Probability rules, independent/dependent events, counting
High School Essentials • 9-12
Probability is the mathematics of uncertainty. It gives us a precise language for reasoning about chance events -- from card games to weather forecasting to medical testing. Every probability is a number between 0 (impossible) and 1 (certain).
| Term | Definition | Example |
|---|---|---|
| Experiment | A process with uncertain outcomes | Rolling a die |
| Sample space (S) | The set of all possible outcomes | S = {1, 2, 3, 4, 5, 6} |
| Event (A) | A subset of the sample space | A = "rolling even" = {2, 4, 6} |
| P(A) | Probability of event A | P(A) = 3/6 = 1/2 |
(This formula applies when all outcomes are equally likely.)
The probability something does NOT happen equals 1 minus the probability it does happen.
We subtract P(A and B) to avoid double-counting outcomes in both events.
If A and B are mutually exclusive (cannot happen simultaneously), then P(A and B) = 0:
If A and B are independent (one does not affect the other), then P(B|A) = P(B):
Independent: flipping a coin twice -- the second flip is not affected by the first.
Dependent: drawing two cards without replacement -- the second draw depends on the first.
If one task can be done in m ways and a second task in n ways, the two tasks together can be done in m × n ways.
A bag contains 4 red, 3 blue, and 5 green marbles. What is P(blue)?
In a standard deck of 52 cards, what is P(heart or face card)?
A fair coin is flipped 3 times. What is P(all heads)?
Adding probabilities for "or" without subtracting the overlap. If events can happen simultaneously, you must use P(A or B) = P(A) + P(B) - P(A and B). Skipping the subtraction leads to a probability that may exceed 1 -- which is always wrong.
Favorable outcomes: {5, 6}. P = 2/6 = 1/3.
By the counting principle: 6 × 6 = 36 outcomes.
P(no rain) = 1 - 0.3 = 0.7.
P(1st red) = 5/12. P(2nd red | 1st red) = 4/11. P(both red) = (5/12)(4/11) = 20/132 = 5/33 ≈ 0.152.
10 × 10 × 10 = 1,000 passwords. P(correct) = 1/1000 = 0.001.