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Virginia SOL Mathematics Textbook

Geometry Workbook — Chapter 15: Equations of Circles

SOL G.PC.4 (a, b) · Companion to Textbook Chapter 15

Each page below is one Canva page. Headings are sized for direct paste: page title as H1, section labels as H2. Figures referenced by filename live in ../figures/. Every numbered item is the same problem as in the textbook, so one answer key serves both. Item numbers run continuously from 1 to 112.


PAGE 1 — Chapter opener

Chapter 15 · Equations of Circles

Standard G.PC.4 (a, b)

In this chapter you will:

Words to know: standard form · center · radius · Pythagorean Theorem · leg · hypotenuse · diameter · midpoint · simplest radical form

Conventions: standard form is (xh)2+(yk)2=r2(x-h)^2+(y-k)^2=r^2. Both terms are subtractions — a negative center coordinate flips the sign you see. The right side is r2r^2, not rr. Radii are given in simplest radical form, never a rounded decimal.


PAGE 2 — The whole chapter on one page

One Triangle, Four Problem Types

you are given you find how
equation, standard form center and radius read hh, kk; take  \sqrt{\ } of the right side
a graph of the circle center and radius read the center; measure to the edge
a diameter's endpoints the equation center = midpoint; rr = distance to an endpoint
center and one point on it the equation rr = distance from center to the point

Every row ends at a center and a radius — the only two numbers a circle's equation ever needs.

Before every problem:


PAGE 3 — The right triangle inside every circle

15.1 Where the Equation Comes From

FIGURE: fig1-deriving-the-equation.png (full width)

Fill in from the figure.

Horizontal leg: ____________________ Vertical leg: ____________________ Hypotenuse: ____________________

(x__)2+(y__)2=__2(x - \_\_)^2 + (y - \_\_)^2 = \_\_^2


PAGE 4 — The origin case

15.1 When the Center Is (0, 0)

FIGURE: fig2-circle-at-the-origin.png (full width)

x2+y2=r2x^2 + y^2 = r^2

Not a different formula — the h=0h = 0, k=0k = 0 case of the same one.


PAGE 5 — Writing from center and radius

15.1 No Point to Measure To

FIGURE: fig6-writing-from-center-and-radius.png (full width)

Copy the three steps, in order.

Step one: ____________________ Step two: ____________________ Step three: ____________________


PAGE 6 — Guided practice 15.1

Work Through It

  1. Name the two legs of the right triangle and what each one measures. ______
  2. Name the hypotenuse and give the equation it produces. ______
  3. Give the equation shown and identify hh and kk. ______
  4. Explain why a center at the origin shortens the equation. ______
  5. Give the center and the radius shown. ______
  6. Give the three steps that turn a center and a radius into an equation. ______

PAGE 7 — Write it

15.1 Center and Radius to Equation

Give the equation.

  1. center (0,0)(0, 0), radius 33 ______
  2. center (0,0)(0, 0), radius 88 ______
  3. center (4,0)(4, 0), radius 55 ______
  4. center (0,6)(0, -6), radius 66 ______
  5. center (5,2)(5, 2), radius 77 ______
  6. center (3,1)(-3, 1), radius 44 ______
  7. center (2,5)(-2, -5), radius 99 ______
  8. center (6,4)(6, -4), radius 1010 ______

PAGE 8 — On the circle, or not?

15.1 Check It

Answer yes or no.

  1. (3,4)(3, 4) on x2+y2=25x^2+y^2=25 ______
  2. (2,2)(2, 2) on x2+y2=9x^2+y^2=9 ______
  3. (7,1)(7, 1) on (x3)2+(y1)2=16(x-3)^2+(y-1)^2=16 ______
  4. (5,5)(5, 5) on (x1)2+(y2)2=25(x-1)^2+(y-2)^2=25 ______
  5. (0,0)(0, 0) on (x3)2+(y4)2=25(x-3)^2+(y-4)^2=25 ______
  6. (1,1)(1, 1) on (x+2)2+(y3)2=20(x+2)^2+(y-3)^2=20 ______

PAGE 9 — Derive it

15.1 Center and a Point

Derive the equation.

  1. center (0,0)(0, 0), point (6,8)(6, 8) ______

  2. center (1,1)(1, 1), point (4,5)(4, 5) ______

  3. center (2,3)(-2, 3), point (1,1)(1, -1) ______

  4. Application. A fountain is centered at the origin of a park's grid, in meters, and its edge reaches (9,12)(9, 12). Give its equation.

  5. Error analysis. A student derives center (2,3)(2, -3), radius 55 as (x+2)2+(y3)2=25(x+2)^2+(y-3)^2=25. Identify and correct the sign errors.

  6. Reasoning. Explain why the right side is r2r^2, not rr, tracing back to the right triangle.

Exit ticket 15.1

  1. Give the equation with center (0,5)(0, 5) and radius 33. ______
  2. Is (4,3)(4, 3) on x2+y2=25x^2+y^2=25? Justify using the Pythagorean Theorem. ______

PAGE 10 — Anatomy of the equation

15.2 Every Equation Has This Shape

FIGURE: fig3-anatomy-of-the-equation.png (full width)

Fill in.

The number subtracted from xx is ______. The number subtracted from yy is ______.

A negative center coordinate makes the sign you see ____________________.

The number on the right is ______, not rr — finding the radius costs one ____________________.


PAGE 11 — A table of them

15.2 Read the Equation, Write Down Two Things

FIGURE: fig4-reading-center-and-radius.png (full width)


PAGE 12 — Reading a graph

15.2 No Equation — Just the Picture

FIGURE: fig5-reading-a-graph.png (full width)

The radius is easiest to read straight up, down, left, or right from the center — where the circle crosses a grid line exactly.


PAGE 13 — When the radius is a radical

15.2 Not Every Radius Is a Whole Number

FIGURE: fig9-radius-in-radical-form.png (full width)

r2=__2+__2=__    r=____r^2 = \_\_^2 + \_\_^2 = \_\_ \;\rightarrow\; r = \_\_\_\_


PAGE 14 — Guided practice 15.2

Work Through It

  1. Give the center and the radius shown. ______
  2. Explain why the center's negative xx-coordinate makes the equation show a plus sign. ______
  3. Give the center and the radius directly from the picture. ______
  4. Say which directions are easiest to measure a radius along, and why. ______
  5. Give the equation, center, and radius from the radical row of the table. ______
  6. Give the two legs, r2r^2, and the radius in simplest radical form. ______

PAGE 15 — Read it

15.2 Equation to Center and Radius

Give the center and radius.

  1. (x4)2+(y1)2=36(x-4)^2+(y-1)^2=36 ______
  2. (x+2)2+(y5)2=49(x+2)^2+(y-5)^2=49 ______
  3. (x6)2+(y+3)2=64(x-6)^2+(y+3)^2=64 ______
  4. x2+(y7)2=81x^2+(y-7)^2=81 ______
  5. (x+5)2+y2=100(x+5)^2+y^2=100 ______
  6. (x1)2+(y+8)2=144(x-1)^2+(y+8)^2=144 ______
  7. (x+9)2+(y+2)2=169(x+9)^2+(y+2)^2=169 ______
  8. x2+y2=121x^2+y^2=121 ______

PAGE 16 — Radical radii

15.2 Simplest Radical Form

Give the center and radius.

  1. (x2)2+(y1)2=18(x-2)^2+(y-1)^2=18 ______
  2. (x+1)2+(y4)2=20(x+1)^2+(y-4)^2=20 ______
  3. x2+(y+3)2=50x^2+(y+3)^2=50 ______
  4. (x3)2+y2=45(x-3)^2+y^2=45 ______

PAGE 17 — Graphs, and back to writing

15.2 Both Directions

  1. Center (2,3)(2, -3), through (2,4)(2, 4) straight up. Give rr and the equation. ______
  2. Center (5,1)(-5, 1), through (1,1)(1, 1) straight across. Give rr and the equation. ______
  3. Center (0,0)(0, 0), through (0,9)(0, -9). Give rr and the equation. ______

Give the equation.

  1. center (7,5)(7, -5), radius 232\sqrt3 ______

  2. center (6,6)(-6, -6), radius 1515 ______

  3. Application. A cell tower at (5,2)(5, -2) on a town's grid, in miles, has signal reaching (5,6)(5, 6). Confirm rr and give the equation.

  4. Error analysis. A student reads (x4)2+(y+2)2=49(x-4)^2+(y+2)^2=49 as center (4,2)(4, 2), radius 4949. Identify both mistakes.

  5. Reasoning. Explain why finding rr from an equation needs a square root but finding the center does not.

Exit ticket 15.2

  1. Give the center and radius of (x+3)2+(y6)2=40(x+3)^2+(y-6)^2=40, radius in simplest radical form. ______
  2. Center (1,4)(1, 4), through (1,2)(1, -2). Give rr and the equation. ______

PAGE 18 — Center and a point on the circle

15.3 One Point Pins Down the Radius

FIGURE: fig7-center-and-a-point.png (full width)

r2=__2+__2=__    r=__r^2 = \_\_^2+\_\_^2=\_\_ \;\rightarrow\; r=\_\_


PAGE 19 — The endpoints of a diameter

15.3 The Circle in Disguise

FIGURE: fig8-diameter-endpoints.png (full width)


PAGE 20 — Guided practice 15.3

Work Through It

  1. Give the two legs of the triangle and the radius they produce. ______
  2. Give the resulting equation. ______
  3. Give the center's coordinates, and explain how you found them. ______
  4. Give the radius, and name the segment you measured. ______
  5. Explain what goes wrong if the full diameter is used as the radius. ______
  6. Compare the two methods: what step is shared, and what step is different? ______

PAGE 21 — Center and a point

15.3 Write the Equation

  1. Center (3,5)(3, 5), point (7,8)(7, 8) ______
  2. Center (2,4)(-2, 4), point (10,1)(10, -1) ______
  3. Center (0,0)(0, 0), point (8,6)(-8, 6) ______
  4. Center (1,3)(1, -3), point (1,5)(1, 5) ______
  5. Center (4,1)(4, -1), point (2,7)(-2, 7) ______
  6. Center (5,2)(-5, 2), point (3,4)(3, -4) ______
  7. Center (0,3)(0, 3), point (5,15)(5, 15) ______
  8. Center (6,6)(6, 6), point (3,6)(-3, -6) ______

PAGE 22 — Diameter endpoints

15.3 Write the Equation

Endpoints of a diameter. Give the equation.

  1. A(0,0)A(0, 0), B(6,8)B(6, 8) ______

  2. A(4,1)A(-4, 1), B(4,7)B(4, 7) ______

  3. A(2,5)A(2, -5), B(2,9)B(2, 9) ______

  4. A(6,2)A(-6, -2), B(2,4)B(2, 4) ______

  5. A(1,3)A(1, 3), B(9,9)B(9, 9) ______

  6. A(3,7)A(-3, 7), B(5,3)B(5, -3) ______

  7. A(8,4)A(-8, -4), B(4,4)B(4, 4) ______

  8. A(2,2)A(2, 2), B(2,14)B(2, -14) ______

  9. A(1,1)A(-1, -1), B(7,5)B(7, 5) ______

  10. Application. A lighthouse beam centers on (4,3)(4, -3), kilometers, and reaches (4,9)(4, 9). Give the equation.

  11. Error analysis. Diameter endpoints A(2,6)A(2, 6), B(10,2)B(10, 2) — a student adds instead of averages to find the center. Give the correct center and equation.

  12. Reasoning. Both methods end at a center and a radius. Which does each skip, and which does it compute?

Exit ticket 15.3

  1. Center (5,5)(5, 5), point (9,8)(9, 8) on the circle. ______
  2. A(0,6)A(0, 6), B(8,0)B(8, 0) endpoints of a diameter. ______

PAGE 23 — Four starting points, two computations

15.4 The Whole Chapter, One Table

FIGURE: fig10-the-four-types.png (full width)


PAGE 24 — The most common mistake

15.4 Watch the Sign

FIGURE: fig11-the-sign-error.png (full width)


PAGE 25 — What each part controls

15.4 Same Center or Same Radius

FIGURE: fig12-two-circles-compared.png (full width)


PAGE 26 — In context

15.4 Three Real Circles

FIGURE: fig13-equations-in-context.png (full width)


PAGE 27 — Guided practice 15.4

Work Through It

  1. Give the "how" column for each of the four given-information types. ______
  2. Give the wrong equation, the correct one, and what changed. ______
  3. Give both equations in the left panel and what changed. ______
  4. Give both equations in the right panel and what changed. ______
  5. Name which of the four types each context panel is. ______
  6. Give one blank panel's center and radius by reading the grid. ______

PAGE 28 — Name it, then solve

15.4 Which Type Is This?

Name the type, then solve.

  1. (x5)2+(y+2)2=81(x-5)^2+(y+2)^2=81 ______
  2. (x+7)2+(y3)2=144(x+7)^2+(y-3)^2=144 ______
  3. x2+(y+9)2=100x^2+(y+9)^2=100 ______
  4. (x8)2+(y8)2=169(x-8)^2+(y-8)^2=169 ______
  5. Graphed: center (3,5)(3, -5), through (3,3)(3, 3) straight up. ______
  6. Graphed: center (6,0)(-6, 0), through (0,0)(0, 0). ______
  7. Diameter A(0,4)A(0, 4), B(8,2)B(8, -2). ______
  8. Diameter A(5,5)A(-5, -5), B(3,1)B(3, 1). ______
  9. Center (2,6)(2, -6), point (10,0)(10, 0). ______
  10. Center (4,4)(-4, 4), point (4,10)(-4, -10). ______

PAGE 29 — More mixed practice

15.4 Keep Going

  1. Diameter A(8,2)A(-8, -2), B(0,4)B(0, 4). ______

  2. Center (0,0)(0, 0), point (3,3)(3, -3) — radical radius. ______

  3. (x4)2+(y+1)2=50(x-4)^2+(y+1)^2=50 ______

  4. (x+2)2+(y+3)2=72(x+2)^2+(y+3)^2=72 ______

  5. Application. A weather balloon station at the origin, km, loses signal at (8,15)(8, 15). Give the equation.

  6. Application. A plaza's diameter is staked at (8,3)(-8, 3) and (0,3)(0, -3), meters. Give the equation.

  7. Application. A lighthouse beam centers on (3,6)(3, -6), km, and reaches (3,2)(3, 2). Give the equation.

  8. Error analysis. Given (x+1)2+(y5)2=40(x+1)^2+(y-5)^2=40, a student states r=40r=40. Give the correct radius.

  9. Reasoning. Why are a midpoint and a segment length genuinely different computations?

  10. Reasoning. For (xa)2+(yb)2=c(x-a)^2+(y-b)^2=c to be an actual circle, what must be true of cc?

Exit ticket 15.4

  1. Center (3,5)(-3, 5), point (3,3)(3, -3) on the circle. ______
  2. State the one question to ask before choosing among the four methods. ______

PAGE 30 — Blank circles

Your Turn

FIGURE: fig14-blank-circle-equation-frames.png (full width)

For every problem in this chapter:


PAGE 31 — Chapter review

Chapter 15 Review

Review 1 (G.PC.4a). A circle has center C(4,2)C(-4, 2) and passes through P(2,10)P(2, 10).

Review 2 (G.PC.4b). A circle's equation is (x6)2+(y+9)2=169(x-6)^2+(y+9)^2=169.

Review 3 (G.PC.4b). A(7,4)A(-7, -4) and B(1,2)B(1, 2) are diameter endpoints of one circle. A second circle has center (3,8)(-3, -8) and passes through (9,3)(9, -3).