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H34 • Lesson 56 of 105

Quadratic Equations - Conceptual

Quadratic concept, parabolas, roots, vertex

High School Essentials • 9-12

Prerequisites: H33

Key Concepts

  • quadratics
  • parabola
  • roots
  • vertex

Quadratic Equations -- Conceptual

Quadratic equations -- equations of the form ax2 + bx + c = 0 where a is not 0 -- produce one of the most recognizable curves in mathematics: the parabola. From the arc of a basketball to the shape of satellite dishes, parabolas appear throughout the natural and engineered world. This lesson builds your conceptual understanding of quadratics before diving into solving techniques.

The Parabola

The graph of y = ax2 + bx + c is always a parabola -- a smooth, symmetric, U-shaped curve. The coefficient a determines two fundamental properties:

If a > 0:

  • Parabola opens upward
  • Has a minimum value at the vertex
  • Shaped like a cup

If a < 0:

  • Parabola opens downward
  • Has a maximum value at the vertex
  • Shaped like a cap

The magnitude |a| controls the width: larger |a| makes the parabola narrower (steeper), while smaller |a| makes it wider (flatter). Compare y = 5x2 (very narrow) to y = 0.2x2 (very wide).

Key Features of a Parabola

FeatureDescriptionHow to Find
VertexThe highest or lowest pointx = -b/(2a), then find y
Axis of SymmetryVertical line through the vertexx = -b/(2a)
Roots / ZerosWhere the parabola crosses the x-axisSet y = 0 and solve
y-interceptWhere the parabola crosses the y-axisSet x = 0; it equals c

Worked Example 1 -- Finding the Vertex and Axis of Symmetry

Find the vertex and axis of symmetry of y = 2x2 - 8x + 3.

  1. Identify a = 2, b = -8, c = 3.
  2. Axis of symmetry: x = -b/(2a) = -(-8)/(2 * 2) = 8/4 = 2.
  3. Find the y-coordinate of the vertex: y = 2(2)2 - 8(2) + 3 = 8 - 16 + 3 = -5.
  4. Vertex: (2, -5). Axis of symmetry: x = 2.

Since a = 2 > 0, the parabola opens upward and (2, -5) is the minimum point.

Roots, Zeros, and the Discriminant

The roots (also called zeros, solutions, or x-intercepts) are where the parabola meets the x-axis. The discriminant, defined as D = b2 - 4ac, tells you how many real roots exist without actually solving:

Discriminant ValueNumber of Real RootsGraph Behavior
D > 0Two distinct real rootsParabola crosses x-axis twice
D = 0One repeated real rootParabola touches x-axis at vertex
D < 0No real rootsParabola does not reach x-axis

Worked Example 2 -- Using the Discriminant

How many real solutions does 3x2 - 4x + 5 = 0 have?

  1. Identify a = 3, b = -4, c = 5.
  2. Calculate the discriminant: D = (-4)2 - 4(3)(5) = 16 - 60 = -44.
  3. Since D = -44 < 0, the equation has no real solutions.

The parabola y = 3x2 - 4x + 5 lies entirely above the x-axis.

Worked Example 3 -- Interpreting a Parabola in Context

A ball is thrown upward. Its height in feet after t seconds is h(t) = -16t2 + 48t + 5. Describe the key features.

  1. Since a = -16 < 0, the parabola opens downward -- the ball goes up then comes down.
  2. Vertex time: t = -48/(2 * -16) = -48/(-32) = 1.5 seconds.
  3. Maximum height: h(1.5) = -16(2.25) + 48(1.5) + 5 = -36 + 72 + 5 = 41 feet.
  4. The y-intercept h(0) = 5 means the ball was thrown from a height of 5 feet.

Common Mistake: Sign Error in the Vertex Formula

The formula is x = -b/(2a). Do not forget the negative sign in front of b. For y = x2 + 6x + 8, the axis of symmetry is x = -6/(2*1) = -3, not x = 3.

Practice Problems

1. For y = -x2 + 4x - 1, does the parabola open up or down? Find the vertex.

Show Solution

a = -1 < 0, so it opens downward. Vertex x-coordinate: x = -4/(2*(-1)) = -4/(-2) = 2. Then y = -(2)2 + 4(2) - 1 = -4 + 8 - 1 = 3. Vertex: (2, 3), which is the maximum point.

2. Find the discriminant of x2 + 6x + 9 = 0 and determine the number of real solutions.

Show Solution

D = 62 - 4(1)(9) = 36 - 36 = 0. There is exactly one repeated real solution. (The parabola touches the x-axis at its vertex, x = -3.)

3. What is the y-intercept of y = 5x2 - 3x + 7?

Show Solution

Set x = 0: y = 5(0) - 3(0) + 7 = 7. The y-intercept is (0, 7).

4. A parabola has vertex (3, -2) and opens upward. Can it have zero x-intercepts? Explain.

Show Solution

No. Since the vertex is at y = -2 (below the x-axis) and the parabola opens upward, it must eventually cross the x-axis on both sides. It will have two x-intercepts.

5. Compare the widths of y = 4x2, y = x2, and y = 0.25x2.

Show Solution

All open upward. y = 4x2 is the narrowest (steepest). y = x2 is the standard width. y = 0.25x2 is the widest (flattest). Larger |a| means narrower; smaller |a| means wider.

Summary

Quadratic functions produce parabolas. The sign of a determines direction (up or down), and |a| controls width. The vertex (-b/(2a), f(-b/(2a))) is the extreme point, and the axis of symmetry is the vertical line through it. The discriminant b2 - 4ac reveals how many times the parabola crosses the x-axis: twice, once, or never. Understanding these features lets you analyze any quadratic before solving it.

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