Logarithms as inverse of exponentials, properties, evaluation
High School Essentials • 9-12
Exponents answer "what do I get when I raise b to a power?" Logarithms ask the reverse: "what power do I need?" This inverse relationship makes logarithms the essential tool for solving exponential equations.
In words: "the logarithm base b of x is the exponent you put on b to get x."
log2(8) = 3 because 23 = 8.
log5(25) = 2 because 52 = 25.
log10(1000) = 3 because 103 = 1000.
| Notation | Base | Name | Typical Use |
|---|---|---|---|
| log(x) | 10 | Common logarithm | pH scale, decibels, Richter scale |
| ln(x) | e ≈ 2.718 | Natural logarithm | Continuous growth, calculus |
| log2(x) | 2 | Binary logarithm | Computer science |
These properties follow directly from the exponent rules:
| Property | Rule | Example |
|---|---|---|
| Product Rule | logb(MN) = logb(M) + logb(N) | log(6) = log(2) + log(3) |
| Quotient Rule | logb(M/N) = logb(M) - logb(N) | log(5) = log(10) - log(2) |
| Power Rule | logb(Mp) = p · logb(M) | log(8) = 3 log(2) |
| Identity | logb(b) = 1 | ln(e) = 1 |
| Zero | logb(1) = 0 | log(1) = 0 |
| Inverse | blogb(x) = x | 10log(5) = 5 |
To evaluate a logarithm in any base using your calculator:
Example: log3(20) = log(20) / log(3) ≈ 1.3010 / 0.4771 ≈ 2.727.
The key strategy: take the logarithm of both sides to bring the exponent down.
Solve: 3x = 81.
Alternatively: take log of both sides. x · log(3) = log(81), so x = log(81)/log(3) = 4.
Solve: 52x = 200.
How long to double an investment at 6% annual interest compounded yearly?
log(a + b) is NOT equal to log(a) + log(b). The product rule says log(a · b) = log(a) + log(b). There is no simple rule for the log of a sum.
43 = 64, so log4(64) = 3.
log2(8x3) = log2(8) + log2(x3) = 3 + 3 log2(x).
x = log(50)/log(2) ≈ 1.6990 / 0.3010 ≈ 5.644.
= log(x2) - log(y) + log(z) = log(x2z / y).
Model: N = N0 · 3t/4. Set 10 = 3t/4. Take log: log(10) = (t/4) log(3). So t = 4 log(10)/log(3) = 4 × 1 / 0.4771 ≈ 8.38 hours.