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H40 • Lesson 62 of 105

Rational Expressions & Equations

Simplifying, operations, solving rational equations

High School Essentials • 9-12

Prerequisites: H32

Key Concepts

  • rational
  • simplification
  • solving

Rational Expressions & Equations

A rational expression is a fraction whose numerator and denominator are polynomials. Working with them is essentially working with fractions -- but with variables. The same rules you learned for numeric fractions (common denominators, canceling common factors) apply here, with one crucial addition: you must watch for values that make the denominator zero.

Simplifying Rational Expressions

The strategy: factor, then cancel common factors.

Worked Example 1 -- Simplifying

Simplify: (x2 - 9) / (x2 + 5x + 6).

  • Factor numerator: x2 - 9 = (x - 3)(x + 3).
  • Factor denominator: x2 + 5x + 6 = (x + 2)(x + 3).
  • Cancel the common factor (x + 3): result is (x - 3)/(x + 2), with x ≠ -3, x ≠ -2.

Multiplying and Dividing

Multiplying: factor everything, cancel common factors across all numerators and denominators, then multiply what remains.

Dividing: multiply by the reciprocal of the divisor, then proceed as above.

Worked Example 2 -- Multiplying

Multiply: (x2 - 4)/(x + 1) · (x + 1)/(x + 2).

  • Factor: x2 - 4 = (x - 2)(x + 2).
  • Rewrite: [(x - 2)(x + 2)]/(x + 1) · (x + 1)/(x + 2).
  • Cancel (x + 1) and (x + 2): result is (x - 2).

Adding and Subtracting

Just like numeric fractions, you need a common denominator.

Worked Example 3 -- Adding

Add: 3/(x - 1) + 2/(x + 4).

  • LCD = (x - 1)(x + 4).
  • Rewrite: 3(x + 4)/[(x - 1)(x + 4)] + 2(x - 1)/[(x - 1)(x + 4)].
  • Combine: [3(x + 4) + 2(x - 1)] / [(x - 1)(x + 4)] = (3x + 12 + 2x - 2) / [(x - 1)(x + 4)].
  • Simplify numerator: (5x + 10) / [(x - 1)(x + 4)] = 5(x + 2) / [(x - 1)(x + 4)].

Solving Rational Equations

To solve an equation involving rational expressions:

Extraneous Solutions -- Do Not Skip This Step

When you multiply both sides by an expression containing a variable, you may introduce solutions that are not valid. Always substitute your answers back into the original equation and verify that no denominator equals zero.

Worked Example 4 -- Solving a Rational Equation

Solve: x/(x - 2) = 4/(x - 2) + 1.

  • LCD = (x - 2). Multiply every term by (x - 2).
  • x = 4 + (x - 2).
  • x = 4 + x - 2 → x = x + 2 → 0 = 2.
  • This is a contradiction -- there is no solution.

Note: if we had gotten x = 2, we would reject it because x = 2 makes the denominator zero.

Factoring First Saves Time

Always factor every denominator before finding the LCD. This often reveals common factors that make the LCD smaller and the algebra simpler.

Practice Problems

  1. Simplify: (x2 - x - 6) / (x2 - 9).
    Show Solution

    Factor: (x - 3)(x + 2) / (x - 3)(x + 3). Cancel (x - 3): (x + 2)/(x + 3), x ≠ 3.

  2. Divide: (x2 - 1)/(x + 3) ÷ (x - 1)/(x + 3).
    Show Solution

    Multiply by reciprocal: [(x - 1)(x + 1)/(x + 3)] · [(x + 3)/(x - 1)]. Cancel (x + 3) and (x - 1): result is x + 1.

  3. Add: 5/(x + 2) + 3/(x - 1).
    Show Solution

    LCD = (x + 2)(x - 1). Result: [5(x - 1) + 3(x + 2)] / [(x + 2)(x - 1)] = (8x + 1)/[(x + 2)(x - 1)].

  4. Solve: 2/x + 3/(x + 1) = 1.
    Show Solution

    LCD = x(x + 1). Multiply: 2(x + 1) + 3x = x(x + 1). 2x + 2 + 3x = x2 + x. So x2 - 4x - 2 = 0. x = (4 ± √24)/2 = 2 ± √6. Both values are valid (neither makes a denominator zero). x ≈ 4.449 or x ≈ -0.449.

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