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H39 • Lesson 61 of 105

Logarithms

Logarithms as inverse of exponentials, properties, evaluation

High School Essentials • 9-12

Prerequisites: H38

Key Concepts

  • logarithms
  • inverse
  • properties

Logarithms

Exponents answer "what do I get when I raise b to a power?" Logarithms ask the reverse: "what power do I need?" This inverse relationship makes logarithms the essential tool for solving exponential equations.

Definition

logb(x) = y    means    by = x

In words: "the logarithm base b of x is the exponent you put on b to get x."

Reading Logarithms

log2(8) = 3  because  23 = 8.

log5(25) = 2  because  52 = 25.

log10(1000) = 3  because  103 = 1000.

Common Bases

NotationBaseNameTypical Use
log(x)10Common logarithmpH scale, decibels, Richter scale
ln(x)e ≈ 2.718Natural logarithmContinuous growth, calculus
log2(x)2Binary logarithmComputer science

Properties of Logarithms

These properties follow directly from the exponent rules:

PropertyRuleExample
Product Rulelogb(MN) = logb(M) + logb(N)log(6) = log(2) + log(3)
Quotient Rulelogb(M/N) = logb(M) - logb(N)log(5) = log(10) - log(2)
Power Rulelogb(Mp) = p · logb(M)log(8) = 3 log(2)
Identitylogb(b) = 1ln(e) = 1
Zerologb(1) = 0log(1) = 0
Inverseblogb(x) = x10log(5) = 5

Change of Base Formula

To evaluate a logarithm in any base using your calculator:

logb(x) = log(x) / log(b) = ln(x) / ln(b)

Example: log3(20) = log(20) / log(3) ≈ 1.3010 / 0.4771 ≈ 2.727.

Solving Exponential Equations

The key strategy: take the logarithm of both sides to bring the exponent down.

Worked Example 1

Solve: 3x = 81.

  • Recognize that 81 = 34, so x = 4.

Alternatively: take log of both sides. x · log(3) = log(81), so x = log(81)/log(3) = 4.

Worked Example 2

Solve: 52x = 200.

  • Take the natural log of both sides: ln(52x) = ln(200).
  • Power rule: 2x · ln(5) = ln(200).
  • Solve: x = ln(200) / (2 ln(5)) ≈ 5.2983 / (2 × 1.6094) ≈ 5.2983 / 3.2189 ≈ 1.645.

Worked Example 3

How long to double an investment at 6% annual interest compounded yearly?

  • Set up: 2P = P · 1.06t, so 2 = 1.06t.
  • Take log: log(2) = t · log(1.06).
  • Solve: t = log(2) / log(1.06) ≈ 0.3010 / 0.02531 ≈ 11.9 years.

Common Mistake

log(a + b) is NOT equal to log(a) + log(b). The product rule says log(a · b) = log(a) + log(b). There is no simple rule for the log of a sum.

Practice Problems

  1. Evaluate without a calculator: log4(64).
    Show Solution

    43 = 64, so log4(64) = 3.

  2. Use properties to expand: log2(8x3).
    Show Solution

    log2(8x3) = log2(8) + log2(x3) = 3 + 3 log2(x).

  3. Solve: 2x = 50.
    Show Solution

    x = log(50)/log(2) ≈ 1.6990 / 0.3010 ≈ 5.644.

  4. Condense to a single logarithm: 2 log(x) - log(y) + log(z).
    Show Solution

    = log(x2) - log(y) + log(z) = log(x2z / y).

  5. A bacteria culture triples every 4 hours. How long until it reaches 10 times its initial size?
    Show Solution

    Model: N = N0 · 3t/4. Set 10 = 3t/4. Take log: log(10) = (t/4) log(3). So t = 4 log(10)/log(3) = 4 × 1 / 0.4771 ≈ 8.38 hours.

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