Geometric sequences, common ratio, formulas
High School Essentials • 9-12
While arithmetic sequences grow by adding, geometric sequences grow by multiplying. Each term is obtained by multiplying the previous term by a fixed value called the common ratio. This multiplicative pattern appears in compound interest, population dynamics, fractal geometry, and signal processing.
A sequence is geometric if the ratio between consecutive terms is always the same:
3, 6, 12, 24, ... (r = 2)
100, 50, 25, 12.5, ... (r = 0.5)
2, 5, 8, 11, ... (constant difference, not ratio)
1, 4, 9, 16, ... (perfect squares)
| Formula | Expression | Use |
|---|---|---|
| Explicit (nth term) | an = a1 · r(n-1) | Jump to any term |
| Recursive | an = an-1 · r, with a1 given | Each term from the previous |
| Partial sum (r ≠ 1) | Sn = a1(1 - rn) / (1 - r) | Sum of the first n terms |
| Infinite sum (|r| < 1) | S = a1 / (1 - r) | Sum of all terms when series converges |
Find the 8th term of the sequence 5, 15, 45, 135, ...
Find the sum of the first 6 terms of: 4, 12, 36, 108, ...
Find the sum: 18 + 6 + 2 + 2/3 + ...
The repeating decimal 0.333... = 3/10 + 3/100 + 3/1000 + ... is an infinite geometric series with a1 = 0.3 and r = 0.1. Sum = 0.3/(1 - 0.1) = 0.3/0.9 = 1/3. This technique proves that every repeating decimal is a fraction.
The infinite sum formula S = a1/(1 - r) only works when |r| < 1. If |r| ≥ 1, the terms do not shrink toward zero and the sum diverges -- it grows without bound.
a1 = 2, r = -3. a6 = 2 · (-3)5 = 2 · (-243) = -486.
a1 = 1000, r = 0.5. an = 1000 · (0.5)n-1.
S5 = 1(1 - (1/2)5) / (1 - 1/2) = (1 - 1/32)/(1/2) = (31/32)/(1/2) = 31/16 = 1.9375.
a1 = 24, r = 1/2. S = 24/(1 - 1/2) = 24/(1/2) = 48.
Down distances: 80, 48, 28.8, ... (a1 = 80, r = 0.6). Up distances: 48, 28.8, ... (a1 = 48, r = 0.6). Total = 80/(1 - 0.6) + 48/(1 - 0.6) = 200 + 120 = 320 feet. Alternatively: first drop of 80, then twice each bounce: total = 80 + 2(48)/(1 - 0.6) = 80 + 240 = 320 feet.