Understanding inequality symbols, solving one-step inequalities, number line representation
Reserve & Extensions • K-12
Not every mathematical relationship is about equality. When we say "you must be at least 48 inches tall to ride," we are describing an inequality -- a statement that one value is greater than, less than, or not equal to another.
| Symbol | Meaning | Example |
|---|---|---|
| < | less than | 3 < 7 |
| > | greater than | 10 > 4 |
| ≤ | less than or equal to | x ≤ 5 (x can be 5) |
| ≥ | greater than or equal to | x ≥ -2 (x can be -2) |
The symbol always "points" to the smaller value. Think of the arrow opening toward the larger side: 3 < 7 means 3 is smaller, 7 is larger.
Solving inequalities works almost exactly like solving equations. You can add, subtract, multiply, or divide both sides -- with one critical exception we will cover shortly.
Solve x + 4 > 11
On a number line, use an open circle at 7 and shade to the right.
Solve 3x - 5 ≤ 10
On a number line, use a closed (filled) circle at 5 and shade to the left.
When you multiply or divide both sides by a negative number, you must reverse the inequality symbol.
Why? Consider this: 2 < 5 is true. Multiply both sides by -1: -2 and -5. But -2 > -5. The order flipped!
Solve -4x > 20
Forgetting to flip the inequality when multiplying or dividing by a negative is the most common error. Always ask yourself: "Am I multiplying or dividing by a negative?" If yes, reverse the sign.
Open circle (○): the endpoint is NOT included
Used with < and >
Closed circle (●): the endpoint IS included
Used with ≤ and ≥
1. Solve: x - 3 ≥ 8
Add 3 to both sides: x ≥ 11. Closed circle at 11, shade right.
2. Solve: 2x + 1 < 9
Subtract 1: 2x < 8. Divide by 2: x < 4. Open circle at 4, shade left.
3. Solve: -5x ≤ 30
Divide by -5 and flip the sign: x ≥ -6. Closed circle at -6, shade right.
4. Solve: 7 - 2x > 3
Subtract 7: -2x > -4. Divide by -2, flip: x < 2. Open circle at 2, shade left.
5. A parking garage charges $3 plus $2 per hour. You have $15. Write and solve an inequality for the number of hours you can park.
3 + 2h ≤ 15. Subtract 3: 2h ≤ 12. Divide by 2: h ≤ 6. You can park for at most 6 hours.