515, depth 66 ______

  4. base 1818, height 1212, depth 44 ______

  5. Application. A cedar chest is 44 ft by 22 ft by 33 ft. Find its volume and surface area. ______

  6. Error analysis. A student computes SA=2lwh=2(60)=120SA=2lwh=2(60)=120 for l=5,w=4,h=3l=5,w=4,h=3. Find the error and the correct SASA. ______

  7. Reasoning. Why are the two prisms' SASA formulas really the same idea? ______

Exit ticket 16.2

  1. l=6l=6, w=3w=3, h=2h=2. Find VV and SASA. ______
  2. Triangular prism: base 1212, height 88, depth 33. Find VV and SASA. ______

PAGE 13 — A cylinder

16.3 Two Circles and a Rolled-Up Rectangle

FIGURE: fig5-cylinder.png (full width)

V=πr2hSA=2πr2+2πrhV = \pi r^2h \qquad SA = 2\pi r^2+2\pi rh


PAGE 14 — A cone

16.3 One Circle, One Point

FIGURE: fig6-cone.png (full width)

V=13πr2hSA=πr2+πrll2=r2+h2V = \frac{1}{3}\pi r^2h \qquad SA=\pi r^2+\pi rl \qquad l^2=r^2+h^2

A cone's volume is always exactly 13\frac{1}{3} of a cylinder's with the same rr and hh.


PAGE 15 — Guided practice 16.3

Work Through It

  1. Identify rr and hh on the cylinder, and give VV. ______
  2. Give its SASA. What does 2πrh2\pi rh represent if the side were unrolled flat? ______
  3. Identify rr and hh on the cone, and find ll. ______
  4. Give the cone's volume. ______
  5. Give its SASA. Why only one πr2\pi r^2 term, not two? ______
  6. Both formulas start with πr2\pi r^2. What does that term represent in each solid? ______

PAGE 16 — Cylinders

16.3 Find V and SA

Find the volume and surface area.

  1. r=4r=4, h=10h=10 ______
  2. r=5r=5, h=6h=6 ______
  3. r=2r=2, h=9h=9 ______
  4. r=7r=7, h=10h=10 ______
  5. r=3r=3, h=12h=12 ______

PAGE 17 — Cones

16.3 Find l First

Find the slant height, then the volume and surface area.

  1. r=6r=6, h=8h=8 ______

  2. r=5r=5, h=12h=12 ______

  3. r=8r=8, h=15h=15 ______

  4. r=9r=9, h=12h=12 ______

  5. r=7r=7, h=24h=24 ______

  6. Application. A rain barrel: r=4r=4 ft, h=9h=9 ft. Find VV and SASA. ______

  7. Error analysis. A student uses SA=πr2+πrhSA=\pi r^2+\pi rh for r=5,h=12r=5,h=12, getting 85π85\pi. Find ll and the correct SASA. ______

  8. Reasoning. Why is a cone's volume always 13\frac{1}{3} of a same-rr-and-hh cylinder's? ______

Exit ticket 16.3

  1. r=6r=6, h=5h=5 (cylinder). Find VV and SASA. ______
  2. r=12r=12, h=16h=16 (cone). Find ll, then VV and SASA. ______

PAGE 18 — A square pyramid

16.4 The Apex-to-Edge-Midpoint Triangle

FIGURE: fig7-square-pyramid.png (full width)

V=13b2hSA=b2+2bll2=(b2)2+h2V=\frac{1}{3}b^2h \qquad SA=b^2+2bl \qquad l^2=\left(\frac{b}{2}\right)^2+h^2

ll runs to the MIDDLE of a base edge, not to a corner.


PAGE 19 — A sphere

16.4 One Measurement Does It All

FIGURE: fig8-sphere.png (full width)

V=43πr3SA=4πr2V=\frac{4}{3}\pi r^3 \qquad SA=4\pi r^2


PAGE 20 — All five, side by side

16.4 The Formula Board

FIGURE: fig9-formula-board.png (full width)

The formula sheet supplies every line here — except ll, which you always find yourself.


PAGE 21 — Guided practice 16.4

Work Through It

  1. Identify b2\frac{b}{2} and hh on the pyramid, and find ll. ______
  2. Give the pyramid's volume. ______
  3. Give its SASA. Where does 2bl2bl come from? ______
  4. Identify rr on the sphere, and give VV. ______
  5. Give the sphere's SASA. Why only one measurement needed? ______
  6. On the formula board, which two formulas need a value it doesn't supply? ______

PAGE 22 — Square pyramids

16.4 Find l First

Find the slant height, then the volume and surface area.

  1. b=6b=6, h=4h=4 ______
  2. b=12b=12, h=8h=8 ______
  3. b=10b=10, h=12h=12 ______
  4. b=16b=16, h=15h=15 ______
  5. b=18b=18, h=12h=12 ______

PAGE 23 — Spheres

16.4 Find V and SA

Find the volume and surface area.

  1. r=3r=3 ______

  2. r=9r=9 ______

  3. r=12r=12 ______

  4. r=15r=15 ______

  5. Application. A pyramid monument: square base 4040 ft, height 1515 ft. Find VV, and the four triangular faces' area. ______

  6. Error analysis. A student computes V=b2h=1200V=b^2h=1200 for b=10,h=12b=10,h=12, forgetting 13\frac{1}{3}. Find the correct VV. ______

  7. Reasoning. A sphere with r=3r=3 has V=SA=36πV=SA=36\pi. Why does r=3r=3 do this, and why doesn't it mean VV and SASA are the same kind of quantity? ______

Exit ticket 16.4

  1. b=14b=14, h=24h=24 (pyramid). Find ll, then VV and SASA. ______
  2. r=6r=6 (sphere). Find VV and SASA. ______

PAGE 24 — A silo

16.5 Cylinder and Hemisphere

FIGURE: fig10-silo.png (full width)

Add each piece's full SASA, then subtract the shared circle TWICE.


PAGE 25 — A house

16.5 Box and Triangular-Prism Roof

FIGURE: fig11-house.png (full width)

SA=(box full SA)+(roof full SA)2(shared rectangle)SA = (\text{box full } SA)+(\text{roof full } SA)-2(\text{shared rectangle})


PAGE 26 — An ice-cream cone

16.5 Cone and Hemisphere

FIGURE: fig12-ice-cream-cone.png (full width)

Neither piece keeps a flat circular face here — their one flat face is the SAME shared circle.


PAGE 27 — Guided practice 16.5

Work Through It

  1. Identify the silo's cylinder rr, hh, and hemisphere radius. ______
  2. Give the silo's total volume. Why is the hemisphere's own flat circle left out of SASA? ______
  3. Identify the house's box and roof dimensions, and the shared face's area. ______
  4. Give the house's total VV and SASA. Why subtract the shared face twice? ______
  5. Identify the ice-cream cone's shared radius. Why does neither piece keep a flat face? ______
  6. Give the ice-cream cone's total VV and SASA. ______

PAGE 28 — Build the composite

16.5 Find Total V and SA

Find the total volume and total surface area.

  1. Cylinder (r=4,h=10r=4,h=10) + cone (r=4,h=3r=4,h=3) — a pencil. ______

  2. Box (6×6×56\times6\times5) + square pyramid (b=6,h=4b=6,h=4) — a tent. ______

  3. Cylinder (r=6,h=10r=6,h=10) + hemisphere (r=6r=6) — a larger silo. ______

  4. Cone (r=6,h=8r=6,h=8) + hemisphere (r=6r=6) — a larger ice-cream cone. ______

  5. Cylinder (r=6,h=10r=6,h=10) + hemispheres (r=6r=6) on BOTH ends — a capsule. ______

  6. Error analysis. A student adds the silo's cylinder full SASA (66π66\pi) to the hemisphere's full SASA (27π27\pi), getting 93π93\pi. Which circle was double-counted? Give the correct SASA. ______

  7. Reasoning. Why does "add full areas, subtract the shared face twice" always match counting only the exposed faces directly? ______

Exit ticket 16.5

  1. For the silo, name the circle subtracted twice, and give its area. ______
  2. Cone (r=3,h=4r=3,h=4) + hemisphere (r=3r=3). Find total VV and SASA, and list every included surface. ______

PAGE 29 — Two ways to work backward

16.6 Same Formula, Different Letter

FIGURE: fig13-working-backward.png (full width)

100π=π(5)2hh=4100\pi=\pi(5)^2h \rightarrow h=4

96=62+2(6)ll=5h2=5232=16h=496=6^2+2(6)l \rightarrow l=5 \rightarrow h^2=5^2-3^2=16 \rightarrow h=4

Substitute everything known, then undo the remaining arithmetic one step at a time. Surface area often takes an extra Pythagorean Theorem step that volume never needs.


PAGE 30 — Guided practice 16.6

Work Through It

  1. Identify what's given and unknown in the cylinder problem. ______
  2. Show the substitution and solve for hh. ______
  3. Identify what's given and unknown in the pyramid problem. ______
  4. Solve for ll first. ______
  5. Use ll to find hh. ______
  6. Compare the two problems: same strategy, different number of steps — explain. ______

PAGE 31 — Solve for the missing dimension

16.6 Find It

  1. Rectangular prism: V=150V=150, l=10l=10, w=5w=5. Find hh. ______
  2. Rectangular prism: SA=94SA=94, l=5l=5, w=4w=4. Find hh. ______
  3. Cylinder: V=98πV=98\pi, r=7r=7. Find hh. ______
  4. Cylinder: SA=136πSA=136\pi, r=4r=4. Find hh. ______
  5. Cone: V=48πV=48\pi, r=6r=6. Find hh. ______
  6. Cone: SA=90πSA=90\pi, r=5r=5. Find ll, then hh. ______

PAGE 32 — Finish the set

16.6 Find It

  1. Sphere: V=972πV=972\pi. Find rr. ______

  2. Sphere: SA=400πSA=400\pi. Find rr. ______

  3. Square pyramid: V=400V=400, b=10b=10. Find hh, then ll. ______

  4. Triangular prism: V=180V=180, base 66, height 44. Find the depth. ______

  5. Triangular prism: SA=152SA=152, base 66, height 44. Find the depth. ______

  6. Application. A silo holds 250π250\pi ft³, r=5r=5 ft. Find its height. ______

  7. Error analysis. For V=200πV=200\pi, r=5r=5, a student writes 200π=π(5)h200\pi=\pi(5)h and gets h=40h=40. Find the mistake and the correct hh. ______

  8. Reasoning. Why is working backward from surface area often longer than from volume, for a cone or pyramid? ______

Exit ticket 16.6

  1. Cylinder: V=48πV=48\pi, r=4r=4. Find hh. ______
  2. Cone: SA=216πSA=216\pi, r=9r=9. Find ll, then hh. ______

PAGE 33 — Blank solids

Your Turn

FIGURE: fig14-blank-solid-frames.png (full width)

For every problem in this chapter:


PAGE 34 — Chapter review

Chapter 16 Review

Review 1 (G.DF.1a). A rectangular prism, a cylinder, a cone, and a sphere sit on a table.

Review 2 (G.DF.1 b, c). A shed is a rectangular prism 88 ft by 66 ft by 77 ft, topped with a triangular-prism roof (triangular base 66 ft, height 44 ft, running the full 88-ft length).

Review 3 (G.DF.1d). A cone has surface area 90π90\pi and radius 55.